When you turn on the light switch in a room, you have completed the _____. open circuit series circuit parallel circuit switch circuit

Answers

Answer 1

Answer: A.) When you turn on the light switch in a room, you have completed the "Open Circuit"

Hope this helps!

Answer 2

Answer: open circuit...by flipping on the switch you close the circuit and allow electrons to flow to the light bulb

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What are examples of devices that use electromagnetic waves

Answers

Radio waves, microwaves, visible light and X Rays.

Which phrase best describes wave motion

Answers

Hi!
I don't know your options, but i can describe the wave motion for you:

wave motion is energy transfer through space that proceeds in regular variations (such as vibration),- we say that it's an oscillation because of the regular variations. These variations have specific characteristics, such as frequency or length.

Ruff, the 50 cm tall Labrador Retriever stands 3 m from a plane mirror and looks at his image. What is Ruff’s image position and height?

Answers

Since the mirror is plane, the image will be formed behind the mirror. The distance will be the same as that of the distance of the object from the mirror and the height will just be the same.
So, Ruff's image will be 3 m behind the mirror and 50 cm tall.

Which is 20 miles per hour north an example of?A.acceleration
B.Direction
C.Speed
D.Velocity

Answers

D. Velocity because it describes a speed and direction

D. Velocity
This is because velocity is the speed of something in a specific way.

The momentum of a bald eagle in flight is calculated to be 345. The mass of the eagle is 5.0 kg. What is the magnitude of the velocity of the eagle?

Answers

Answer : v = 69 m/s.

Explanation :

It is given that,

The momentum of a bald eagle in flight, $p = 345\ Kgm/s$

Mass of the eagle, m = 5 kg

We know that the momentum of any object is defined as the product of mass and the velocity with which it is moving.

$p=mv$

$v=(p)/(m)$

$v=(345\ kgm/s)/(5\ kg)$

$v=69\ m/s$

The velocity of the eagle is 69 m/s.

Hence, this is the required solution.

The formula to find the magnitude of velocity is:

▲v= ▲M/m

▲v=Velocity Change
▲M=Momentum Change
m=Mass

Plug in the information;

▲v=345/5

The answer is 69

Two cars collide at an intersection. Car A, with a mass of 1900 kg, is going from west to east, while car B, of mass 1500 kg, is going from north to south at 17.0 m\s. As a result of this collision, the two cars become enmeshed and move as one afterwards. In your role as an expert witness, you inspect the scene and determine that, after the collision, the enmeshed cars moved at an angle of 60.0degrees south of east from the point of impact.Part A WAS: How fast were the enmeshed cars moving just after the collision? I got 8.66 for velocity in part a which was CORRECT but i can't figure out PART B??...Part B:How fast was car A going just before the collision

Answers

Part A: The enmeshed cars were moving at a velocity of approximately 8.66 m/s just after the collision.

Part B: Car A was traveling at a velocity of approximately 8.55 m/s just before the collision.

How to compute the above velocities

To find the speed of car A just before the collision in Part B, you can use the principle of conservation of momentum.

The total momentum of the system before the collision should equal the total momentum after the collision. You already know the total momentum after the collision from Part A, and now you want to find the velocity of car A just before the collision.

Let's denote:

- v_A as the initial velocity of car A before the collision.

- v_B as the initial velocity of car B before the collision.

In Part A, you found that the enmeshed cars were moving at a velocity of 8.66 m/s at an angle of 60 degrees south of east. You can split this velocity into its eastward and southward components. The eastward component of this velocity is:

v_east = 8.66 m/s * cos(60 degrees)

Now, you can use the conservation of momentum to set up an equation:

Total initial momentum = Total final momentum

(mass_A * v_A) + (mass_B * v_B) = (mass_A + mass_B) * 8.66 m/s (the final velocity you found in Part A)

Plug in the known values:

(1900 kg * v_A) + (1500 kg * v_B) = (1900 kg + 1500 kg) * 8.66 m/s

Now, you can solve for v_A:

(1900 kg * v_A) + (1500 kg * v_B) = 3400 kg * 8.66 m/s

1900 kg * v_A = 3400 kg * 8.66 m/s - 1500 kg * v_B

v_A = (3400 kg * 8.66 m/s - 1500 kg * v_B) / 1900 kg

Now, plug in the values from Part A to find v_A:

v_A = (3400 kg * 8.66 m/s - 1500 kg * 8.66 m/s) / 1900 kg