the selling price for a classic speedboat is $1800, which is $1500 less the 2 times its original price. what was the original price
Answers
1800 = 2x - 1500
from this, you need to subtract 1500 from both sides
then, you get:
3300 = 2x
to find x, divide both sides of the equation by two:
1800 = 2x - 1500
--------------------------
2
from this, you get that x = 1650
ANSWER: x = 1650
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I found this question in the Sample Assessment Material of the iGCSE Further Pure Maths.The volume of a right circular cone is increasing at the rate of 45 cm3 s–1. The height of the cone is always three times the radius of the base of the cone. Find the rate of increase of the radius of the base, in cms–1, when the radius of the cone is 4 cm. Give your answer correct to 3 significant figures.
Andrew took 22 minutes to do 13 math problems. Kiley took 24 minutes to do 12 math problems. Which student did more problems per minute?
Whats the y intercept of y= 1/2 log(x+1)-log(2x+10)
Answers
Answer:
A
Step-by-step explanation:
I think it is I'm not sure but I hope it is
Answers
How to solve equation x/3-4=10?
Answers
2x / 5 + 1 = 7
2x + 5 = 5 * 7
2x = 35 - 5
2x = 30
x = 15
If you would like to solve the equation x/3 - 4 = 10, you can do this using the following steps:
x/3 - 4 = 10
x/3 = 10 + 4
x/3 = 14
x = 14 * 3 = 42
Answers
The lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are neither parallel nor perpendicular.
What is an equation?
An equation is slope-interceptthat shows the relationship between two or more numbers and variables.
The first equation y=1/2x-1 is already in the slope intercept form. The slope is, 1/2, and the y-intercept is -1.
The second equation y+4=-1/2(x-2)
From this equation, the slope is -1/2 and the y-ina tercept is -3.
When two lines ara e parallel, they have the same slope. one has slope of 1/2 and the other has slope of -1/2 thus these are not the same our lines are not parallel.
When lines are perpendicular, the slope of one is the negative reciprocal of the other which is not satisfied in the given equations.
Thus, we conclude that the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are neither parallel nor perpendicular.
Learn more about equations here;
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The first equation,
The second equation requires rearranging.
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.
When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.
When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.
Thus, we conclude that the lines are neither parallel nor perpendicular.
B.12 = 9 + 3x
C.6 + 30 = 62
D.ax – by = k
Answers
ANSWER
is an example of literal equation.
EXPLANATION
A literal equation is an equation in which letters or variables are used to represent real values.
A literal equation consists of at least two letters or variables.
The first option consists of two variables but it is not an equation. It is just an expression.
The second option is not a literal equation because it consists of only one variable. This is just a linear equation in one variable. But a literal equation should have at least two variables or letters.
As for the third option, it does not even contain a variable or letter.
Answers
Answer:
A rigid transformation that flips preimage without changing size or shape just the angle over a specific line.
Step-by-step explanation:
"In mathematics, a reflection is a mapping from a Euclidean space to itself that is an isometry with a hyperplane as a set of fixed points; this set is called the axis or plane of reflection. The image of a figure by a reflection is its mirror image in the axis or plane of reflection."
"In geometry, a reflection is a type of rigid transformation in which the preimage is flipped across a line of reflection to create the image. Each point of the image is the same distance from the line as the preimage is, just on the opposite side of the line."