Find f(a-2) when f(x)=x^2-1

I forgot how to do these so please show all steps

Answers

Answer 1

Answer: $f(a-2)=(a-2)^2-1=a^2-4a+4-1=a^2-4a+3$

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solve by substitution ( show steps)y=3x+23x-y=2
Matilda is filling a circular section of her porch with colorful pebbles. She knows the diameter of the circular section is 15ft, and each bag of pebbles covers 10ft. How many bags of pebbles will Matilda need? A. 15 bags B. 16 bags C. 17 bags D. 18 bags
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On Friday, a local restaurant served 200 customers. Of these, 168 people ordered soup. What percent of the customers ordered soup?
How do you solve this problem 8a+a-3=6a-2a-3

How are rational expressions related to rational numbers?

Answers

A rational expression is the same way that any integer is also a rational number. You can stick to any polynomial in the numerator of a fraction and put "1" in the denominator.

Any large random sample from a group of people will be representative of the entire group.True
False

Answers

False.

In a random sample each member of the group has the same chances to be choosen. A representative sample replicates the characteristcs that you want of the group. Many times you need to make the sampling not random to pick a sample that represents or replicates the group.

The probability that a given urine sample analyzed in a pathology lab contains protein is 0.73 (event A). The probability that the urine sample contains the protein albumin is 0.58 (event B). The probability that a sample contains protein, given that albumin is detected, is 1. Which statement is true?
a. Events A and B are dependent because P(A|B) =P(A).
b. Events A and B are dependent because P(A| B) ≠ P(B).
c. Events A and B are dependent because P(A|B) = P(A) + P(B).
d. Events A and B are dependent because P(A| B)≠ P(A).
e.Events A and B are dependent because P(A|B) = P(A).

Answers

The right answer for the question that is being asked and shown above is that: "e.Events A and B are dependent because P(A|B) = P(A)." The probability that a sample contains protein, given that albumin is detected, is 1. The statement that is true is this events A and B are dependent because P(A|B) = P(A).

Is 5mi bigger or 26,300 ft

Answers

5 mi = 26400 ft.

5 mi is bigger by 100 ft.

~Evie

Making Consumer ChoicesI. The Bread Machine (25 points)r /> In real life, you must often make choices about whether to buy something pre-made or make it yourself. There are many things to consider: quality of homemade vs. bought, expense, convenience, enjoyment of making something, etc. In this response, you will be looking at the choice of buying a bread machine or relying exclusively on store bought bread.

A. The bread machine you are interested in costs $100 with tax.
The ingredients to make one loaf of bread cost $0.80.
What is the rate of cost of one loaf of bread?

B. What is your start up cost? (cost of machine)

C. Write a linear equation, y = mx + b for the total cost.

D. Graph the equation on the graph provided. You may use either Point Plotting or Slope-Intercept. Be sure to locate at least 3 points. You may want to do this in pencil in case you decide to use more points later in the problem.

Answers

cool question relying on real life scinarios

A.

1 loaf=inital cost for macine+cost per bread or
number of loaves=x
cost to make=y
y=100+0.8x
so to find 1 loaf, just subsitute 1 for x
y=100+.8(1)
y=100+0.8
y=100.80
1 loaf costs $100.80 to make

B.
start up cost is $100

C. linear equation is
start up cost+cost per loaf times loaf or
y=100+0.8x
in y=mx+b form
y=0.8x+100

C.
to find points, just subsitute values for x and get values for y (I used multiplules of 10 so that you wouldn't have to plot a decimal coordinate)

if we put it 0 for x, we get 100 for y
if we put in 10 for x, we get 108 for y
if we put in 20 for x, we get 116 for y
and of course don't use negative becasue you can't make negative amounts of bread

Publishing scientific papers online is fast, and the papers can be long. Publishing in a paper journal means that the paper will live forever in libraries. The British Medical Journal combines the two; it prints short and reasonable versions, with longer versions available online. Is this OK with authors? The journal asked about a random sample of 104 of its recent authors' several questions. One question was, "Should the journal continue using this system?"
In the sample, 72 said "yes."
(a) do the data give good evidence that more than two-thirds (67%) of authors support continuing this system? carry out an appropriate test to help answer this question.
(b) interpret the p-values from your test in the context of the problem.

Answers

Answer:

There is no significant evidence that more than two-thirds (67%) of authors support continuing this system.

Step-by-step explanation:

Let p be the proportion of authors who support continuing the system

Then hypotheses are:

$H_(0)$ : p=0.67

$H_(a)$ : p>0.67

To calculate the test statistic:

z= $\frac{p(s)-p}{\sqrt{(p*(1-p))/(N) } }$ where

p(s) is the sample proportion of authors who support the publishing system ( $(72)/(104)$ ≈0.692)

p is the proportion assumed under null hypothesis. (0.67)

N is the sample size (104)

Then z= $\frac{0.692-0.67}{\sqrt{(0.67*0.33)/(104) } }$ ≈ 0.477

p-value of test statistic is ≈0.317

Assuming a significance level 0.05, since 0.317>0.05 we fail to reject the null hypothesis.

p-value 0.317 is the probability that the sample is drawn from the distribution assumed under null hypothesis, that is where the proportion of authors supporting the new publishing system is at most 0.67

Final answer:

A hypothesis test for a proportion is used to determine whether more than two-thirds of authors support continuing the system. The p-value associated with the test is less than 0.0001, indicating that the data provide good evidence in favor of the alternative hypothesis. Therefore, the majority of authors support continuing the system.

Explanation:

To determine whether the data provides evidence that more than two-thirds (67%) of authors support continuing the system, we can use a hypothesis test for a proportion. We will use a significance level of 0.05.

Let's set up our hypotheses:

Null hypothesis (H0): p ≤ 0.67 (less than or equal to two-thirds support)
Alternative hypothesis (Ha): p > 0.67 (more than two-thirds support)

Using the normal approximation to the binomial, we can calculate the test statistic and p-value. With a sample size of 104 and 72 authors in favor, the test statistic is:

z = (72 - 0.67 * 104) / sqrt(0.67 * (1 - 0.67) * 104) ≈ 3.79

The p-value associated with a z-score of 3.79 is less than 0.0001. Since this p-value is less than 0.05, we reject the null hypothesis.

Therefore, the data provide good evidence that more than two-thirds of authors support continuing the system.