(x^2 - x^(1/2))/(1-x^(1/2))

Answers

Answer 1
Answer: \frac { \left( { x }^( 2 )-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\n \n =\frac { \left( { x }^( 2 )-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\n \n =\frac { \left( { x }^( 2 )-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\n \n =\frac { { x }^( 2 )+{ x }^( 2 )\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\n \n =\frac { -\sqrt { x } \left( 1-{ x }^( 2 ) \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\n \n =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\n \n =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\n \n =-\sqrt { x } \left( 1+x \right) -x\n \n =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\n \n =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\n \n =-\sqrt { x } -\sqrt { { x }^( 3 ) } -x
Answer 2
Answer: x² - x^(1/2) = x²
1 - x^(1/2)

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How many miles from ft Lauderdale to Haiti

Answers


Ft. Lauderdale is a city that stretches several miles, and Haiti
is a whole country, that's many miles wide and many miles high. 

In order to nail down a reliable answer, you'd really need to specify
one point in Ft. Lauderdale and one point in Haiti.

If you start at the northwest end of Runway-13 at Ft. Lauderdale
Executive Airport, and take the shortest possible route to the east
end of Runway-28 at the Aeroport International de Port au Prince
at Haiti's capital city, you'd have to travel 727.57 miles.

But if you start in Ft. Lauderdale at the intersection of Griffin Rd
and Ravenswood Rd, and take the shortest possible route to the
Dispensaire de Bord-de-Mer hospital on Haiti's north coast, you'd
only have to travel 613.63 miles.

You really need to say WHERE in Ft. Lauderdale and WHERE in Haiti.
♥ Based upon research I found that 
♥ From Ft. Lauderale to Haiti is exactly 703 miles 

Bob, driving a new Ford, travels 330 miles in the same amount of time it takes John, driving an old Chevy and traveling 10 miles per hour faster, to travel 390 miles. How fast is Bob driving?

Answers

Answer:

  55 mph

Step-by-step explanation:

Let x represent Bob's speed. Then John's speed is x+10, and their respective times are found by ...

  time = distance/speed

  330/x = 390/(x+10) . . . . . . . the times are the same

  330(x +10) = 390x . . . . . . .  multiply by x(x+10)

  3300 = 60x . . . . . . . . . . . . . subtract 330x

  55 = x . . . . . . . . . . . . . . . . . . divide by the coefficient of x

Bob is driving at 55 miles per hour.

The hypotenuse of a right triangle is 7 inches, and one of the legs is square root 13 inches. Find the length of the other leg.A)  6 inches
B)    square root 62 inches
C)     square root 128 inches

Answers

The answer is A) 6 inches.
First I punch square root 13 in the calculator and got 3.6055... then I square the number since the formula has square root on it and got 13. Now the equation look something like this: 13 + b^2 = 49. 49 because 7^2 is 49. Then i subtract 49 by 13 and got 36. Now the equation look like this: b^2 = 36. After I square both side, I get b=6 in. 

What are the possible number of positive, negative, and complex zeros of f(x) = x6 – x5– x4 + 4x3 – 12x2 + 12 ?

Answers

This is a polynomial with more than 2 as a degree. Using Descartes Rule of Signs: 
f(x) = x⁶ + x⁵ + x⁴ + 4x³ − 12x² + 12 
Signs: + + + + − + 2 sign changes ----> 2 or 0 positive roots 
f(−x) = (−x)⁶ + (−x)⁵ + (−x)⁴ + 4(−x)³ − 12(−x)² + 12 f(−x) = x⁶ − x⁵ + x⁴ − 4x³ − 12x² + 12 
Signs: + − + − − + 4 sign changes ----> 4 or 2 or 0 negative roots 
Complex roots = 0, 2, 4, or 6 

Descarte's Rule of Sign is useful for finding the zeroes of a polynomial. The rule will tell you how many roots you can expect and of which type not where the polynomial's zeroes are. This rule is given as follows:

For \ a \ polynomial \ f(x)=a_(n)x^n+a_(n-1)x^(n-1)+ \ldots a_(2)x^2+a_(1)x+a_(0) \n \n with \ real \ coefficients \ and \ a_(0) \neq 0


\bullet \ The \ number \ of \ \mathbf{positive \ real \ zeros} \ of \ f \ is \ either \ equal \ to \n the \ number \ of \ variations \ in \ sign \ of \ f(x) \ or \ less \ than \ that \n number \ by \ an \ even \ integer. \n \n \bullet \ The \ number \ of \ \mathbf{negative \ real \ zeros} \ of \ f \ is \ either \ equal \ to \n the \ number \ of \ variations \ in \ signs \ of \ f(x) \ or \ less \ than \ that \n number  \ by \ an \ even \ integer.


That is, the function:

f(x)=x^6-x^5-x^4+4x^3-12x^2+12 \n \n \n + \ - \ - \ + \ - \ + \n \n Has \ four \ changes \ in \ sign

4, 2, or 0 positive roots


On the other hand, the function:

f(-x)=(-x)^6-(-x)^5-(-x)^4+4(-x)^3-12(-x)^2+12 \n \n f(-x)=x^6+x^5-x^4-4x^3-12x^2+12 \n \n \n + \ + \ - \ - \ - \ + \n \n Has \ 2 \ changes \ in \ sign

2, or 0 negative roots


Finally:

Complex roots: 0, 2, 4, or 6

I don't understand number 25. Please I need an explanation.

Answers

First plot points J, K, and L randomly on a plane. Then, draw a line connecting J and K. Next, put a point on the line, JK named M. Now draw a ray from M to L connected the two points with an arrow at one end to indicate a ray.

What are the explicit equation and domain for a geometric sequence with a first term of 2 and a second term of −8? an = 2(−8)n − 1; all integers where n ≥ 1 an = 2(−8)n − 1; all integers where n ≥ 0 an = 2(−4)n − 1; all integers where n ≥ 0 an = 2(−4)n − 1; all integers where n ≥ 1

Answers

Hello,

The question is
"What are the explicit equation and domain for a geometric sequence with a first term of 2 and a second term of −8?"

It is a geometric sequence =>U(2)=U(1)*r==>-8=2*r ==>r=-4

U(1)=2=2*(-4)^0
U(2)=-8=2*(-4)=2*(-4)^1
U(3)=32=-8*(-4)=2*(-4)(-4)=2*(-4)^2
U(4)=-128=32*(-4)=2*(-4)^3
...
U(n)=2*(-4)^(n-1) where n>=1.

Answer C