Hi I just have a question how do you divide 18/32 with out a calculator.If I divide it in a piece of paper it comes out a different answer that is not correct the one that is correct is the one that comes out in the calculator 18/32= 0.5625

so i need to know how to divide 18/32 without a calculator because in my test calculators are not allowed thank you .

Answers

Answer 1

Answer: first set it up like this: $32 √(18)$
then add a zero on to the 18 and a decimal point like this: $32 √(18.0)$
then solve for 180/32 and add a decimal in the same location that it is in the 18.0 Hope this helps!

Answer 2

Answer: Try cross multiplying and then simplifying the answer

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What number is 1.6 more than 3.7

Answers

Answer: 5.3

Step-by-step explanation: To solve this question, all you need to do is add the numbers together. 1.6+3.7=5.3

Answer:

the answer is5.3

Step-by-step explanation:

3.7+1.6=5.3

What is (5-sqrt of 2)(3-sqrt of 2)

Answers

then the answer is 17 minus 8 times the square root of 2, or 5.68629

Y=2x-5
3x+8y+32=56
What does y and x equal?

Answers

y = 2x - 5
3x + 8y + 32 = 56
3x + 8(2x - 5) + 32 = 56
3x + 8(2x) - 8(5) + 32 = 56
3x + 16x - 40 + 32 = 56
19x - 8 = 56
      + 8   + 8
   19x = 64
      19    19
   x = 3.4
y = 2(3.4) - 5
y = 6.8 - 5
y = 1.8
(x, y) = (3.4, 1.8)

Solve for x algebraically: 7-3(4x-8)<6x+12-9x

Answers

7-3(4x-8)<6x+12-9x
7-12x+24<6x+12-9x
-12x-6x+9x<12-7-24
-9x<-19
-x<-19/9
x>19/9

Answer: x>19/9 or (19/9 , +∞)

(02.03 MC) The temperature at a mountain base camp was −2 degrees Celsius on Thursday. Friday morning, the temperature was 1 degree Celsius lower than it was on Thursday. By Friday evening, the temperature was 3 degrees Celsius lower than it was that morning. What was the temperature at the base camp Friday evening? (1 point) −9 degrees Celsius −8 degrees Celsius −7 degrees Celsius −6 degrees Celsius

Answers

Answer:

The temperature at the base camp Friday evening is - 6 degrees Celsius.

Step-by-step explanation:

To get the temperature at a mountain base camp on Friday evening, we must translate statement into a mathematical form:

(i)The temperature at a moutain base camp was - 2 degress Celsius on Thursday:

$T_(o) = -2\,^(\circ)C$

(ii)Friday morning, the temperature was 1 degree Celsius lower than it was on Thursday:

$\Delta T_(1) = -1\,^(\circ)C$

(iii)Friday evening, the temperature was 3 degrees Celsius lower that it was that morning:

$\Delta T_(2) = -3\,^(\circ)C$

The temperature at the base camp Friday evening is:

$T = T_(o)+\Delta T_(1)+\Delta T_(2)$

$T = -2\,^(\circ)C-1\,^(\circ)C-3\,^(\circ)C$

$T = -6\,^(\circ)C$

The temperature at the base camp Friday evening is - 6 degrees Celsius.

Answer:

D) -6 degrees Celsius

What is the range and domain of the function : y= sqrt(x) -5 ... Can you please explain? Thanks btw the square root is only over the x

Answers

Domain of $√(x)$ - 5 : x ≥ 25 .

Range of √x - 5 : y ≥ -5 .

Given,

f(x) = √x - 5

Here,

To find the domain,

√x - 5 ≥ 0

√x ≥ 5

Squaring both sides ,

x ≥ 25 .

Thus domain of √x - 5 is x ≥ 25 .

Range of √x - 5,

To define the range of the function the value of x can not be negative as it will make the function complex .

So,

Range will be ,

y ≥ -5 .

Know more about domain and range,

brainly.com/question/30133157

#SPJ2

okay so basically domain =input and range =output. you can never have a negative number underneath the square root sign because it will make the answer imaginary (i), unless you are on that concept. Therefore the range is any number greater than 0. -> all real numbers greater than or = 0

for the range if you input 0 as x you will get -5, so any number you input after 0 will be greater than -5. so range is all real numbers greater than or equal to -5.

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