The numbers on a certain combination lock start with 0 and go through 10. If a combination consists of 3 numbers, how many different lock combinations are possible?

Answers

Answer 1

Answer: There would be 165 combinations

Answer 2

Answer:

the answer isnt that^ its not an option.

Related Questions

An example of a quadrilateral that is not a parallelogram is a _________.a. rhombus b. square c. rectangle d. none of the above
Find a4 in the sequence given by {a1=-3 and an=an-1+7
A survey showed that the probability that an employee gets placed in a job that is suitable for the employee is 0.65. A psychometric test consultant claimed that he could help place any employee in a suitable job based on the result of a psychometric test. An employee working in a particular company decides to take this test. The test has an accuracy rate of 70%. This data is represented in the tree diagram.The probability that the employee is in the wrong job and the test predicts that he is in the wrong job is . A. 0.105 B. 0.195 C. 0.245 D. 0.455
Solve the equation. x/2 + 2x/3 =5
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the distance between two cities a and b is 330 km. a train starts from a at 8 a.m. and travels towards b at 60 km/hr. another train starts from b at 9 a.m. and travels towards a at 75 km/hr. at what time do they meet? options: A. 11 : 30 am B. 10 : 30 am C. 11 am D. 10 am

Answers

Answer: 11 am

hope this helps!

Write an inequality for the given statement: Two-thirds of a number, decreased by 4, is less than 6.

Answers

Answer:

$(2)/(3) x$ < is the answer.

Step-by-step explanation:

Let number be x

two third of x = $(2)/(3) x$

two third of x decreased by 4 = $(2)/(3) x$ -4

which is less than 6 therefore mathematically it equals

$(2)/(3) x$ -4< 6

$(2)/(3)$ x-4<6

To get $(2)/(3)$ of a number you have to multiply the number by $(2)/(3)$ , which gives you $(2)/(3)$ x then you subtract that by 4. The inquality faces the 6 because it is greater than $(2)/(3)$ x-4 based on the statement above. The inquality always faces the greatest number.

What is the product of 2x + y and 5x – y + 3?

Answers

Answer: The required product is $10x^2-y^2+3xy+6x+3y.$

Step-by-step explanation: We are to find the product f the following two algebraic expressions:

$E_1=2x+y,\n\nE_2=5x-y+3.$

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

$M\n\n=E_1 * E_2\n\n=(2x+y)*(5x-y+3)\n\n=10x^2-2xy+6x+5xy-y^2+3y\n\n=10x^2-y^2+3xy+6x+3y.$

Thus, the required product is $10x^2-y^2+3xy+6x+3y.$

Answer: $10x^2-y^2+3xy+6x+3y$

Step-by-step explanation:

Given expressions are 2x+ y and 5x -y +3

Product of 2x+y and 5x-y+3 is

$(2x+y)* (5x-y+3) = 2x* (5x-y+3) + y* (5x-y+3)$ ( by applying distributive property under multiplication over addition)

⇒ $(2x+y)* (5x-y+3) = 10x^2-2xy+6x+5xy-y^2+3y$ (again by distributive property)

⇒ $(2x+y)* (5x-y+3) = 10x^2-y^2+3xy+6x+3y$ ( by operating the like terms.)

At a summer camp,the ratio of campers to adults is kept equivalent to 7:1 use equivalent ratios to complete the table

Answers

The tabular representation of the ratio of campers to adults in the summer camp is given as follows -

CAMPERS : 7 14 21 28 . . . . 7n

ADULTS : 1 2 3 4 . . . . n

We have a summer camp in which the ratio of campers to adults is kept equivalent to 7:1 .

We have to complete the table using the equivalent ratios.

How can you find out the equivalent ratios of the ratio a : b ?

To find the equivalent ratios of a : b, follow the simple rule -

$a:b=(a)/(b)=(a*2)/(b*2) =(a*3)/(b*3) =(a*4)/(b*4) = ... =(a* n)/(b* n)$

In the question given -

$a:b=(7)/(1)=(7*2)/(1*2) =(7*3)/(1*3) =(7*4)/(1*4) = ... =(7* n)/(n* n)$

Hence, we can write the equivalent ratios in the form of tables -

CAMPERS : 7 14 21 28 . . . . 7n

ADULTS : 1 2 3 4 . . . . n

To solve more question on ratios, visit the link below -

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Answer:

Campers: 7, 14, 28, 42

Adults: 1,2,5,30

Step-by-step explanation:

Evaluate log (base 9) 27. Can someone explain this one for me so i could do some tasks on my own?

Answers

$log_927=log_93^3=3log_93=3log_9\sqrt9=3log_99^(1)/(2)\n\n=(1)/(2)\cdot3log_99=(3)/(2)$

You would use some properties of the logarithm. First, $log_927=log_(3^2)27=(1)/(2)log_327$ . So, now you have $log_327$ to calculate. It's $log_33^3=3$ , so the final result is $(1)/(2)*3=(3)/(2)$
Hope it helps.

All right triangles are similar. true or false.

Answers

The statement is False.

Right triangles don't all look the same.

When two triangles are similar, their corresponding angles and sides must be equal and proportional.

Although right triangles have the same attribute of having a single 90-degree angle, they might differ in their side lengths and angles, therefore they are not always comparable.

The relationship between a triangle's angles and side lengths determines how similar they are.

Only when the side lengths of two right triangles are proportionate and all of their angles, including the right angle, are congruent can two right triangles be said to be similar.

Hence the statement is false.

Learn more about similar triangles click;

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not all triangles are similar, like all triangles, all angles must addd up to 180 degrees. Hope this helps.

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Angle x is (2n + 12)°, and angle y is (3n + 18)° . Find the measure of angle x. Note: not drawn to scale. A) 24° B) 30° C) 72° D) 108