Sin2x/1+cos2x=tanx
How do I prove this with the double angle law

Answers

Answer 1
Answer: sin(2x) = 2 sin x cos x \n \n cos(2x) = cos^2 x - sin^2 x
After Substituting:
(2 sin x cos x)/(1+cos^2 x - sin^2 x)
Use pythagorean thm:
1 - sin^2 x = cos^2 x
......................
(2 sin x cos x)/(2cos^2 x) \n \n = (sinx )/(cos x) \n \n = tan x

Related Questions

If 2/3x+1/2y=5 what is the value of 4x+3y
2 mi. yd. I'm confused​
Identify which equations have one solution, infinitely many solutions, or no solution. No
. What would be the new coordinates if (-2,-4) is translated 5 units up and7 units to the left.
Question 6(06.02 MC)Which of these is the algebraic expression for "5 less than 6 times some number?" (1 point)6t - 5Ob5t-6С5 - 6tOd6-50

Solve the equation. And write all solutions in general form.

Answers

Answer:

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Step-by-step explanation:

8 cos^2 x + 4 cos x-4 = 0

Divide by 4

2 cos^2 x +  cos x-1 = 0

Let u = cos x

2 u^2 +u -1 =0

Factor

(2u -1) ( u+1) = 0

Using the zero product property

2u-1 =0    u+1 =0

u = 1/2      u = -1

Substitute cosx for u

cos x = 1/2    cos x = -1

Take the inverse cos on each side

cos ^-1(cos x) = cos ^-1(1/2)   cos ^-1( cos x) =cos ^-1( -1)

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Solve for x Write both solutions, seperated by a comma 4x^2+5x+1=0

Answers

Answer:

-1/4 , -1

Step-by-step explanation:

I solved it using Factorization method and Quadratic Equation .

Factorization Method

4x^2+5x+1=0\nWrite +5x- as- a -difference(write+5x-using- two- numbers -in-which-their-sum-is ; 5-and-their-product-is ; 4)\n4x^(2) +4x+1x+1=0\nFactorize-out-common-terms\n4x(x+1)+1(x+1)=0\nFactor-out-(x+1)\n(4x+1)(x+1)=0\n4x+1 =0    \nx+1=0\n4x=0-1\nx =0-1\n4x =-1\nx =-1\n4x=-(1)/(4) \n\nAnswer = -1/4 , -1

Quadratic Equation

4x^2+5x+1=0\na = 4\nb =5\nc = 1\n\nx =(-b\±√(b^2 -4ac) )/(2a) \n\nx = (-(5)\±√((5)^2-4(4)(1)) )/(2(4)) \n\nx = (-5\±√(25-16) )/(8) \n\nx = (-5\±√(9) )/(8) \n\nx = (-5\±3)/(8) \n\nx =(-5+3)/(8) \n\nx = (-5-3)/(8) \n\nx = (-2)/(8) \n\nx = (-8)/(8) \n\nx = -(1)/(4) \nx=-1

hernando is choosing a random number between 0 and 9 state the number of successful outcomes for choosing an even number

Answers

Let’s see 1,2,3,4,5,6,7,8,9
We have to identify our evens from our odds
2,4,6,8 are evens
1,3,5,7,9 are odds.
From this we can conclude there are 4 even numbers so that is a 4/9 chance to pick an even or 44% chance.

Hope this helped!!!

In isosceles triangle ∆ABC, BM is the median to the base AC . Point D is on BM . Prove the following triangle congruencies:∆ABD ≅ ∆CBD

Answers

Answer:

We know that triangle ABD and triangle CBD are congruent because of SAS.

Step-by-step explanation:

AB is congruent to BC because of the definition of an isosceles triangle

BD=BD because of the reflexive property

m<ABD=m<CBD because BM is the median of an isosceles triangle

Thus, triangle ABD is congruent to triangle CBD because of SAS

Let X∼ Exponential (λ )and let t be a constant with 0 0 be any value.

Answers

Answer:

Hello! Hope you are having a good day. Your answer is F. I just did this. Good luck!

Step-by-step explanation:

In △ABC, point P∈ AB
is so that AP:BP=1:3 and point M is the midpoint of segment
CP
. Find the area of △ABC if the area of △BMP is equal to 21m2.

Answers

Answer:

56 m²

Explanation:

A diagram can be helpful.

Triangles with the same altitude will have areas proportional to the length of their bases.

The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...

... ACPB = 21 m² + 21 m² = 42 m²

The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...

... ACPA : ACPB = PA : PB = 1 : 3

... ACPA : 42 m² = 1 : 3

So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...

... AABC = ACPA + ACPB = 14 m² + 42 m²

... AABC = 56 m²