A student pushes a 40-N block across the floor for a distance of 10 m. How much work was done to move the block? Question 3 options: 4 J 40 J 400 J 4,000 J
Answers
Answer:
The work done to move the block is 400 Joules.
Explanation:
It is given that,
Force acting on the block, F = 40 N
The distance covered by the block, d = 10 m
We need to find the work done by the block. The work done by an object is given by :
W = 400 Joules
So, the work done to move the block is 400 Joules. Hence, the correct option is (B) "400 J".
Work = Force x distance
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Do you think that the universe has a starting point and ending point? explain.
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What is the acceleration caused by your push on the ball
B. Reflection gratings on plastic
C. Transmission gratings on glass
D. Replica transmission gratings on plastic
Answers
Final answer:
Holographic gratings are likely to produce the brightest spectra.
Explanation:
The correct answer is A. Holographic gratings are likely to produce the brightest spectra. Holographic gratings are created using interference patterns produced by laser light, resulting in highly precise and bright spectra. Reflection gratings on plastic (option B), transmission gratings on glass (option C), and replica transmission gratings on plastic (option D) can also produce spectra, but holographic gratings are known to have superior brightness and quality.
Learn more about Holographic gratings here:
#SPJ2
Answers
Answers
Answer: 1.81m
Explanation:
Given the following:
Horizontal speed = 4m/s
Height of table = 1m
Taking the vertical component of the motion:
Using:
S = ut + 0.5 at^2
Where, S = height of table, a = acceleration due to gravity (9.8m/s^2), t = time and u = Initial Velocity in vertical direction = 0
1 = 0(t) + 0.5(9.8)t^2
1 = 4.9t^2
t^2 = 1 / 4.9
t^2 = 0.204081
t = sqrt(0.204081)
t = 0.452s
For Horizontal :
Gravitational acceleration is absent, therefore distance can be calculated using:
Distance = Velocity × time
Distance = 4m/s × 0.452s
Distance = 1.808 m
Distance = 1.81m
Answers
Let's solve this problem by steps.
Method 1 -
Step 1 --> Taking GCF
Step 2 ---> Combining like terms
Or
Method 2 -
We can straight way subtract
Hope it helped you.. :)
2) calculate the potential energy of a 5 kg object sitting on a 3 m ledge
3) a rock is at the top of a 20 meter tall hill, the rock has a mass of 10 kg. how much potential energy does it have?
Answers
These questions are testing to see if you know
the formulas for work and potential energy ... or
if you know where to find them when you need them.
1). The formula for work is:
Work = (force) x (distance) .
In this question: Work = (25 N) x (6 m) = 160 joules .
_____________________________
The formula for potential energy is
PE = (mass) x (gravity) x (height) .
On Earth, gravity = 9.8 m/s²
This information gives you both of the other questions.
#2). PE = (mass) x (gravity) x (height)
= (5 kg) x (9.8 m/s²) x (3m) = 147 joules
#3). PE = (mass) x (gravity) x (height)
= (10 kg) x (9.8 m/s²) x (20 m) = 1,960 joules
Answers
The correct answer will be:
Planetary system.