A solution of Na2CO3 is added dropwise to a solution that contains 1.05×10−2 M Fe2+ and 1.60×10−2 M Cd2+. What concentration of CO32− is need to initiate precipitation? Neglect any volume changes during the addition.

Answers

Answer 1

Answer:

The Ksp of FeCO₃ is 3.45x10-11 and the Ksp of CdCO₃ is 8.7x10-12.

What is Ksp?

Ksp is a mathematical expression used to predict the behavior of a saturated solution. It is an abbreviation of the term “solubility product constant”, and is derived from the thermodynamic equilibrium equation that exists between a solid and its dissolved ions in a solution. Ksp is used to predict the solubility of a given ionic compound, and is a measure of the maximum amount of solute that can be dissolved in a given solvent at a given temperature and pressure.

To initiate precipitation, the concentration of CO²⁻₃ must be greater than or equal to the solubility product of the least soluble salt, which is CdCO₃.
Therefore, the concentration of CO²⁻₃ must be greater than or equal to 8.7x10-12 M.

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Predict whether the compounds are soluble or insoluble in water

Answers

Answer:

The polar compounds are soluble in water while non polar are insoluble in water.

Explanation:

Solvent is the that part of solution which is present in large proportion and have ability to dissolve the solute. In simplest form it is something in which other substance get dissolve. The most widely used solvent is water, other examples are toluene, acetone, ethanol, chloroform etc.

Water is called universal solvent because of high polarity all polar substance are dissolve in it. Hydrogen is less electronegative while oxygen is more electronegative and because of difference in electronegativity hydrogen carry the partial positive charge while oxygen carry partial negative charge.

Water create electrostatic interaction with other polar molecules. The negative end of water attract the positive end of polar molecules and positive end of water attract negative end of polar substance and in this way polar substance get dissolve in it.

Example:

when we stir the sodium chloride into water the cation Na⁺ ions are surrounded by the negative end of water i.e oxygen and anion Cl⁻ is surrounded by the positive end of water i.e hydrogen and in this way all salt is get dissolved.

The chemicals that can dissolve in a certain solvent to create a homogenous mixture known as a solution are said to be soluble chemicals. The compounds that are soluble are: $KNO_3$ , $AgNO_3$ , and $CuBr_2$ .

As per this,

Nitrate ( $NO^{3-$ ) salts are often soluble in water. $KNO_3$ is potassium nitrate.
The majority of nitrate ( $NO^{3-$ ) salts, including silvernitrate, are soluble in water, including $AgNO_3$ .
The majority of bromide ( $Br^-$ ) salts, including copper(II) bromide, are water soluble.

Insoluble:

Lead(II) chloride, or $PbCl_2$ , is an exception and is regarded as being insoluble in water among the chloride ( $Cl^-$ ) salts.
Barium sulphate, also known as BaSO4, is an exception to the rule of most sulphate ( $SO^{4-$ ) compounds being soluble in water.

Thus, these are the classification of the compounds as per their solubility.

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Your question seems incomplete, the prpbable complete question is:

Predict whether the following compounds are soluble or insoluble in water. Soluble Insoluble PbCl2, BaSO4, KNO3, AgNO3, and CuBr2.

How many grams of chloride are there in 256 g of magnesium chloride?

Answers

Given :

Mass of given magnesium chloride, m = 256 g.

To Find :

How many grams of chloride are there in 256 g of magnesium chloride.

Solution :

Molecular formula of magnesium chloride is $MgCl_2$ .

Molecular formula of $MgCl_2$ is, M = 95.211 g/mol .

Mass of chlorine in 1 mol of $MgCl_2$ is , m = 35.5 × 2 = 71 g.

So, amount of chlorine in 256 gram $MgCl_2$ :

$m =(71* 256)/(95.211)\n\nm = 190.90\ g$

Hence, this is the required solution.

3.7500*10^4+9.7100*5

Answers

Answer:

37548.55

Explanation:

3.7500*10^4+9.7100*5

3.7500*10000+9.7100*5

37500+48.55

37548.55

All the elements beyond uranium, the transuranium elements, have been prepared by bombardment and are not naturally occurring elements. The first transuranium element neptunium, NpNp, was prepared by bombarding U−238U−238 with neutrons to form a neptunium atom and a beta particle. Part A Complete the following equation: 10n+23892U→?+?01n+92238U→?+? Express your answer as a nuclear equation.