imagine that the number 2 button on your calculator is damaged and cannot be used.use a flow chart to show 3 different ways in which you can calculate 24x12

Answers

Answer 1

Answer: (6x4)(4x3)
Hope this helps you. I accidentally wrote my answer in the comment box.

Related Questions

Two customers went to a flower shop to buy roses and daisies. Each bunch of roses costs the same amount, and each bunch of daisies costs the same amount.The first customer paid $62.00 for 3 bunches of roses and 4 bunches of daisies.The second customer paid $60.00 for 2 bunches of roses and 5 bunches of daisies.What was the cost, in dollars, of each bunch of roses?(A) $8.25(B) $9.50(C) $10.00(D) $12.00
Y = 10 + 16x − x^2y = 3x + 50 If (x1, y1) and (x2, y2) are distinct solutions to the system of equations shown above, what is the sum of the y1 and y2?
1. Round to the nearest hundredth. 1.824A. 1.82B. 1.83C. 2D. 1.8
Factor the perfect square trinomial 4x^2– 20x + 25.
Subtract the quotient of 15 ÷ 3 from the sum of 33 and 7.

Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.
a. x = 8, y = 17
b. x = 6, y = 8
c. x = 8, y = 10
d. x = 8, y = 6

Answers

The answer is d.

3x-14 = x-2 solve for x

4y-7 = y+11 solve for y

3x-14=x+2
Add 14 to both sides.
3x=x+16
Subtract x from both sides.
2x=16
Divide by 2.
x=8

4y-7=y+11
Add 7 to both sides.
4y=y+18
Subtract y from both sides.
3y=18
Divide by 3.
y=6

The answer is d.

The weight of a person on Venus is directly proportional to their weight on Earth. Aperson weighing 120 pounds on Earth weighs 106 pounds on Venus.
Approximately how much would a person weighing 180 pounds on Earth weigh on
Venus?

Answers

Answer:

a person would weigh 158 pounds on venus

Step-by-step explanation:

weight of a person on venus is directly proportional to their weight on earth

i.e. weight on venus ∝ weight on earth

weight on venus = k * weight on earth

where k is the constant of proportionality

according to the question:

106 = k * 120

k = 106/120 = .88

thus,

person weighing 180 pounds on earth weighs on venus:

weight on venus = .88 * 180

= 158 pounds

PLS HELP ASAP Consider a standard deck of 52 playing cards with 4 suits. If A is the event of drawing a 6 from the deck, and B is the event of drawing a black playing card from the deck, what is the intersection of A and B? (Remember that the black cards are spades and clubs.) A) drawing a 6, a club, or a spade B) drawing the 6 of hearts or the 6 of diamonds C) drawing a 6, a heart, or a diamond D) drawing the 6 of clubs or the 6 of spades

Answers

Answer:

Correct answer is option D) drawing the 6 of clubs or the 6 of spades

Step-by-step explanation:

Given that:

A standard deck of 52 playing cards with 4 suits.

A be the event of drawing a card with 6 from the deck.

B be the event of drawing a black card from the deck.

So, event A will have 4 possibilities i.e. {6 of club, 6 of spade, 6 of diamond, 6 of heart}

And event B will have 26 possibilities {Any card (including 6) from club or spade}

Intersection of two sets is defined as the common elements in the two sets.

As per the explanation of the sets and elements in the sets given above:

If we take intersection it will be:

{6 of club or 6 of spade}

Hence, Correct answer is option D) drawing the 6 of clubs or the 6 of spades

Final answer:

The intersection of events A and B is represented by drawing the 6 of clubs or the 6 of spades (D) .

Explanation:

The intersection of events A (drawing a 6) and B (drawing a black playing card) refers to the cards that satisfy both criteria. In this case, event A consists of the card 6 from any suit, while event B consists of the black cards (spades and clubs) from any value. To determine the intersection, we need to find the cards that are both a 6 and black.

Looking at the options given, option D) drawing the 6 of clubs or the 6 of spades represents the cards that satisfy both events. The 6 of clubs and the 6 of spades are black cards and also have a value of 6. Therefore, the intersection of events A and B is represented by option D).

Learn more about Intersection here:

brainly.com/question/32117953

#SPJ3

Ax+by=1
bx-ay=a+b
solve in linear equation in 2 variables

Answers

$\left\{\begin{array}{ccc}ax+by=1&/\cdot a\nbx-ay=a+b&/\cdot b\end{array}\right\n\n+\left\{\begin{array}{ccc}a^2x+aby=a\nb^2x-aby=ab+b^2\end{array}\right\n------------\n.\ \ \ \ \ a^2x+b^2x=a+ab+b^2\n.\ \ \ \ \ \ (a^2+b^2)x=a+ab+b^2\n.\ \ \ \ \ \ \ \ \ \ \ \ x=(a+ab+b^2)/(a^2+b^2)\n\na\cdot(a+ab+b^2)/(a^2+b^2)+by=1\n\n(a^2+a^2b+ab^2)/(a^2+b^2)+by=1\n\nby=1-(a^2+a^2b+ab^2)/(a^2+b^2)$

$by=(a^2+b^2)/(a^2+b^2)-(a^2+a^2b+ab^2)/(a^2+b^2)\n\nby=(a^2+b^2-a^2-a^2b-ab^2)/(a^2+b^2)\n\nby=(b^2-a^2b-ab^2)/(a^2+b^2)\n\ny=(b^2-a^2b-ab^2)/(a^2b+b^3)$

$y=(b(b-a^2-ab))/(b(a^2+b^2))\n\ny=(b-a^2-ab)/(a^2+b^2)\n\nAnswer:\n\nx=(a+ab+b^2)/(a^2+b^2)\ and\ y=(b-a^2-ab)/(a^2+b^2)$

ax+by=1
bx-ay=a+b
The solution in attached file

The sides of a triangle are in the ratio of 6:8:10 and its perimeter is 720 cm. Find its area.

Answers

216m²

Given that the sides of a triangle are in the ratio of 6:8:10 and their perimeter is equal to 720cm.

To find the area, we would use heron's formula which says area = √[s(s-a)(s-b)(s-c)] ,where a,b,c are the respective sides of the triangle and s = perimeter/2 but before that,we would need to find out the sides , for that , let's say the sides are equal to 6x ,8x & 10 x.

Then,

ATQ,

6x + 8x +10x = 720cm

24x = 720cm

x = 720cm/24

x = 30cm

therefore,

6x = 6*30cm = 180cm

8x = 8*30cm = 240cm

10x = 10*30cm = 300cm

and

s = 720cm/2 = 360cm

Now,

using heron's formula,

area = √[s(s-a)(s-b)(s-c)]

area = √[360cm(360cm-180cm)(360cm-240cm)(360cm-300cm)

area = √[360cm*180cm*120cm*60cm]

area = √(466,560,000cm⁴)

area = 21,600cm² or 216m²

The circles below is centered at the point (4,3) and has a radius of length 8. Whats its equation?

Answers

$centered =(x_(o),y_(o))= (4,3) \n radius : \ r= 8 \n \n General \ equation \ for \ circle: \n \n (x- x_(o) )^2+(y- y_(o) )^2 = r^2 \n \n(x- 4 )^2+(y- 3 )^2 = 8^2 \n \n(x- 4 )^2+(y- 3 )^2 = 64$

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