What is word meaning "heated to a glow"?

Answers

Answer 1

Answer:
I think the word you want is "incandescent".

Related Questions

Under what conditions might a stream's volume increase, and under what conditions might it decrease? How would the size of the sediment particles in the stream's load differ in the two situations?
[URGENT] A swimmer wants to end up at a dock due north of her starting position on the south shore of a river. In still water her maximum speed is 1.25m/s. The river has a current flowing 0.35m/s [E].a.) calculate the direction that she must aim herself through the water to arrive at the dock. b.) how long will it take for the swimmer to cross the river, if the distance from the starting point to the dock is 300 m?Please show all your work, thanks
Two objects with different masses collide and bounce back after an elastic collision. Before the collision, thetwo objects were moving at velocities equal in magnitude but opposite in direction. After the collision, A. the less massive object had gained momentum. B. the more massive object had gained momentum. C. both objects had the same momentum. D. both objects lost momentum.
PLEASE HELP I NEED ANSWERS ASAP I WILL GIVE BRAINIEST AND 5 STARS
A plane is flying due east at 520 mile/hour. Another plane is 20 miles east of that plane, flying with a velocity of 650 miles/hour due west what is their relative velocity

A solid, horizontal cylinder of mass 18.0 kg and radius 1.70.0 m rotates with an angular speed of 40 rad/s about a fixed vertical axis through its center. A 0.8 kg piece of putty is dropped vertically onto the cylinder at a point 0.300 m from the center of rotation and sticks to the cylinder. Determine the final angular speed of the system.

Answers

Answer:39.88 rad/s

Explanation:

Given

mass of cylinder m_1=18 kg

radius R=1.7 m

angular speed $\omega =40rad/s$

mass of $m_2=0.8 kg$ dropped at r=0.3 m from center

let $\omega _2$ be the final angular velocity of cylinder

Conserving Angular momentum

$L_1=L_2$

$\left ( (m_1R^2)/(2)\right )\omega =\left ( (m_1R^2)/(2)+m_2r^2\right )\omega _2$

$\left ( (18\cdot 1.7^2)/(2)\right )\cdot 40=\left ( (18\cdot 1.7^2)/(2)+0.8\cdot 0.3^2\right )\omega _2$

$26.01* 40=26.082* \omega _2$

$\omega _2=39.88 rad/s$

The potential energy of a catapult was completely converted into kinetic energy by releasing a small stone with a mass of 20 grams. The velocity of the stone when it reached the target was 15.0 meters/second. What was the value of the kinetic energy of the stone when it reached the target?

Answers

Answer: 2.25 J

Explanation: Kinetic energy is the energy possessed by an object by virtue of its motion.

$K.E=(1)/(2)* mv^2$

m= mass of object= 20 g = 0.02 kg (1 kg= 1000 g)

v= velocity of object= 15 m/s

$K.E=(1)/(2)* 0.02* 15^2=2.25kgm^2s^(-2)=2.25J$

$(1J=1kgm^2s^(-2))$

1,000 grams = 1 kilogram
20 grams = 0.02 kilogram

Kinetic energy = (1/2) (mass) x (speed)²

(1/2) (0.02) x (15)² =

(0.01) x (225) = 2.25 joules

A mass that weighs 8 lb stretches a spring 24 in. The system is acted on by an external force of 4 sin 4t lb. If the mass is pulled down 6 in. and then released, determine the position of the mass at any time. Determine the first four times at which the velocity of the mass is zero

Answers

Answer:

$t = (\pi)/(8), (\pi)/(4), (3\pi)/(8), (3 \pi)/(4)$

Explanation:

The equation of force is

F = 4 sin 4 t

Compare with the standard equation

f = A sin wt

where, w is the angular frequency and A is the amplitude.

Now

w = 4 rad/s

Let the time period is T.

the relation for the time period is

$T = (2\pi)/(w)\n\nT = (2 \pi)/(4)\n\nT = (\pi)/(2)$

the time period is defined as the time taken by the body to complete one oscillation.

So, the velocity is zero at the extreme points where the object is at time, T/4 and its odd T/2, 3T/4, 3T/2, etc.

So, the velocity is zero at time

$t = (\pi)/(8), (\pi)/(4), (3\pi)/(8), (3 \pi)/(4)$

Final answer:

To determine the position of the mass and the times when the velocity is zero in a mass-spring system.

Explanation:

To determine the position of the mass at any time, we need to solve the equation of motion for the mass-spring system. The equation is:

mx'' + kx = Fext

where m is the mass, x is the displacement of the mass from its equilibrium position, k is the spring constant, and Fext is the external force. We can solve this differential equation to find the position of the mass as a function of time.

To determine the first four times at which the velocity of the mass is zero, we need to solve for the velocity of the mass, which is given by:

v = x'

We can find the times at which the velocity is zero by finding the values of t for which x' = 0.

Learn more about Mass-spring system here:

brainly.com/question/30393799

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In which situation can you be at rest and moving at the same time?When playing soccer, you are at rest relative to the ball and moving relative to the field.

When swimming, you are at rest relative to the water and moving relative to the sides of the pool.

When riding a bike, you are at rest relative to the bicycle and moving relative to the road

Answers

I think the answer is ( When riding a bike...)

I believe the last one about the bike is correct.

4. Which problem is most likely to result from the use of nuclear power?O A. storage of radioactive wastes
B. miners getting trapped underground
C. oil spills that pollute oceans and beaches
O D. pollutants in the groundwater after drilling

Answers

Answer:

i think it is A

Explanation

An unbalanced force of 40. newtons keeps a5.0-kilogram object traveling in a circle of radius
2.0 meters. What is the speed of the object?
(1) 8.0 m/s (3) 16 m/s
(2) 2.0 m/s (4) 4.0 m/s

Answers

This can be answered using the formula of centripetal force. In the given problem, the centripetal force (40 N), mass (5 kg), radius (2 m) are all named, except for the speed. The formula is shown below:

F = mv^2 / r

Substituting the given values:

40 N = 5kg(v^2) / 2
80 = 5 * v^2
v^2 = 16
v = 4

Therefore, the correct answer is 4.0 m/s (4).

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