How much water must be evaporated from 64 ounces of a 2% salt solution to make a 10% salt solution?

Answers

Answer 1

Answer: $64 * 2\%=64 * 0.02=1.28$
64 ounces of a 2% salt solution contains 1.28 ounces of salt and thus 62.72 ounces of water.

The mass of the 10% solution is (x+1.28), where x is the mass of water.
1.28 divided by (x+1.28) must be equal to 10%.
$(1.28)/(x+1.28) * 100\%=10\% \n(1.28)/(x+1.28) * 100=10 \n1.28 * 100=10(x+1.28) \n128=10x+12.8 \n115.2=10x \nx=11.52$

The 10% solution contains 11.52 ounces of water.
$62.72-11.52=51.2$

51.2 ounces of water must be evaporated.

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Answers

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Answers

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