Find the distance between the points 6 + 5i and 1 – 2i.

Answers

Answer 1

Answer:

For edgeunity students it’s approximately 8.6

Answer 2

Answer: This didnt get answered so Ill answer it. Its simple.

The distance between 6 and 1 is going to be 5. (or in some cases, -5)

The distance between +5i and -2i is going to be 7i (or in some cases, -7i)

So depending on how the problem defines the distance, it is either 5 + 7i or -5 - 7i

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The area of a rectangle is 77 yd2, and the length of the rectangle is 3 yd more than twice the width find the dimensions of the rectangle

Answers

Let the width be x.

Length is 3 more than twice the width = 2x + 3

Area = x*(2x + 3)

x*(2x + 3) = 77

2x² + 3x = 77

2x² + 3x - 77 = 0 This is a quadratic equation. Solve by factorization.

Multiply first and last coefficients: 2*-77 = -154

We look for two numbers that multiply to give -154, and add to give the middle coefficient +3

Those two numbers are 14 and -11.

Check: 14*-11 = -154 14 + -11 = 14 - 11 = +3

We replace the middle term of +3x in the quadratic expression with 14x -11x

2x² + 3x - 77 = 0

2x² + 14x -11x - 77 = 0

2x(x + 7) - 11(x + 7) = 0

(2x - 11)(x + 7) = 0

2x - 11 = 0 or x + 7 = 0

2x = 0 + 11 x = 0 - 7

2x = 11 x = -7

x = 11/2 = 5.5

The solutions are x = -7 or 5.5.

Since we are solving for length of rectangle, x can't be negative. So we do away with x = -7.

x = 5.5 is the only valid solution.

Recall width = x = 5.5,
Length = 2x + 3 = 2*5.5 + 3 = 11 + 3 = 14

Therefore length = 14 yards, and width = 5.5 yards.

One day a store sold 30 sweatshirts. White ones cost $11.95 and yellow ones cost$11.50. In all, $349.95 worth of sweatshirts were sold. How many of each color were sold?

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With this, I would use a guess and check method.
Start by splitting them half.
$11.95x15 sweatshirts = $179.25
$11.50x15 sweatshirts = $172.50
Then you add the totals to see how close you are.
$197.25+$172.50=$351.75
That's a little high. so we'll shift the amount of sweatshirts.
$11.95x14 sweatshirts= $167.30
$11.50x16 sweatshirts= $184.00
And add the totals again.
$167.30+184.00= $351.30
Closer, but too high still, so we'll shift it more in the direction we're going.
$11.95x11 sweatshirts = $131.45
$11.50x 19 sweatshirts = $218.50
Once again, add the totals to check if it matches.
$131.45+$218.50= $349.95
Therefore, 11 white sweatshirts and 19 yellow sweatshirts were sold.

Michael buys a ticket in the Tri-State Pick 3 lottery every day, always betting on 812. He will win something if the winning number contains 8, 1, and 2 in any order. Each day, Michael has probability 0.006 of winning, and he wins (or not) independently of other days because a new drawing is held each day. What is the probability that Michael’s first winning ticket comes on the 10th day?

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Answer:

0.00568 ANS

Step-by-step explanation:

Since Michael has a .006 chance of winning on any given day,

Than his tries of not winning on any day are as:

1-.006=.994.

For Michael first winning ticket would be on 10 day, Michael should not win on the first 9 days, so then he has to win on the 10 day. For Michael not to succeed on the first 9 days, the probability is:

.994^9=0.94727801832

Hence for him to succeed on the 10 day, the probability is .006.

Now the probability of his first winning ticket being on the 10 day is:

.006*.994^9.=0.0056836681.

Susan has a collection of nickels and dimes. If the number of nickels is times the number of dimes, how many nickels and how many dimes does she have?

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there’s no context to your question, it could be any number. try reworking your question.

Moso bamboo can grow 90 cm per day. a Lombardy poplar can grow up to 1 cm per day. A botanical garden has a 5.5 m tall Lombardy poplar and a 0.3 m tall Moso bamboo. If each plant grows at its maximum rate, which plant will be the tallest at the end of the week?

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Srry just needed points

The formula to find the area of the walls of a rectangular room is A=2h (l+b), h is wall height, l is room length, and b is room breadth. The area of doors and windows are ignored.Question - Using the formula find the wall area if the room length is 8m, breadth is 6m and height is 2.5 m.
Sorry but I have NO clue :(

Answers

Problems are very often written in a confusing way. This one couldn't possibly have been
written any more clearly. Sooner or later, you have to stop telling yourself that you have
no clue, settle down, and carefully read the words that are right there on the page.

I'll tell you one more detail that's not in the problem: "breadth" means "width".

Now. The problem clearly tells you all of these things, in this exact order:

=> Area of the walls = (2 x height) x (length + width)

=> length = 8m
=> width = 6m
=> height = 2.5m

Is there a reason you can't take the numbers for length, width, and height,
and write them in the formula for the area ? Do I have to do all the work ?

Area = (2 x height) x (length + width)

Area = (2 x 2.5m ) x ( 8m + 6m )

Do the arithmetic inside the parentheses:

Area = ( 5m ) x ( 14m )

Do the multiplication:

Area = 70 m² .

You will never see a problem that comes any closer to answering itself for you.

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