Find the highest common factor (HCF) of 12x^12 and 16x^16
Answers
Answer:
Step-by-step explanation:
To find the highest common factor (HCF) of 12x^12 and 16x^16, we need to factor both expressions.
12x^12 = 2^2 * 3 * (x^2)^6
16x^16 = 2^4 * (x^2)^8
The common factors of 12x^12 and 16x^16 are 2^2 and (x^2)^6. To find the HCF, we take the product of these common factors:
HCF = 2^2 * (x^2)^6 = 4x^12
Therefore, the highest common factor (HCF) of 12x^12 and 16x^16 is 4x^12.
Final answer:
To find the HCF of 12x^12 and 16x^16, break down the terms into prime factors and take the lowest exponent for each common prime factor.
Explanation:
To find the highest common factor (HCF) of 12x^12 and 16x^16, we need to determine the largest number or expression that divides both 12x^12 and 16x^16 without leaving a remainder.
First, let's break down the terms into their prime factors:
12x^12 = 2^2 * 3 * (x)^12
16x^16 = 2^4 * (x)^16
Next, compare the prime factors and take the lowest exponent for each prime factor. In this case, the common factors are 2^2 and (x)^12. Multiplying these together gives us the HCF: 4x^12.
Learn more about HCF here:
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A fruit company delivers its fruit in two types of boxes : large and small. A delivery of 6 large boxes and 5 small boxes has a total weight of 190 kilograms. A delivery of 2 large boxes and 3 small boxes has a total of 84 kilograms. How much does each type of boxes weigh ?
Answers
2x-2y=-2
x+3y=7
x+3y-3y=7-3y
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3(7-3y)+y=5
21-9y+y=5
21-8y=5
21-21-8y=5-21
8y=-16
8y/8=-16/8
y=-2
x=7/3
Answers
Step-by-step explanation:
d = do + vo t + 1/2 at^2
when the car starts at zero velocity, this becomes
d = 1/2 a t^2
1000 = 1/2 (20) t^2
t^2 = 1000/ ( 1/2 * 20) shows t = 10 s
Answers
18 hotdogs - 12 hotdog buns = 6 hotdug buns still needed
6 is the amount of hotdog buns needed.
You subtract 12 from 18 because you already have that amount of buns and need to see how many you need to get.
y = −x + 8
Which of the following statements is a correct step to find x and y?
Multiply the equations to eliminate y.
Add the equations to eliminate x.
Write the points where the graphs of the equations intersect the x-axis.
Write the points where the graphs of the equations intersect the y-axis.
Answers
Answer:
the answer is B. add all the equations to eliminate x. its true. i did the test and i defiantly got it right. (brainliest would b appreciated)
Step-by-step explanation:
Answers
Answers
Answer:
Option C.
Step-by-step explanation:
First, let's define the transformations used here:
We can see that the red graph is shifted horizontally to the right, and that is reflected across the x-axis:
Horizontal shift:
For a general function f(x) an horizontal shift of N units is written as:
g(x) = f(x + N)
where:
If N > 0, the shift is to the left
if N < 0 , the shift is to the right.
Reflection across the x-axis.
For a function f(x), a reflection across the x-axis is just written as:
g(x) = -f(x)
So, if here we have a reflection across the x-axis and a horizontal shift of one unit to the right, we would write the equation for the red graph as:
g(x) = -f(x) (only for the reflection)
g(x) = -f(x - 1) (for the reflection and the shift)
Then the graph of the red function is:
y = -f(x - 1)
We can rewrite this as:
y = -1*f(x - 1)
dividing both sides by -1 we get:
y/-1 = f(x - 1)
This is what we can see in option C, so the correct option is C.