MATHEMATICS HIGH SCHOOL

The sum of two numbers is 50. the greater number is four less than five times the lesser number. Find the numbers

Answers

Answer 1
Answer:

The required two numbers are 9 and 41.

What is the equation?

The equation is defined as a mathematical statement that has a minimum of two terms containing variables or numbers that are equal.

Let x be the lesser number, and y be the greater number.

From the question, we know that:

x + y = 50 (Equation 1: The sum of the two numbers is 50)

y = 5x - 4 (Equation 2: The greater number is four less than five times the lesser number.)

The equation is to solve for one of the variables, and then substitute that value into the other equation to find the other variable.

Then, two numbers are x = 9 and y = 41.

Learn more about the equations here:

brainly.com/question/10413253

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Answer 2
Answer: X=greater number
Y=lesser number
x+y=50
x=5y-4

5y-4+y=50
+4 +4
5y+y=54
V
6y=54
/6 /6
y=9

X=5(9)-4
X=45-4
X=41

41+9=50 ✔️

Greater number=41
Lesser number=9

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Answers

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answer 4

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Answers

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A'(1,1) , B'(5,3), C'(2,5)

Explanation:

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Answers

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If the tournament is 195 miles away, how many gallons of gas will she have to purchase? g= 2d/26

Answers

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Answer:

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Step-by-step explanation:

Solve for x and express your answer as a logarithm.2(10^(3x) ) = 24


Simplify your answer as much as possible.


Use the following notations where necessary:

• For fractions, use the / symbol to separate numerator and denominator, like this: 42/53

• For logs with a base of 10, such as log107, just write the log without the base and place the value in parentheses, like this: log(7)

• For logs with a base other than 10, write the base after an underscore then place the value in parentheses. For example, to write log27, write it like this: log_2(7)

Answers

2\cdot10^(3x)=24\ \ \ \ |divide\ both\ sides\ by\ 2\n\n10^(3x)=12\iff\log(10^(3x))=\log(12)\n\n3x\log(10)=\log(12)\n\n3x=\log(12)\ \ \ \ |divide\ both\ sides\ by\ 3\n\n\boxed{x=(\log(12))/(3)}\to(\log(12))/(3)=(1)/(3)\log(12)=\log\left(12^(1)/(3)\right)=\boxed{\log\sqrt[3]{12}}

Use:\n\log_ab^c=c\log_ab\n\log_aa=1\na^(1)/(n)=\sqrt[n]{a}\n-------------------\n\nAnswer:\boxed{x=(\log(12))/(3)\ other\ form\ x=\log(\sqrt[3]{12})}

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Answers

Answer: B,C,D

Step-by-step explanation:

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