MATHEMATICS HIGH SCHOOL

Find the balance in the account. $700 principal earning 5%, compounded monthly, after 9 years

Answers

Answer 1

Answer:

Answer: The balance in the account after 9 years is $1085.93.

Step-by-step explanation:

Since we have given that

Principal amount = $700

Rate of interest = 5%

Number of years = 9

Since we have mentioned to use "Compound Interest " method:

As we know the formula for above i.e.

$A=P(1+(r)/(100))^n\n\nA=700(1+(5)/(100))^9\n\nA=\$1085.93$

Hence, the balance in the account after 9 years is $1085.93.

Answer 2

Answer: A=700×(1+0.05÷12)^(12×9)
A=1,096.79

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Answers

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There were 26 students in the classroom. 14 of the students went to thecafeteria and the rest went to the gym. What percentage of students
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Answers

Answer:

53.85%

Step-by-step explanation:

14 of the 26 went to the cafeteria

14/26

7/13

Change to decimal form

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Change to percent form from decimal form

53.85%

Answer:

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What is the solution to this equation?A. x=-4
B. x= 100
C. x= 4
D. x=-100

Answers

Answer:

D. x = - 100

Step-by-step explanation:

$\bold{\frac x5=-20}\n{}\ \ ^(\cdot5\qquad\cdot5)\n\bold{\frac x5\cdot\frac51=-20\cdot5}\n\n\bold{x=-100}$

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Answers

Answer:

-15

Step-by-step explanation:

The sum of the 2 numbers (-13) is a negative, meaning the missing number also has to be negative. To find it, you must ask yourself, what minus 2 would equal 13.

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here is a picture of the previous question

Answers

$2m-\frac { 1 }{ 2 } =\frac { m }{ 7 } +\frac { m }{ 2 } \n \n \frac { 1 }{ m } \left( 2m-\frac { 1 }{ 2 } \right) =\frac { 1 }{ m } \left( \frac { m }{ 7 } +\frac { m }{ 2 } \right)$

$\n \n \frac { 2m }{ m } -\frac { 1 }{ 2m } =\frac { m }{ 7m } +\frac { m }{ 2m } \n \n 2-\frac { 1 }{ 2m } =\frac { 1 }{ 7 } +\frac { 1 }{ 2 } \n \n 2-\frac { 1 }{ 7 } -\frac { 1 }{ 2 } =\frac { 1 }{ 2m }$

$\n \n \frac { 28 }{ 14 } -\frac { 2 }{ 14 } -\frac { 7 }{ 14 } =\frac { 1 }{ 2m } \n \n \frac { 19 }{ 14 } =\frac { 1 }{ 2m } \n \n { \left( 2m \right) }^( -1 )={ \left( \frac { 14 }{ 19 } \right) }^( -1 )$

$\n \n 2m=\frac { 14 }{ 19 } \n \n \frac { 1 }{ 2 } \cdot 2m=\frac { 14 }{ 19 } \cdot \frac { 1 }{ 2 } \n \n m=\frac { 14 }{ 38 } =\frac { 7 }{ 19 }$

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