What is x+5 over x = 5 over 4

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Answer 1

Answer: $x\not=0\n\n(x+5)/(x)=(5)/(4)\n5x=4(x+5)\n5x=4x+20\n5x-4x=20\nx=20$

Related Questions

Simplify 7/100 please !!!!!!!!!!!!!!!!!1
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Solve for d.120 - 11d + 2d + 4d - 5 = 16
When f(x)= -3,what is x
Substitution and elimination are two symbolic techniques used to solve linear equations. For example, if it is easy to set up an equation for substitution where 1 variable is on 1 side, then use that; For example, 4y=16+4x, you can easily divide by 4, get y=4+x (or y=x+4), and plug that into the other equation. In other cases where it may not be so easyFractions/decimals, etc., then you would probably rather use elimination.1) The substitution method. This method is best utilized when one of the variables in one of the equations has a coefficient of 1 or -1, otherwise you will introduce fractions. Substitution can also be used for nonlinear systems of equations.(2) Linear combinations also called the elimination method, multiplication and addition method, etc... My personal favorite as it can be done efficiently. It generalizes well to larger systems and is the underpinning of various other solution methods.As the name implies it requires the equations to be linear.You need to know both and be comfortable switching between them.Can we get one for the elimination method too?Also, can you solve the same problem using either of the two techniques?

You have a box that measures 11
inches on each side. What is the
volume of that box

Answers

Answer:

1,331in^3

Step-by-step explanation:

an exponential function is expressed in the form y=a*b/\x. the relation represents a growth when ________ and a decay when ________.

Answers

That function grows when 'b' is more than 1 and 'x' is positive, or when b <1 and x<0. It decays when b> 1 and x <0, or when b<1 and x> 0.

Answer 1: b>1

Answer 2: 0b<b<1

An exponential function is expressed in the form y=axb^x. The relation represents a growth when "b>1" and a decay when "0<b<1".

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Answers

Answer:

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

Origin.

Step-by-step explanation:

A function f(x) is said to be a odd function if:

$f(-x)=-f(x)$

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

$f(-x)=f(x)$

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

$\tan(-x)=-\tan x\n\n\cos (-x)=-\cot x\n\n\csc (-x)=-\csc x$

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

Hence, the graph of tangent function, cotangent function and cosecant function is symmetric about the origin.

Final answer:

The tangent, cotangent, and cosecant functions are odd and exhibit symmetry with respect to the origin. This is because an odd function satisfies the condition y(x) = -y(-x), meaning for every point (x, y) on the graph, the point (-x, -y) is also on the graph.

Explanation:

The tangent, cotangent, and cosecant functions are indeed odd functions, meaning they exhibit symmetry with respect to the origin. An odd function satisfies the condition y(x) = -y(-x), and when graphed, this produces a symmetry with respect to the origin of the coordinate plane. Essentially, this means that if a point (x, y) is on the graph of an odd function, the point (-x, -y) is also on the graph.

For an example, let's consider the tangent function, which is an odd function: For any angle A, the tangent of -A is the opposite of the tangent of A, or tan(-A) = -tan(A). Graphically, this implies that if we reflect the graph of the tangent function over the x-axis, and then over the y-axis, we will get the original function back, thus verifying the symmetry in odd functions.

Learn more about Odd Functions here:

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What is 30 minutes as a percentage of an hour?

Answers

30 minutes is half of an hour so it would be 50%.

Which of the following could be the ratio of the length of the longer leg of a 30 60 90 triangle to the length of its hypotenuse

Answers

for 30 60 90 triangles, the ratio of the side lengths is
$(1)/(2) : ( √(3) )/(2) :1$
where the first is the shorter leg, the second is the longer leg, and the third is the hypotenuse (the longest side that doesn't form a 90 degree angle)

so the ratio of the longer leg to the hypotenuse is $( √(3) )/(2) :1$
or
$( ( √(3) )/(2) )/(1)$
which equals $( √(3) )/(2)$