Mr. Johnson borrowed $8000 for 4 years to make home improvements. Ifhe repaid a total of $10, 320, at what interest rate did he borrow the money?
Answers
Answer:
Mr. Johnson borrowed the money at an interest rate of 4.25%.
Step-by-step explanation:
We can use the formula for simple interest to solve this problem:
Simple Interest = Principal x Rate x Time
Where:
Principal is the amount borrowed.
Rate is the interest rate (as a decimal).
Time is the length of time the money is borrowed for.
We know that Mr. Johnson borrowed $8000 for 4 years and repaid a total of $10,320. We can use this information to set up an equation:
10,320 = 8000 + 8000 x Rate x 4
Simplifying this equation:
10,320 = 8000 + 32000 x Rate
Dividing both sides by 32000:
Rate = (10,320 - 8000) / (8000 x 4) = 0.0425 or 4.25%
Therefore, Mr. Johnson borrowed the money at an interest rate of 4.25%.
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Hope this helps :)
($2.65) / ($0.25/oz) = 10.6 oz
Answer: She bought 10.6 ounces
4
5
6
7
I need help quickly.
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Explanation
Quotient=division
23.564/5.97=3.947
Round answer therefore
3.947=4
Answers
The Distributive property states that
a(b+c)=ab+ac
Now, let's simplify:
6(3a-4)
18a-24
Answer:
first you multiply 6 and 3a which equals 18a. Then you multiply 6 and 4 which equals 24. So in the end it should look like: 18a-24
Answers
Answer:
Step-by-step explanation:
Assuming the order in which he answers the questions matter the answer is the number of permutations of 8 in 10.
This is 10! / (10-8)!
= 1,814.400.
If the order does not matter then the answer is the number of combinations of 8 from 10:
This is 10!/8!*2!
= 45.
Answers
Answer:
1/6
Step-by-step explanation:
2/3-1/2 = find the denominator 3×2=6
4/6-3/6 = rewrite with a denominator of 6
(4-3)/6 = 1/6 subtract numerators
Answer:
1/3
Step-by-step explanation:
Exam Image
Subject to
x ≤ 3
y ≤ 9
x + y ≥ 9
x ≥ 0
y ≥ 0
Answers
Answer:
Minimum value of function is 63 occurs at point (3,6).
Step-by-step explanation:
To minimize :
Subject to constraints:
Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line
Eq (2) is in green in figure attached and region satisfying (2) is below the green line
Considering , corresponding coordinates point to draw line are (0,9) and (9,0).
Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line
Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)
Now calculate the value of function to be minimized at each of these points.
at A(0,9)
at B(3,9)
at C(3,6)
Minimum value of function is 63 occurs at point C (3,6).
Applying the method of corners to the linear programming problem yields a minimum value of 6 at the point (3, 0) for the given objective function and constraints.
The linear programming problem involves minimizing an objective function subject to certain constraints. The constraints are given as follows:
Minimize z = 2x + 3y
Subject to:
x ≤ 3
y ≤ 9
x + y ≥ 9
x ≥ 0
y ≥ 0
To find the minimum value, we employ the method of corners. The feasible region is determined by the intersection of the inequalities. The corner points of this region are where the constraints intersect.
Intersection of x ≤ 3 and y ≥ 0 gives the point (3, 0).
Intersection of y ≤ 9 and x ≥ 0 gives the point (0, 9).
Intersection of x + y ≥ 9 and y ≥ 0 gives the point (9, 0).
Now, evaluate the objective function z = 2x + 3y at each corner point:
z1 = 2(3) + 3(0) = 6
z2 = 2(0) + 3(9) = 27
z3 = 2(9) + 3(0) = 18
The minimum value occurs at point (3, 0) with z_min = 6.
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