Which factor has the greatest effect on the melting point of a crystalline solid

Answers

Answer 1
Answer:

The answer is: the type of bonding among the particles.

For example, calcium oxide (CaO) has ionic bonds between calcium cations (Ca²⁺) and oxygen anions (O²⁻).

Because it has strong ionic bonds, it has high melting point (around 2600°C).

Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).

Amount of energy required to change 1 gram of material from the solid to the liquid state at its melting point

Answer 2
Answer: Inter-molecular forces. The greater the attraction between particles the more energy required to break the forces or "melt" them.

Please mark as brainliest if satisfied with answer.

Related Questions

What's the purpose of the battery in a circuit
The atomic mass of an element is calculated using the(1) atomic number and the ratios of its naturally occurring isotopes(2) atomic number and the half-lives of each of its isotopes(3) masses and the ratios of its naturally occurring isotopes(4) masses and the half-lives of each of its isotopes
What type of reaction takes place when the melting of a solid occurs?
Why is the reaction of Iron and hydrochloric acid slow ​
Which of these scenarios involve a reaction that is at equilibrium? a. the reaction is producing reactants and products at an equal rate. b. the reaction is producing more reactants than products. c. the reaction is only producing products d. the reaction is producing more products than reactants.

What is the total number of grams of NaI(s)needed to make 1.0 liter of a 0.010 M solution?
(1) 0.015 (3) 1.5
(2) 0.15 (4) 15

Answers

You have to multiply. That is molecules x ram = 0.01 * 150 = 1.5So your answer is 3) 1.5.

Write a nuclear equation for the fusion of two h−2 atoms to form he−3 and one neutron.

Answers

'Heavy' hydrogen (the isotope deuterium) , 2/1H is involved ,

[2= mass number, 1= atomic (proton) number]

2/1H + 2/1H → 3/2He + 1/0n

Calculate the number of moles 3.15 g of HNO3 19.3 g of NaCl 21.25 g of NaNO3

Answers

The number of moles:
3.15g of HNO_(3)
1 mole of HNO_(3)- 63g.
x moles of HNO_(3)- 3.15g
x=(1\ mole*3.15g)/(63g)=(3.15)/(63)=0.05\ mole

The number of moles:
19.3 g of NaCl
1 mole of NaCl- 58.44g.
x moles of NaCl- 19.3g.
x=(1\ mole*19.3g)/(58.44g)=(19.3)/(58.44)=0.33\ mole

The number of moles:
21.25 g of NaNO_(3)
1 mole of NaNO_(3)- 85g.
x moles of NaNO_(3)- 21.25g.
x=(1\ mole*21.25g)/(85g)=(21.25)/(85)=0.25\ mole

Greetings, 
n00nst00p :)

What is presipitation?

Answers

Precipitation is the prcross by which rain, sleet, snow, etc, is released from the clouds.

Magma from Earth's interior oozes from the cracks at mid-ocean ridges.
a. True
b. False

Answers

The answer is A. True

Magma from Earth's interior oozes from the cracks at mid-ocean ridges.

true is the right one

The volume of a gas decreases from 15.7 m3 to 11.2 m3 while the pressure changes from 1.12 atm to 1.67 atm. If the initial temperature is 245 K, what is the final temperature of the gas

Answers

The final temperature of the gas is 260.01 K.

 The final temperature can be calculated by using the equation as follows:-

(P_(1)V_(1) )/(T_(1)) =(P_(2)V_(2) )/(T_(2))........(1)

Here, P_1 and P_2  is the pressure of this gas before and after the changes.

V_1  and V_2 is volume of this gas before and after the changes.

T_1 and T_2 is the temperature (in degrees Kelvins) of this gas before and after the changes.

Given values:-

P_1=1.12\ atm, P_2=1.67\ atm\n\nV_1=15.7\ m^(3) , V_2=11.2\ m^(3)\n\nT_1=245\ K.T_2=?

Substitute all the values in the equation (1) as follows:-

(1.12\ atm*15.7\ m^(3))/(245\ K ) =(1.67\ atm*11.2\ m^(3))/(T_2 )\nT_2=(1.67\ atm*11.2\ m^(3)*245\K)/(1.12\ atm*15.7\ m^(3) )\n=260.60\ K

Hence, the final temperature of the gas is 260.60 K.

To know more about:-

brainly.com/question/23967621

   

Explanation:

The data is given as follows.

P_(1) = 1.12 atm,              P_(2) = 1.67 atm

V_(1) = 15.7 m^(3),           V_(2) = 11.2 m^(3)

T_(1) = 245 K,                  T_(2) = ?

Therefore, calculate the final temperature using the relation as follows.

    (P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))

    (1.12 atm * 15.7 m^(3))/(245) = (1.67 atm * 11.2 m^(3))/(T_(2))

 T_(2) = (1.67 atm * 11.2 m^(3) * 245 K)/(1.12 atm * 15.7 m^(3))

                  = (4582.48 K)/(17.584)

                  = 260.605 K

                  = 260.61 K (approx)

Thus, we can conclude that final temperature is 260.61 K.