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The ellipse ^2/9 + ^2/4 =1, has its major axis length equal toa.13b. 9 c. 4 d. 3 e. 6

Answers

Answer 1

Answer:

The given equation of ellipse is,

$\begin{gathered} (x^2)/(9)+(y^2)/(4)=1 \n (x^2)/(3^2)+(y^2)/(2^2)=1 \end{gathered}$

Thus, the major axis length can be determined as,

$2a=2*3=6$

Thus, option (e) is correct.

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Explain why you cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds?

Answers

Answer:

We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds

Step-by-step explanation:

We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds because we do not know the number of possible outcomes, the events , sample space or the sample size. Probability is calculated with frequency or occurrences or how much certainty there is.It is a number between 0 and 1. 1 indicates certainty and 0 indicates impossibility. Without a range or frequency how can we depict the possibility or impossibility of an occurrence of 200 pounds.

Final answer:

You cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds without sufficient data on the weight distribution of the population. Weight can widely vary due to individual factors, making it hard to have a definitive measurement. Accurate data and appropriate statistical methods are necessary.

Explanation:

The process of calculating the probability that a randomly selected passenger weighs more than 200 pounds would be seemingly simple deductive reasoning. However, it's impossible without access to sufficient data that provides information about the population's weight distribution. Since people's weights are variable and oftentimes private information, it would not be straightforward to obtain accurate and representative data.

For instance, while we can calculate the probability of drawing a certain card from a deck because we know the total number of cards and the number of each type of card, determining the likelihood of a randomly chosen passenger weighs over 200 pounds requires knowledge of the weight distribution of all potential passengers.

Moreover, weight can vary significantly among individuals due to factors like age, gender, health status, and so on. This makes it a continuous variable, meaning it's also affected by dimensions like decimal form and scientific notation when measuring. We'd need accurate data and appropriate statistical methodologies to consider all possible weight ranges and their frequencies for a reliable calculation of such probability.

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Maria found the least common multiple of 6 and 15. Her work is shown below.Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . .

Multiples of 15: 15, 30, 45, 60, . . .

The least common multiple is 60.

What is Maria’s error?

the answer is IDK

Answers

Answer:

The Least Common Multiple is 3

Step-by-step explanation:

Maria's error was that she tried finding the largest multiple rather than the least.

Answer:

Step-by-step explanation:

Maria's error on this is the LCM is 30 not 60

the least is 30 not 60

Use the distributive property to simplify this expression -2x(3x + x-5)

Answers

-6x-2x+10x
8x+10x
18x.

Answer:

−8x^2 + 10x

Step-by-step explanation:

$(a^(2)-1)/(2-5a) times (15a-6)/(a^(2)+5a-6)$ click on answer to see full problem

Answers

$\bf \cfrac{a^2-1}{2-5a}* \cfrac{15-6}{a^2+5a-6}\n\n-----------------------------\n\nrecall\quad \textit{difference of squares}\n \quad \n(a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\n\nthus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)\n\n\nnow\quad a^2+5a-6\implies (a+6)(a-1)\n\n-----------------------------\n\nthus\n\n\n\cfrac{a^2-1}{2-5a}* \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}* \cfrac{3(5a-2)}{(a+6)(a-1)}\n\n-----------------------------\n\n$

$\bf now\quad 3(5a-2) \iff -3(2-5a)\n\n-----------------------------\n\nthus\n\n\n\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}* \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}$

What is the effect on the graph of the function f(x)=x when f(x) is replaced with -1/2f(x)?

Answers

Answer:

For negative sign , the graph reflects over x -axis and for 1/2 there will be a vertical compression

Step-by-step explanation:

Parent function is f(x)= x

We need to find the effect of the graph when f(x) is replaced with -1/2f(x)

When negative sign is multiplied outside f(x) like -f(x), then there will be a reflection over x-axis

When negative sign is multiplied inside f(x) like f(-x) then there will be a reflection over y-axis

When a number is multiplied outside f(x) then there will be a vertical stretch or compression

Here 1/2 is multiplied outside f(x). $(1)/(2)$ is less than 1 so there will be a vertical compression

For negative sign , the graph reflects over x -axis and for 1/2 there will be a vertical compression

Which algebraic expression has a term with a coefficient of 9? O A. 6(x + 5) O B. 6x - 9 O C. 6+ x - 9 O D. 9x=6

Answers

Answer:

D is the answer to your question

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