The length of a rectangle is 7 mm longer than its width. Its perimeter is more than 62 mm. Let w equal the width of the rectangle. Write an expression for the length in terms of the width.
Use these expressions to write an inequality based on the given information.
Solve the inequality, clearly indicating the width of the rectangle

Answers

Answer 1

Answer: We know that the length (L) of the rectangle in question is 7mm longer than its width (W). Let's represent that as the following:
L=7+W

A rectangle's perimeter (the total sum of its sides) will be made my 2 sides representing the length (2L) and 2 sides representing the width (2W). We also know that this rectangle's perimeter is greater than 62. Since eventually we are solving for W, let's state all expressions in terms of W:
2L=2(7+W)
2(7+W)+2W>62
14+2W+2W>62
14+4W>62
4W>62-14
4W>48
W>48/4
W>12
If the rectangle's perimeter is greater than 62, then the width will be greater than 12. Let's confirm this:
Perimeter=2L+2W
P=2(7+12)+2(12)
P=14+24+24
P=62
So we can see that if the perimeter is to surpass 62, W needs to be greater than 12 and L ( which is also 7+W) needs to be greater than 19.

Answer 2

Answer:

Final answer:

The length of the rectangle is expressed as w + 7 mm. The inequality for the perimeter is 2(w + w + 7) > 62. The solution for the inequality reveals that the width, w, must be more than 12mm.

Explanation:

The question is asking for an expression for the length of a rectangle in terms of the width and an inequality based on the perimeter. We are given that the length of the rectangle is 7 mm longer than its width, and its perimeter is more than 62 mm.

The width of the rectangle is defined as w. We can express the length as w + 7 mm, since it is 7 mm longer than the width.

The perimeter of a rectangle is calculated as 2 times the sum of its width and length, so we form the inequality: 2(w + w + 7) > 62.

To solve it, we simplify the left side: 4w + 14 > 62. We then subtract 14 from both sides, getting 4w > 48. Finally, we divide both sides by 4, which gives us w > 12. Therefore, the width of the rectangle must be more than 12 mm.

Learn more about Inequalities here:

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Answers

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I would say 31.256s because it has 5 significant digits.

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Answers

Hello,

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Answers

Answer:

Step-by-step explanation:

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Answer:

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Answers

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Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. Write and solve an equation to find how far Joey walked to get to Armando's home.

Answers

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

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Let's get rid of the plus/minuses. Squaring,

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$\pm 2ab = c^2-a^2-b^2$

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For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=(9)/(100) \textrm{ or } c^2=(9)/(4)$

$c=(3)/(10) \textrm{ or } c=(3)/(2)$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

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