Who is SohCahToa Joe? on Csi geometry:trigonometry I need the answers.

Answers

Answer 1

Answer: SohCahToa is an acronym for the basic trigonometric functions which are sine, cosine, and tangent. Sine's value comes from the quotient of the opposite side and the hypotenuse. Cosine's value comes from the quotient of the adjacent side and the hypotenuse. Lastly, Tangent is the quotient of the opposite side and the adjacent side.

Related Questions

The numbers 4, 5, 6, and 7 are on a spinner. You spin the spinner twice. Which calculation proves that landing on an even number for the first spin and the second spin are independent events?
In the inverse variation function, what happens to the output when the function's input value is divided by 5?
Aubree is making pizzas for a pizza party. Each pizza requires 2/3 pound of cheese. How many pounds of cheese does she need to make 16 pizzas? Express your answer in simplest form.
I need help pleaseee
Using a directrix of y = 5 and a focus of (4, 1), what quadratic function is created?

The coordinates of triangle GBW are G (20, 10) B (-35, 20), and W (5,-10). Is GBW a right triangle? Justify your answer.

Answers

We know from Pythagoras' Theorem, a right angle triangle can be identified by the relationship:

$a^2+b^2=c^2$

Thus, we know if the side lengths of the triangle in question abide by this relation, the triangle is right.

First, we must find the greatest side length.

We know, using the distance formula.

$GB= √((-35-20)^2 +(20-10)^2) =√(3125)$
$BW= √((5+35)^2 +(-10-20)^2) =√(2500)$
$WG= √((20-5)^2 +(10+10)^2) =√(625)$

From this, we know that:
$GB\ \textgreater \ BW\ \textgreater \ WG$
Therefore, GB would be the hypotenuse of the triangle.
Now we substitute the values for the two shorter lengths and the greater length into the pythagorean theorem:
$a^2+b^2=2500+625=3125$
$c^2=3125$
$\therefore LHS=RHS$
Therefore, this triangle is a right angled triangle

Y = 10 + 16x − x^2y = 3x + 50
If (x1, y1) and (x2, y2) are distinct solutions to the system of equations shown above, what is the sum of the y1 and y2?

Answers

Solving the system we can see that the sum of the y-values of the two solutions is 139.

How to get the sum of y₁ and y₂?

Let's solve the system of equations.

y = 10 + 16x − x²

y = 3x + 50

We can write this as a single quadratic equation:

10 + 16x - x² = 3x + 50

10 + 16x - x² - 3x - 50 = 0

-x² + 13x - 40 = 0

Using the quadratic formula we will get the two solutions for x:

$x = (-13 \pm √(13^2 - 4*-1*-40) )/(-2) \n\nx = (-13 \pm 3 )/(-2)$

So the two solutions are:

x = (-13 + 3)/-2 = 5

x = (-13 - 3)/-2 = 8

Evaluating the linear equation in these two values we will get y1 and y2.

if x = 5

y₁ = 3*5 + 50 = 65

if x= 8

y₂ = 3*8 + 50 = 74

The sum is:

65 + 74 =139

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Final answer:

The distinct solutions to the system of equations are (5, 65) and (8, 74), and the sum of the y-values is 139.

Explanation:

To find the sum of y-values of the distinct solutions to this system of equations, first, you need to set the two equations equal to each other to find the x-values of the solutions:

10 + 16x − x^2 = 3x + 50.

Then, solve the resulting equation for x:

x^2 - 13x + 40 = 0.

This is a quadratic equation, and it can be solved either by factoring or using the quadratic formula. The solutions for x result in:

x = 5 and x = 8.

These are the two distinct x-values for the intersections of the graphs of the two equations. To find the corresponding y-values, plug these x-values into either of the original equations. We'll use the simpler equation, y = 3x + 50:

For x = 5, y = 65 and for x = 8, y = 74.

Therefore, the distinct solutions to the system of equations are (5, 65) and (8, 74). Finally, the sum of y1 and y2 is 65 + 74 = 139.

Learn more about System of Equations here:

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Find the volume of this square pyramid.48 cm3
96 cm3
144 cm3
288 cm3

Answers

Formula:

V = 1/3 * b^2 * h

Plug in what we know:

V = 1/3 * 6^2 * 4

Simplify exponent:

V = 1/3 * 36 * 4

Multiply all 3 numbers together:

V = 48cm^3

V= $a^(2)$ ·(h/3)
a=base edge
h= height
V= $6^(2)$ ·(4/3)
V=36·(4/3)
V=48
48 cm³

Find the total area the regular pyramid.

Answers

Answer:

$4+4√(10) \n72+24√(3) \n144+36√(3) \n16√(3)\n 18√(91) +54√(3) \n$

Step-by-step explanation:

The above answers are for total area. They belong to the lesson called Solid's: Pyramids. They are in order so find each T.A question and input the answer accordingly.

To find total are of a regular pyramid, we add 4 times the area of one side and the area of base.

Please answer this question.1m of ribbon costs £3.20. find the cost of 1 and 1/4 m

Answers

$\begin{array}{ccc}1m&-&\£3.20\n\n1(1)/(4)m&-&x\end{array}\n-------------\nmultiply\ on\ the\ cross\n-------------\n1\cdot x=1(1)/(4)\cdot3.20\n\nx=1.25\cdot3.20\n\nx=4\n\nAnswer:\£4.00$

Convert the rate 1000 fluid ounces per 2 hours to cups per minute.

Answers

The conversion may be done through the dimensional analysis and the use of proper conversion factors. Each fluid once is 0.125 cup and each hour is equal to 60 minutes.
(1000 fluid ounces / 2 hours) x (0.125 cup / 1 fl oz.) x (1 hr / 60 min) = 2.08 cup/ minute

Thus the conversion is 2.08 cup / minute.

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