How many Atoms are in 2.3 g of Na? show your work and these question will take two steps

Answers

Answer 1

Answer: Use stoichiometry and convert 2.3 grams of sodium to moles. Then convert the moles to atoms using 6.02(10)^23.

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How many moles of I2 are in 8.23 moles of NaI ?

Answers

Answer: 4.12

Explanation:

we know that the given mol is 8.23 mol and they are 2NaI and I2 so we will write the equation like this.

8.23mol NaI x 1mol of I2 ÷ 2molNaI = 4.115≅ 4.12 mol of I2

we placed NaI at the bottom to cancel out with the 8.23 mol of NaI

The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) 40.4 80.8 -126 67.5 20.2

Answers

The amount of heat that is released by the chemical reaction of 25.0 g of $Na_(2)O_2$ with water is -20.223 Joules.

Given the following data:

Mass of $Na_(2)O_2$ = 25.0 grams

Enthalpy of combustion = -126 kJ/mol

To find the amount of heat that is released by the chemical reaction of 25.0 g of $Na_(2)O_2$ with water:

First of all, we would determine the number of moles of $Na_(2)O_2$ in this chemical reaction:

$2Na_2O_2_((s)) + 2H_2O_((l))$ ------> $4NaOH_((s)) + O_2_((g))$

$Number\;of\;moles \;(Na_(2)O_2)= (Mass\; of\;Na_(2)O_2)/(Molar\;mass\;of\;Na_(2)O_2)$

Substituting the values into the formula, we have;

$Number\;of\;moles \;(Na_(2)O_2)= (25.0)/(77.98)$

Number of moles ( $Na_(2)O_2$ ) = 0.321 moles.

Now, we can find the quantity of heat released when $Na_(2)O_2$ reacts with water:

2 mole of $Na_(2)O_2$ = -126 kJ/mol

0.321 mole of $Na_(2)O_2$ = X kJ/mol

Cross-multiplying, we have:

$2X = 0.321$ × $(-126)$

$2X = -40.446\n\nX = (-40.446)/(2)$

X = -20.223 Joules.

Answer : The amount of heat released by the reaction is, 20.2 kJ

Explanation :

First we have to calculate the number of moles of $Na_2O_2$ .

$\text{Moles of }Na_2O_2=\frac{\text{Mass of }Na_2O_2}{\text{Molar mass of }Na_2O_2}$

Molar mass of $Na_2O_2$ = 77.98 g/mole

$\text{Moles of }Na_2O_2=(25.0g)/(77.98g/mole)=0.320mole$

Now we have to calculate the heat released during the reaction.

The balanced chemical reaction is:

$2Na_2O_2(s)+2H_2O(l)\rightarrow 4NaOH(s)+O_2(g)$

From the reaction we conclude that,

As, 2 moles of $Na_2O_2$ releases heat = 126 kJ

So, 0.320 moles of $Na_2O_2$ releases heat = $(0.320)/(2)* 126=20.2kJ$

Therefore, the amount of heat released by the reaction is, 20.2 kJ

What are the three particles of an atom?

Answers

The three particles found in an atom are the protons, neutrons and electrons. Protons have a positive charge. Electrons have negative charge. Lastly, neutrons have no net electrical charge. Protons and neutrons are much heavier than electrons and are located in the center of the atom.

What is the hydronium ion concentration of a solution whose pH is 12.40?

Answers

Hydronium ion concentration = 3.98×10-13

Which is defined as moles of solute per liter of solution?a. Molarity
b. Formality
c. Density
d. Molality
e. Normality

Answers

A. Molarity . Explaining about Moles

The answer is A. Molarity

How many moles are in 22 grams of argon

Answers

Explanation:

It is known that number of moles equal mass divided by molar mass.

Mathematically, Number of moles = $(mass given)/(molar mass)$

Since, it is given that mass is 22 grams and molar mass of argon is 40 g/mol.

Therefore, Number of moles = $(mass given)/(molar mass)$

= $(22 g)/(40 g/mol)$

= 0.55 mol

Thus, we can conclude that there are 0.55 moles in 22 grams of argon.

number of moles are the amount of substance of an element .
number of moles can be calculated as follows;
number of moles = mass present / molar mass of element
molar mass of Ar - 40 g/mol
number of moles of Ar = 22 g / 40 g/mol = 0.55 mol .
there are 0.55 mol of Ar

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