Very Important!! Electron lender or borrower?i need to know if these elements lend or borrow electrons and how many do they lend or borrow.
-sodium
-phosphorus
-potassium
-oxygen
-iodine
-cesium
-bromine
-sulfur
-magnesium
Please answer!! Its really important..

Answers

Answer 1

Answer:

Answer : Lending makes the element as cation (positively charged species) and borrowing makes the element as anion (negatively charged species).

Usually all the metal species donates the electrons and non-metals accepts (borrows) the electrons.

Sodium (Na) donates 1 electron and becomes $Na^(+)$ .

Phosphorus (P) accepts 3 electrons and becomes an anion of phosphorus $P^(-3)$ .

Potassium (K) donates its one electron and gets converted to $K^(+)$ .

Oxygen (O) accepts 2 electrons and turns as $O^(-2)$ .

Iodine (I) accepts one electron and gets converted into $I^(-)$ .

Cesium (Cs) donates 1 electron and turns to $Cs^(+)$ .

Bromine (Br) accepts 1 electron and turns as $Br^(-)$ .

Sulfur (S) accepts 2 electrons and becomes $S^(-2)$ .

Magnesium (Mg) donates its 2 electrons and gets converted as $Mn^(+2)$ .

Answer 2

Answer: Sodium lends 1 electron.
Phosphorus borrows 3 electrons.
Potassium lends one electron.
Oxygen borrows 2 electrons.
Iodine borrows one electron.
Cesium lends 1 electron.
Bromine borrows 1 electron.
Sulfur borrows 2 electrons.
And magnesium lends 2 electrons.

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Would the concentration of hydroxide ion in a 0.30 m solution of potassium hydroxide (koh) be greater than, less than, or equal to 0.30 m?

Answers

Potassium hydroxide KOH is a strong base which can completely ionize to form potassium and hydroxide ions.

The equation representing ionization of KOH,

$KOH(aq)-->K^(+)(aq)+OH^(-)(aq)$

The mole ratio of hydroxide to KOH from the above equation is $(1molOH^(-) )/(1molKOH)$

The given concentration of KOH solution=0.30M

Calculating the concentration of hydroxide ions present in 0.30M KOH solution:

$(0.30mol KOH)/(L) *(1mol OH^(-) )/(1 mol KOH) =0.30(mol)/(L)OH^(-)$

Therefore the concentration of hydroxide ion will be equal to 0.30 M in a 0.30 M KOH solution.

Final answer:

The concentration of hydroxide ion in a 0.30 m solution of potassium hydroxide would be equal to 0.30M. Potassium hydroxide is a strong base, it completely dissociates in water producing an equal concentration of hydroxide ions. In a basic solution where the concentration of Hydroxide ions is high, the concentration of hydronium ions will be low.

Explanation:

The concentration of hydroxide ion in a 0.30 m solution of potassium hydroxide (KOH) would be equal to 0.30 M. This is based on the fact that potassium hydroxide is a strong base and it completely dissociates in water, which means one KOH molecule produces one hydroxide ion. Therefore, the concentration of the hydroxide ion [OH-] in the final solution would be equal to the initial concentration of the potassium hydroxide.

This is different from the behavior of weak acids and bases which do not completely dissociate in water, leading to a lower concentration of hydronium (H3O+) or hydroxide (OH-) ions compared to the initial concentration of the acid or base.

However, it's important to note that in solutions with a high concentration of hydronium ions, the concentration of hydroxide ions will decrease according to Le Chatelier's principle, which describes how equilibrium adjusts when it's disturbed. Conversely, in a basic solution—like this 0.30 M KOH solution—where the concentration of hydroxide ions is high, the concentration of hydronium ions will be comparatively low.

Learn more about Ionic Dissociation here:

brainly.com/question/29125502

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Answers

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Answers

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Answer:

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U welcome

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Answers

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