The blood pressure in veins is __________ the blood pressure in arteries.(A)not comparable to

(B)the same as

(C)higher than

(D)lower than

Answers

Answer 1
Answer: lower than

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Why is gas able to flow? a its particles have melted and can move around b its particles have high viscosity and can move around c its particles have enough energy to move around d its particles have enough pressure to move around 3. which of the following is true about the viscosity of liquids? a liquids with high viscosity do not flow as well as liquids with low viscosity b liquids with high viscosity flow better than liquids with low viscosity c liquids with high viscosity do not resist flow any more than liquids with low viscosity d water is a good example of a liquid with high viscosity 4.in a(n_____, the particles form a regular, repeating pattern please help!?

Answers

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The process by which a gas changes to a solid is

Answers

The correct answer to the question is - Deposition i.e the process by which a gas changes to a solid is called deposition.

EXPLANATION:

There are various thermal processes of state or phase change in which matter in one state is converted into matter in another state.

Deposition is the type of thermodynamic process of state or phase change in which a gaseous substance is directly converted into corresponding solid substance without entering into liquid phase.

During this process, the loss of thermal energy from gas is very fast. Hence, the gas directly enters solid phase without undergoing into liquid phase.

This process is just the opposite process of sublimation where a solid is converted into gas directly. That's why this process is also known as desublimation.

For instance, conversion of water vapor into ice.

That process is called deposition.

Given: Q1 = 3.0 × 10-5 CQ2 = 4.0 × 10-5 C
K = 9.00 × 109 N ×
r = 3.0 m, determine F.

_____ N

Answers

The force is obtained from the charges Q₁ = 3×10⁻⁵ C and Q₂ = 4×10⁻⁵ C and distance r = 3 m is 1.2 N.

What is Coloumb's law?

Coloumb's law is defined as the force of attraction and repulsion between two charges is directly proportional to the product of charges and inversely proportional to the square of the distance between them.

The attractive and repulsive force, F∝ (q₁×q₂) / r². It is also known as F = k (q₁×q₂) / r², where k is the proportional constant. The unit of force is newton N.

From the given,

Q₁ = 3×10⁻⁵ C

Q₂ =  4×10⁻⁵ C

r = 3m

k = 9×10⁹ Nm²C⁻²

The attractive and repulsive force,

F = k (q₁×q₂) / r²

  = (9×10⁹× 3×10⁻⁵×4×10⁻⁵) / (3)²

 = 12×10⁻¹

= 1.2 N

Force = 1.2 N

Thus, the force of repulsion and attraction of given charges is 1.2 N.

To know more about Coloumb's law:

brainly.com/question/21083799

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F=KQ1Q2/R2
F=9 x 10^9 x 3 x 10^-5 x 4 x 10^-5 / 9
F=12 x 10^-1
F=1.2 N