A traditional western pack of playing cards consists of four suits. Each suit has 13cards. Find the fraction of the playing cards are:a)red. B)diamonds
c)face cards. D)black and face cards

Answers

Answer 1
Answer:

a) 1/2, b) 1/4, c) 3/13, d) 7/26 (fraction of black and face cards) in a traditional Western pack of playing cards.

A traditional Western pack of playing cards consists of four suits: Hearts (colored red), Diamonds (colored red), Spades (colored black), and Clubs (colored black). Each suit has 13 cards: Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, and King.

a) To find the fraction of the playing cards that are red, we need to add up the number of red cards and divide by the total number of cards in the deck. There are two red suits, Hearts and Diamonds, and each has 13 cards. So there are 26 red cards in total. Since there are 52 cards in a deck, the fraction of red cards is 26/52 or 1/2.

b) To find the fraction of cards that are Diamonds, we simply divide the number of Diamonds (13) by the total number of cards (52). This gives us a fraction of 13/52 or 1/4.

c) To find the fraction of face cards, we need to add up the number of face cards and divide by the total number of cards in the deck. In each suit, there are three face cards: King, Queen, and Jack. So there are 12 face cards in each deck (4 suits x 3 face cards per suit). Therefore, there are 12/52 or 3/13 face cards in the deck.

d) To find the fraction of black and face cards, we need to count the number of black cards and the number of face cards that are also black. There are two black suits, Spades and Clubs, and each has 13 cards. So there are total 26 black cards. Of these 26 cards, there are 12 face cards (King, Queen, and Jack) which are not black, leaving 14 black cards which are face cards. Therefore, the fraction of black and face cards is 14/52 or 7/26.

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Solve for x. 10x^2=29x-21 does anyone know this

Answers

10x^2=29x-21 \n 10x^2-29x+21=0\n \Delta=(-29)^2-4\cdot10\cdot21=841-840=1\n √(\Delta)=\sqrt1=1\n x_1=(-(-29)-1)/(2\cdot10)=(28)/(20)=(7)/(5)\n x_2=(-(-29)+1)/(2\cdot10)=(30)/(20)=(3)/(2)\n

For each value of kk specified in parts (a)–(e), plot the set of points in the plane that satisfy the equationx2 / k − y2 = 1.
a. k = −1
b. k = 1
c. k = 2
d. k = 4
e. k = 10
f. k = 25
g. Describe what happens to the graph of
x2 / k − y2 = 1 as k → [infinity].

Answers

Answer:

Seee answer below.

Step-by-step explanation:

a. k = −1

If K=-1 the equation gets this form:

(x^2/-1) -y^2=1

There aren't natural numbers that being negative, adding them, we get 1 as result. So there is no graph for this equation.

b. k = 1

(x^2/1) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

c. k = 2

(x^2/2) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

d. k = 4

(x^2/4) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

e. k = 10

(x^2/10) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

f. k = 25

(x^2/25) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

g. Describe what happens to the graph of

x2 / k − y2 = 1 as k → [infinity].

As K is increasing the value of X will be tending to 0. So the equation for this will be:

− y^2 = 1.The solution for this is in the domain of the imaginary numbers.

Help help help help help

Answers

area=108 in. squared

12/2 gives you the radius (6)

6 squared is 36

36 times 3 is 108

5/3x=10 solve equation

Answers

if yo meant 5/(3x)=10 go to A
if you ment (5/3)x=10 go to B


A
times 3x both sides
5=30x
divide both sides by 30
5/30=x
1/6=x

B
if yo meant
(5/3)x=10 then
times 3/5 both sides
x=30/5
x=6



if 5/(3x)=10, x=1/6
if (5/3)x=10, x=6

Which expression has a value of 15 when n = 7?1: 43 minus 5 n
2: 3 n minus 5
3: 6 n minus 28
4: 19 minus StartFraction 28 Over n EndFraction

Answers

Answer:

19-(28)/(n) is the expression with the value of 15 when n = 7

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

43-5n

Substitute the value of n & simplify,

43-5(7)

43-35=8

Since the value of the expression is 8 which is not equal 15.

Hence expression 43-5n does not have value of 15 when n = 7.

Expression 2:

3n-5

Substituting the value of n & simplify,

3(7)-5

21-5=16

Since the value of the expression is 16 which is not equal 15.

Hence expression 3n-5 does not have value of 15 when n = 7.

Expression 3:

6n-28

Substituting the value of n & simplify,

6(7)-28

42-28=14

Since the value of the expression is 14 which is not equal 15.

Hence expression 6n-28 does not have value of 15 when n = 7.

Expression 4:

19-(28)/(n)

Substituting the value of n & simplify,

19-(28)/(7)

19-4=15

Since the value of the expression is 15 which is equal 15.

Hence expression 19-(28)/(n)has the value of 15 when n = 7.

Benito spent $1837 to operate his car last year. Some of these expenses are listed below. Benito's only other expense was for gasoline. If he drove 7600 miles, what was the average cost of the gasoline per mile?

Answers

Operating Expenses
Cost Insurance $972
Registration $114
Maintenance $105

1837 - 972 - 114 - 105 = 646 cost of gasoline

646 / 7600 = 0.085 or 8.5 centavos

Answer:

8.5 Cent

Step-by-step explanation:

Benito’s only other expense was for gasoline. If he drove 7600 miles, what was the average cost of the gasoline per mile?

a.

7.5¢

b.

5.5¢

c.

8.0¢

d.

8.5¢

Operating Expenses  Cost

Insurance  $972

Registration  $114

Maintenance  $105