Microorganisms that occur or have adapted to live in a specific environment are called a. fomites. b. droplets. c. pathogen. d. flora.

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Answer 1
Answer: The microorganism that occurs or has adapted to live in a specific environment is called D. Flora. Normal Flora or Flora lives inside the body without harming the person.  They are mostly found in the large intestine. I hope you find this helpful.

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In the combined gas law, if the pressure in the system is increased, what happens to the volume?a. The volume decreases. b. The volume increases. c. The volume remains the same.
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Which model of earth's interior does this image show? if u answer i'll give u a thanks

Answers

It shows the inner core, core, mantle, and crust

Final answer:

The student's question lacks an image, so a specific model can't be identified. However, a common model of Earth's interior includes four parts: the crust, mantle, outer core, and inner core. Each of these parts have distinct characteristics and they are made up of different materials.

Explanation:

Unfortunately, I'm not able to identify the specific model of Earth's interior based on your question as it doesn't include an image for me to review. However, I can tell you that commonly used models include the crust, mantle, outer core, and inner core model, based on our current understanding of geology. The crust is the surface layer, followed by the mantle which is the largest part of Earth's interior. Below the mantle are the outer core and the inner core, which are primarily made up of iron and nickel and exhibit different physical properties.

Learn more about Earth's interior models here:

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. Which of the following is not an ultimate goal of science?A. Understand patterns
B. Give explanations for natural events
C. Make predictions
D. Produce unchanging, absolute answers

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What is not the ultimate goal of science is to produce unchanging and absolute answers - D. Scientists would like to, however, understand patterns, give explanations for natural events, and even make predictions. And it isn't really the case that they would like to produce unchanging answers.

If you notice that two waves combine and a part of the resulting wave has less light intensity than either of the individual waves, you're observing A. destructive interference. B. polarization. C. constructive interference. D. diffraction.

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If you notice that two waves combine and a part of the resulting wave has less light intensity than either of the individual waves, you're observing destructive interference. Destructive interference happens when the two waves that combine have amplitudes with opposite signs,which results in subtraction- combined wave with a lower amplitude.

The force between two charges is 1000 N. One has a charge of 2 × 10-5 C, and the other has a charge of 5 × 10-6 C. What is the distance between them?

Answers

Use the Coulomb Law:

F=k.(q_1.q_2)/(d^2)\n \n 1000=9.10^9.(2.10^(-5).5.10^(-6))/(d^2)\n \n 1000d^2=9.10^9.2.10^(-5).5.10^(-6)\n \n d^2=(9.10^9.2.10^(-5).5.10^(-6))/(10^3)\n \n d^2=(9)/(10^4)\n \n d=\sqrt{(9)/(10^4)}=(3)/(100)=0,03 \ m

Final answer:

The distance between the charges is calculated using Coulomb's Law and found to be 0.134m or 13.4 cm.

Explanation:

This problem can be solved using Coulomb's Law. The formula for Coulomb's Law is: F = k*(|q1*q2|)/r², where F is the force between the charges, q1 and q2 are the amounts of charge, r is the distance between the charges, and k is Coulomb's constant (approximately 9.00 x 10^9 N*(m²/C²)).

Giving the values, we have, 1000 N = 9.00 x 10^9 N*(m²/C²)*((2 x 10^-5 C) * (5 x 10^-6 C))/r².

Solving for r (the distance between the charges) in this equation, we first divide both sides of the equation by the values on the right, excluding r, which gives us: r² = ((2 x 10^-5 C) * (5 x 10^-6 C) * 9.00 x 10^9 N*(m²/C²))/1000N.

Calculating the values in this equation and then taking the square root of the result gives r = 0.134 m or 13.4 cm which is the distance between the two charges.

Learn more about Coulomb's Law here:

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Think about multiplying each speed by a factor to calculate kinetic energy at that speed.Is there a common factor that works for every speed? If so, what’s this factor?

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Answer:

To calculate kinetic energy, you use the formula KE = 0.5 * m * v^2, where "m" is the mass and "v" is the speed. There isn't a common factor that works for every speed; the factor you use is 0.5. This formula is derived from the principles of classical mechanics and doesn't change with speed; it's a fundamental equation for calculating kinetic energy.

A man is carrying a trolley of mass 6kg and having K.E. of 40 J . Calculate its velocity with which he is running .

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The formula to find kinetic energy is -

K.E. = (1)/(2)*m* v^(2)

Where,

m = mass

and

v = velocity

So, putting the values in the formula we get -

40 = (1)/(2) *6*v^(2)

(40)/(3) = v^(2)

\sqrt (40)/(3) = 3.6514 m/s
As we know that K.E = 1/2 mv² so
 by arranging it 
K.E ×2÷6 = v²
now by putting values
v²=13.33 m²/s²
so
v= 3.65 m/s....