MATHEMATICS HIGH SCHOOL

We have:\overline{abc}

a,b,c are natural prime numbers and

a\cdot b \cdot c=30


What are the numbers? Without using GUESS-WORK!

Answers

Answer 1
Answer: 30=2\cdot15=2\cdot3\cdot5

If you have no other data such as a < b < c, or other (even-odd number), then you have 6 answers:

235\n253\n325\n253\n523\n532
Answer 2
Answer: Factorize 30.

30|2
15|3
5|5
1

30=2\cdot3\cdot5\n\Downarrow\na=2\nb=3\nc=5

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The x is positive, and the y is negative.

If you draw your number line showing the positive and negative sides of the x and y axis:

You will find it is in the 4th quadrant.

How do you simplify pxqx4

Answers

The value of the expression p x q x 4 will be 4pq.

What is Multiplication?

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The expression is,

p x q x 4

Now, After multiply the number and variables we get;

p x q x 4 = 4pq

Thus, The value of the expression p x q x 4 will be 4pq.

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(pxqx)⁴ = (pqxx)⁴ = (pqx²)⁴ = p²q²x²°⁴ = p²q²x⁸

2[s+3(s-31)]=18
how would i solve this

Answers

1. 2[s+3(s-31)]=18
2. [s+3(s-31)] = 9
3. s+ 3s - 93 = 9
4. 4s = 9+93
5. 4s = 102
6. s= 25.5

The function g(x) = 3x2 − 12x + 7 written in vertex form is g(x) = 3(x − 2)2 − 5. What is the vertex of g(x)?(−6, −5)

(−2, −5)

(2, −5)

(6, −5)

Answers

Hello,

Answer C (2,-5)

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What is the sum of the quotients of 25x^2/5x and the quotient of 8x^2/x

Answers

If you would like to solve (25 * x^2) / (5 * x) + (8 * x^2) / x, you can calculate this using the following steps:

(25 * x^2) / (5 * x) + (8 * x^2) / x = 5 * x + 8 * x = 13 * x

The correct result would be 13 * x.

What is the common ratio of the geometric sequence whose second and fourth terms are 6 and 54, respectively?

Answers

Hi there! T4=T2×r²,6r²=54. Therefore, the answer would be 3.
a₂ = 6      a₄ = 54

a_(n) = q^(n-1) * a_(1) 

\left \{ {{ a_(2) = q^(2-1) * a_(1) } \atop { a_(4) = q^(4-1)* a_(1) }} \right. \n \n \left \{ {{6 = q * a_(1) } \atop {54 = q^(3) * a_(1) }} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {54 = q^(3) * (6)/(q) }} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {54 = q^(2) * 6 }} \right. 

\left \{ {{ a_(1) = (6)/(q) } \atop { q^(2) =9}} \right. \n \n \left \{ {{ a_(1) = (6)/(q) } \atop {q= √(9) }} \right. 
q = 3     q = -3

a₁ = 6/3 = 2   a₁ = 6/-3 = -2
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