What are the elements in the first vertical line of the periodic table?

Answers

Answer 1

Answer: The first vertical row of elements are all alkali metals with the exception of hydrogen which is a transition metal.The elements are:Hydrogen(H) with an atomic number of 1Lithium(Li) with an atomic number of 3Sodium(Na) with an atomic number 11Potassium(k) with an atomic number 19Rubium(Rb) with an atomic number of 37Cesium(Cs) with an atomic number of 55Fracium(Fr) with an atomic number of 87

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A sample contains 10.5 g of the radioisotope Pb-212 and 157.5 g of its daughter isotope, Bi-212. How many half-lives have passed since the sample originally formed?4
14
15
147.5

Answers

Answer: The sample must have passed 4 half-lives after the sample was originally formed.

Explanation: This is a type of radioactive decay and all the radioactive process follow first order kinetics.

Equation for the reaction of decay of $_(82)^(212)\textrm{Pb}$ radioisotope follows:

$_(82)^(212)\textrm{Pb}\rightarrow _(83)^(212)\textrm{Bi}+_(-1)^0\beta$

To calculate the initial amount of $_(82)^(212)\textrm{Pb}$ , we will require the stoichiometry of the reaction and the moles of the reactant and product.

Expression for calculating the moles is given by:

$\text{no of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of $_(82)^(212)\textrm{Pb}$ left = $(10.5g)/(212g/mol)=0.0495moles$

Moles of $_(83)^(212)\textrm{Bi}=(157.5g)/(212g/mol)=0.7429moles$

By the stoichiometry of above reaction,

1 mole of $_(83)^(212)\textrm{Bi}$ is produced by 1 mole $_(82)^(212)\textrm{Pb}$

So, 0.7429 moles of $_(83)^(212)\textrm{Bi}$ will be produced by = $(1)/(1)* 0.7429=0.7429\text{ moles of }_(82)^(212)\textrm{Pb}$

Amount of $_(82)^(212)\textrm{Pb}$ decomposed will be = 0.7429 moles

Initial amount of $_(82)^(212)\textrm{Pb}$ will be = Amount decomposed + Amount left = (0.0495 + 0.7429)moles = 0.7924 moles

Now, to calculate the number of half lives, we use the formula:

$a=(a_o)/(2^n)$

where,

a = amount of reactant left after n-half lives = 0.0495 moles

$a_o$ = Initial amount of the reactant = 0.7924 moles

n = number of half lives

Putting values in above equation, we get:

$0.0495=(0.7924)/(2^n)$

$2^n=16.0080$

Taking log on both sides, we get

$n\log2=\log(16.0080)\nn=4$

Answer:

Explanation:

Edg 2020

What type of mixture scatters light and cannot be filtered? a colloid, a heterogeneous mixture a solution, a heterogeneous mixture a colloid, a homogeneous mixture a solution, a homogeneous mixture

Answers

the type of mixture that scatters light and cannot be filtered is : A colloid

Colloids include gels, sols, and emulsions and it consist of non-crystalline substance that has large molecules

hope this helps

Colloids. The particles are usually clumpy.

Example of transforming from electric energy to MAGNETICAL energy
PLZZ

Answers

Answer:

speaker

Explanation:

speaker runs by the help of electrical energy and the magnetic energy is used and finally it is converted into sound energy

Answer:

the motor in today's standard power drills. the motor in today's standard power saws. the motor in an electric tooth brushes.

Explanation:

More axamples could be that both devices work because of electromagnetic induction, which is when a voltage is induced by a changing magnetic field.

Increasing the intensity and duration of an exercise program too quickly can lead to injury.a. True
b. False

Answers

It is true that a sudden increase in both intensity and duration of physical exercise can result in injury. The body needs time to process any changes. Muscles need to build strength and flexibility gradually and the joints need time to acclimate to changes in pressure.

this is a true statement

Which of these solutions has the highest freezing point?1.0 M molecular sucrose (C12H22O11)
1.0 M ionic sodium chloride (NaCl)
1.0 M ionic calcium bromide (CaBr2)
1.0 M ionic aluminum bromide (AlBr3)
1.0 M ionic potassium chloride (KCl)

Answers

Answer: 1.0 M molecular sucrose (C₁₂H₂₂O₁₁).

Explanation:

1) The depression of the freezing point of a solvent when you add a solute is a colligative property.

2) Colligative properties are those physical properties of solutions that depends on the number of solute particles dissolved into the solution.

3) The relation between the number of solute particles and the depresson of the freezing point is proportional: the greater the number of solute particles the greater the freezing point depression.

4) You need to find the solution with the highest freezing point, this is the solution in which the freezing point decreased the least.

5) Then, that is the solution with least number of solute particles.

6) Since all the given solutions have the same molarity (1.0 M), you only have to deal with the possible ionization of the different solutes.

7) NaCl, CaBr₂, AlBr₃, and KCl are ionic compounds, so each unit of them will ionize into two, three, four, and two ions, respectively, while sucrose, being a covalent compound does not dissociate.

Then, 1.0 M solution of sucrose will have less solute particles than the others, and will exhitibit the lowest freezing point depression, meaning that it will have the highest freezing point of the given solutions.

The right answer for the question that is being asked and shown above is that: "1.0 M ionic aluminum bromide (AlBr3)." the solution that has the highest freezing point is that 1.0 M ionic aluminum bromide (AlBr3)

Explain the reason for sodiums location in the periodic table , explaining both location in its group and in its period

Answers

Explanation:

It is known that the atomic number of sodium is 11 and its electronic distribution is 2, 8, 1.

As the number of rows (called periods) in the periodic table represent the number of shells present in an element.

Since, sodium element have only two shells. Therefore, sodium lies in row 2 of the periodic table.

Also, the elements which contain same number of valence electrons lie in the same group.

Therefore, sodium belongs to group 1 and elements of the group 1 are also known as alkali metals.

Thus, we can conclude that in the periodic table sodium lies in period 2 and group 1.

Sodium is part of the alkali metal group because it has properties that have periodic patterns relating to the rest of the group. It is in it's period because of it's energy level and the amount of electrons on that level. It is also apart of it's group because of how many valence electrons it has.

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