X+y=0 and x-y=10 solve by substitution.. How do I figure out the problem!

Answers

Answer 1
Answer: x+y=0 \n x-y=10 \n\nx=-y\nx-y=10\n\n-y-y=10\n-2y=10\ny=-5\n\nx-5=0\nx=5\n\n\boxed{(x,y)=(5,-5)}
Answer 2
Answer:   x+y=0
- x-y=10
--------------
(0)+2y=-10 [x and -x cancel each other out. y minus -y is the same as y+y]
y=-5 
now substitute -5 in for y in either problem:

x+-5=0
x=5

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A rain gutter is to be constructed of aluminum sheets 12 inches wide. After marking off a length of 4 inches from each edge, this length is bent up at an angle θ. The area A of the opening may be expressed as the function: A(θ) = 16 sin θ ⋅ (cos θ + 1). If θ = 90°, what is the area of the opening?

Answers

We are already given with the function to solve for the area:
A(θ) = 16 sin θ ⋅ (cos θ + 1)

We simply have to substitute the value of the angle into the function. So,
If θ = 90°,
A(
90°) = 16 sin (90°) ( cos (90°) + 1 )

Using the calculator or the definition of trigonometric functions at angle of 
90°, we get the value of the area:
A(90°) = 16 square inches

we know that

The area A of the opening may be expressed as the function:

A(\alpha) = 16 sin \alpha* (cos \alpha + 1)

For \alpha =90°

We simply have to substitute the value of the angle into the function

so

A(90) = 16*sin 90* (cos 90 + 1)

A(90) = 16*(1)* (0 + 1)

A(90) = 16 in^(2)

therefore

the answer is

the area of the opening is 16 in^(2)

If m\angle CED=101 then what is m\angle CEH∠CEH

Answers

Answer:

m∠CEH = 79°

Step-by-step explanation:

From the picture attached,

∠CED and ∠CEH are the pair of linear angles.

Since, pair of linear angles are supplementary angles.

m∠CED + m∠CEH = 180°

101° + m∠CEH = 180°

m∠CEH = 180° - 101°

             = 79°

Therefore, measure of angle CEH is 79°.

Can someone please help me with this ASAP ill love you forever

Answers

Answer:

Step-by-step explanation:

I can help :D

Please help very urgent will give brainliest

Answers

Answer: x= 45 degrees

Step-by-step explanation: The angle of a square is 90 degrees and it already tell you the other side is 45 degree so 90 - 45 = 45. So that means the answer is 45 degrees.

Since the sum of all the angles of any triangle is 180 degrees, just add 90 and 45 (the answer being 135), then subtract 135 from 180 (answer is 45).

Therefore, the missing answer is 45 degrees.

. Each parent has two of these for a particular gene. an- in arty-an Off

Answers

Each parent has two ALLELES for a particular gene.

6. Minimum value determined by the formula function f (x) = 2x ²-8x + p was 20. Value f (2) is.7. Shape factor of the quadratic equation 4x ²-13x = -3 is ...
8. Quadratic function whose graph passes through the point (-12.0) and has a turning point (-15.3) is ..
9. Roots of a quadratic equation: 4x ² + px +25 = 0 are x1 and x2, if the roots of the quadratic equation x1 ² + x2 ² = 12.5 then the value of p is ....
10. Equation x ²-4x +3 = 0 and x ² +4 x-21 = 0, has a root persekutuan.Akar the alliance is 

Answers

6)\ \ \ f(x)=2x^2-8x+p\nthe\ minimum\ value =20\ \ \ \Leftrightarrow\ \ \ y_(\ of\ vertex)=20\ \ \ \Leftrightarrow\ \ \ - (\Delta)/(2a) =20\n\n\Delta=(-8)^2-4\cdot2\cdot p=64-8p\ \ \Leftrightarrow\ \ - (64-8p)/(2\cdot2) =20\ \ \Leftrightarrow\ \ -16+2p=20\n\n2p=36\ \ \ \Leftrightarrow\ \ \ p=18\ \ \ \Rightarrow\ \ \ \ f(x)=2x^2-8x+18\n\nf(2)=2\cdot2^2-8\cdot2+18=2\cdot4-16+18=8+2=10

7)\ the\ shape\ factor\ of\ the\ quadratic\ equation\ 4x^2-13x = -3\n is\ a=4\ \ \ (\ a>0\ \ \ \rightarrow\ \ \ the\ shape\ is\ \cup\ )\n\n8)\ \ \ the\ turning\ point=(-15;3)\ \ \ \Rightarrow\ \ \ f(x)=a(x+15)^2+3\n\n the\ graph\ passes\ through\ the\ point\ (-12.0) \ \Rightarrow\ \ 0=a(-12+15)^2+3\n\n\Rightarrow\ \ \ a\cdot3^2=-3\ \ \ \Rightarrow\ \ \ a=- (3)/(9) =- (1)/(3) \ \ \ \Rightarrow\ \ \ f(x)=- (1)/(3)(x+15)^2+3

\Rightarrow\ \ \ f(x)=- (1)/(3)(x^2+30x+225)+3=- (1)/(3)x^2-10x-72\n\n9)\ \ \ 4x^2+px+25=0\n\n\Delta=p^2-4\cdot4\cdot25=p^2-400\n\ntwo\ solutions\ \ \Leftrightarrow\ \ \Delta>0\ \ \Leftrightarrow\ \ p^2-40>0\ \ \Leftrightarrow\ \ (p-20)(p+20)>0\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \Leftrightarrow\ \ \ p\in(-\infty;\ -20)\ \cap\ (20;\ +\infty)\n-------------------------------

the\ Vieta's\ formulas\ to\ the\ quadratic\ equation\ ax^2+bx+c=0\n\nx_1+x_2=- (b)/(a) \ \ \ and\ \ \ x_1\cdot x_2= (c)/(a) \n------------------------------\n\nx_1+x_2=- (p)/(4) \ \ \ and\ \ \ x_1\cdot x_2= (25)/(4) \n\nx_1^2+x_2^2=x_1^2+2\cdot x_1\cdot x_2 +x_2^2-2\cdot x_1\cdot x_2 =(x_1+x_2)^2-2\cdot x_1\cdot x_2 \n\nx_1^2+x_2^2=(x_1+x_2)^2-2\cdot x_1\cdot x_2 \ \ \ \Leftrightarrow\ \ \ 12.5=(- (p)/(4) )^2-2\cdot (25)/(4) \n\n

12.5= (p^2)/(16) +12.5 \ \ \ \Leftrightarrow\ \ \ (p^2)/(16)=0 \ \ \ \Leftrightarrow\ \ \ p^2=0 \ \ \ \Leftrightarrow\ \ \ p=0\n\n\n10)\ \ \ x^2-4x+3=0\ \ \ and\ \ \ x^2+4x-21=0\n\n x^2-4x+3=x^2+4x-21\ \ \Leftrightarrow\ \ -4x-4x=-21-3\n\n\ \ \Leftrightarrow\ \ -8x=-24\ \ \Leftrightarrow\ \ x=3