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I need to find an equation that hass an infinite number of solutions

Answers

Answer 1

Answer:

Answer

2(7x + 3) - x

= 13x + 6

Explanation

2(7x + 3) - x

= 14x + 6 - x

= 14x - x + 6

= 13x + 6

Hope this Helps!!!

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A die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on that face. (For example, a six is three times as probable as a two.) What is the probability of getting an even number in one throw?

Answers

Answer:

simple, divide the number by two, round as needed. 6=3x as normal, 5=2.5x as nromal, etc.

Step-by-step explanation:

What is the slope of the line that goes through the points (6, 4) and (8, −2)? A. −6 B. −3 C. − 1 3 D. 3

Answers

Answer:

B -3.

Step-by-step explanation:

The slope = (y2-y1)/(x2-x1)

= (-2-4)/(8-6)

= -6/2

= -3.

90 units needed 8units per case

Answers

Answer: 90/8=11.25

Step-by-step explanation:

What is the least common denominator of 5/12 and 4/18

Answers

The least common denominator of 12 and 18 is 36.

Given that fractions $(5)/(12)$ and $(4)/(18)$ .

Fraction: It is of the form p/q where q is not equal to zero.

∴p/q , q ≠ 0

Fractions: $(5)/(12)$ and $(4)/(18)$

LCM of the denominator: 12 and 18

LCM of 12 and 18 = 36

Fraction 5/12:

Multiply numerator and denominator by 3.

$(5 * 3)/(12 * 3) = (15)/(36)$

Fraction 4/18:

Multiply numerator and denominator by 2.

$(4 * 2)/(18 * 2) = (8)/(36)$

Thus the common denominator of the fraction is 36.

Know more about fractions,

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Answer:

Step-by-step explanation:

Weights of babies at the local community hospital have a distribution that is approximately normal with a mean weight of 7.43 pounds and a standard deviation of 1.25 pounds. A premature baby can be classified as being less than 5.51 pounds. A. Find the probability of a randomly selected baby weighing less than 5.51 pounds. B. If 25 babies are randomly selected, what is the probability that their weight will be less than 5.51 pounds?

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Answer:

Step-by-step explanation:

Hope this helped

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who were vegans and another sample of such women who were omnivores.Diet Sample Size Sample Mean Sample SD
Vegan 85.00 5.20 1.08
Omnivore 91.00 5.65 1.10

Calculate a 99% CI for the difference between the population mean total cholesterol level for vegans and population mean total cholesterol level for omnivores. (Use μvegan−μomnivore). Round to three decimal places.)
Interpret the interval.

a. We are 99% confident that the true average cholesterol level for vegans is less than that of omnivores by an amount within the confidence interval.
b. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount within the confidence interval.
c. We are 99% confident that the true average cholesterol level for vegans is greater than that of omnivores by an amount outside the confidence interval.
d. We cannot draw a conclusion from the given information.

Answers

Answer: hey

Step-by-step explanation:

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