What is 8 1/3 divided by 5

Answers

Answer 1
Answer: Well if you did it correct you should get this : 
Answer:
= 8/5
(simplified) ---->
= 1  3/5
Answer 2
Answer: 8 1/3 divided by 5 is 1 2/3

8 1/3 / 5
First, you turn 8 1/3 into a mixed number.
25/3 / 5
Next, you do the reciprocal for the second number while changing the division sign into a multiplication one. 
25/3 * 1/5
Then cross simplify.
25/3 * 1/5 =
5/3 * 1/1 =
Finally you multiply straight across and simplify.
5/3 * 1/1 = 5/3 = 1 2/3

Hoped this helped! 

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A piece of wood has a width of 5 cm and a height of 10 cm. Its volume is 100 cm3. What is the length of the wood?

How do you find a like term for 25ab

Answers

When you're combining 'like terms', look for all the terms that end with 'ab'.
Then add all the numbers that have 'ab' after them.

Cody is designing a pattern for a wood floor the length of the pieces of wood are 1 1/2 inches 1 13/16 inches and 2 1/8 inches what is the length of the fifth piece of wood if the pattern continues

Answers

The length of the fifth piece is 2 3/4 inches.

Given:
1st piece of wood = 1 1/2 inches
2nd piece of wood = 1 13/16 inches
3rd piece of wood = 2 1/8 inches

f(n) = 1st term + common difference(n-1)

To get the common difference, we need to deduct the fraction from its preceding fraction.

1st piece: 1 1/2 = (2*1 + 1)/2 = 3/2
2nd piece: 1 13/16 = (16*1+13)/16 = 29/16
3rd piece: 2 1/8 = (8*2+1)/8 = 17/8

29/16 - 3/2 = 29/16 - (3/2 * 8/8) = 29/16 - 24/16 = (29-24)/16 = 5/16
17/8 - 29/16 = (17/8 *2/2) - 29/16 = 34/16 - 29/16 = (34-29)/16 = 5/16

Find: 5th piece's measurement
1st term : 1 1/2 or 3/2
common difference : 5/16

f(5) = 3/2 + 5/16 (5-1)
      = 3/2 + 5/16 (4)
      = 3/2 + (5*4)/16
      = 3/2 + 20/16
      = (3/2 * 8/8) + 20/16
      = 24/16 + 20/16
      = (24 + 20)/16
f(5) = 44/16
f(5) = 2 12/16 simplified to 2 3/4 inches.

3x1/10 + 4 x 1/100 how do you solve the problem

Answers

The answer to the question

Explain how you know which coins could be used to show o.77 of a dollar

Answers

I Hope This Helps :)

The coins you could use to show 0.77 of a dollar ( or known as 77 cents ) are nickels , dimes , pennies or even quarters .

Example 1 : You could use 7 dimes which is 70 cents , 1 nickel which is 5 cents , then add 2 pennies which will add up to 77 cents .

Example 2 : You could use 2 quarters which is 50 cents , 2 dimes which is 20 cents & 7 pennies .

Example 3 : For the really long way , you could just use 77 pennies which will also give you 77 cents .

Example 4 : You could use 1 quarter , 5 dimes , & 2 pennies .

( Note : you must ALWAYS remember the values of coins when doing mathematical problems that's dealing with money )

A Penny : Is Equal To 1 Cent . ( 100 Pennies Make Up A Whole Dollar , 50 Pennies Make Up 50 Cents etc . )

A Nickel : Is Equal To 5 Cents . ( 2 Nickels Makes Up A Dime Which Is 10 Cents , 10 Nickels Makes Up 50 Cents , 20 Nickels Will Make Up A Dollar . )

A Dime : Is Equal To 10 Cents . ( 5 Dimes Is 50 Cents , 10 Dimes Is A Dollar . )

A Quarter : Is Equal To 25 Cents . ( 2 Quarters Is 50 Cents , 4 Quarters Is A Dollar . )

Mrs Larnell is making a snack packs for a a class picnic. She puts 1/4 pound of apples,1/8 pound of nut mix, and 1/16 pound of chocolate in each of the students packs. There are 24 students in the class.What is the total weight of the snack packs? Is there more than one way to solve this problem?

Answers

Answer=10 1/2 pounds

One pack has 1/4+1/8+1/16 pounds of snacks....

Lets starts off giving our fractions of 1/4, 1/8 and 1/16 a common denominator of 16.

1/4=4/16
1/8=2/16
1/16=1/16

So...

x=4/16+2/16+1/16
x=7/16

So... One pack has 7/16lbs of snacks in it

Multiply 7/16lbs by the total number of students(24)..

7/16*24=10 1/2 pounds
________________________________________________________
another way of solving this problem could be...

1/4*24=6
1/8*24=3
1/16*24=1.5

6+3+1.5=10.5 pounds

If y is 12 when x is 5, find x when y is 30

Answers


We have no idea how 'x' responds to changes in 'y'.
We don't even know their units, to make a guess with.

-- If 'x' and 'y' are the ages of two people, then when y = 30, 'x' will be  23.

-- If they are the frequency and wavelength of a wave on the lake,
then when y = 30, 'x' will be  2 .

-- If 'x' is the weight of a rock in your front yard and 'y' is the number of pages
in today's newspaper, then 'y' has no effect on 'x'.  No matter what happens
to 'y' . . . 'x' will always be  5 .

With the information given in the question, we just don't know.

We need either an equation, or else one more example.