What is the square root of 14x15
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A car salesperson sells cars at prices ranging from $5,000 to $45,000. the histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years. the median of the car is ___. - $20,000 - $25,000 - $30,000 - $40,000 the distribution exhibits ___. - a negative skew - a positive skew - symmetry - uniformity throughout
Simplify 3z – (3x – 2z) + 2x. Please could you tell me how you worked it out, thanks :)
What is the average rate of change of h over the interval 5 ≤ t ≤ 9 ?
What is the y-intercept of the line? y = -2x - 8 y-intercept =
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Working;
Start by finding the derivative of the function f(x);
Turning points occur when the derivative function=0;
Thus
2x-2=0
x=1
when x=1 then
f(1)=
=7
Turning point then is (1,7)
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9/12= 3/4
3
9/3 = 3
12/3 = 4
9/12 = 3/4
Hope this helps :)
−1(6m2 − 18m + 36)
−6m(m2 − 3m + 6)
−6(m2 + 3m − 6)
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You have to find the greates common divisor of the coefficientes, which is -6 and then divide each momomial with lead to: -6 (m^2 + -3m + 6).
You can verifiy the result by multiplying -6 times the polynomial inside the parenthesis, using the distributive property.
Answer:
The first one is the right one i just took the test
Step-by-step explanation:
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Answer:
The maximum height that the ball reaches is sf = 31 feet from the ground
Step-by-step explanation:
Solution:-
- A ball is thrown vertically upwards from an initial elevation of si = 6 feet from the ground.
- The velocity with which the ball was thrown up, vi = 40 ft/s
- We can determine the maximum height of the ball when it is thrown vertically up by using the 3rd kinematic equation of motion.
vf^2 - vi^2 = 2*g*( sf - si )
Where,
vf : The final velocity of the ball, for maximum height it is = 0
sf : The final height of the ball from the ground
g : Gravitational constant = -32 ft/s^2
0 - 40^2 = -2*32*( sf - 6 )
sf - 6 = 25
sf = 31 feet
- The maximum height that the ball reaches is sf = 31 feet from the ground.
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Answer:
Step-by-step explanation:
Correct option is C)
There are 15 boys and 10 girls in a class
We have to select 3 students such that there should be 1 girl and 2 boys
The number of ways we can select 3 students is
25C3=2300
The number of ways we can select 3 students such that there is 1 girl and 2 boys is 15×7×10=1050
The probability is 1050/2300 =21/46
Therefore the correct option is C
Final answer:
finding the number of combinations for the desired scenario and the total possible combinations, we find that the probability is 21/46.
Explanation:
In order to solve this problem, we need to apply the principles of combinatorics and probability. The total number of students in the class is 25 (10 boys and 15 girls). Firstly, let's calculate the combinations for the scenario of selecting 1 boy out of 10. This can be done by 10C1 resulting in 10 possibilities. Secondly, let's calculate the combinations of selecting 2 girls out of 15, which is 15C2 and gives us 105 possibilities.
Multiply those together to find the total scenario we're interested in, which is 1,050. The total possible combinations of selecting 3 students out of 25 irrelevant of gender would be 25C3, resulting in 2,300 possible combinations.
Therefore, the probability that the selected students are 1 boy and 2 girls is 1,050/2,300. Simplifying this fraction gives us 21/46.
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