I have no idea what I am doing. Here is one of my problems, A gas station sells 1500 gallons of gasoline per hour if it charges $ 2.10 per gallon but only 1300 gallons per hour if it charges $ 2.95 per gallon. Assuming a linear model

(a) How many gallons would be sold per hour of the price is $ 2.70 per gallon?
(b) What must the gasoline price be in order to sell 800 gallons per hour?
(c) Compute the revenue taken at the four prices mentioned in this problem -- $ 2.10, $ 2.70, $ 2.95 and your answer to part (b). Which price gives the most revenue?

Answers

Answer 1

Answer: You need to set up a linear graph. One side with gallons and the other with dollars. Point 1 will be at (1500, 2.10). Point 2 (1300, 2.95). Draw a straight line through these points in your graph and your graph will then give you the answers to your other questions.

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Help please I don’t get this

Find the value of x. Round to the nearest tenth.

Answers

36
i think. hope it helped sorrh if it’s wrong i’m not good at math

A home security system is designed to have a 99% reliability rate. Suppose that nine homes equipped with this system experience an attempted burglary. Find the probabilities of these events:_________.A. At least one alarm is triggered.
B. More than seven alarms are triggered.
C. Eight or fewer alarms are triggered.

Answers

Answer:

a) $P(X \geq 1) = 1-P(X<1) = 1-P(X=0)$

$P(X=0)=(9C0)(0.99)^0 (1-0.99)^(9-0)=1x10^(-18)$

And replacing we got:

$P(X \geq 1) =1 -1x10^(-18) \approx 1$

b) $P(X=7)=(9C7)(0.99)^7 (1-0.99)^(9-7)=0.003355$

$P(X=8)=(9C8)(0.99)^8 (1-0.99)^(9-8)=0.083047$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^(9-9)=0.913517$

And adding we got:

$P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992$

c) $P(X \leq 8) =1 -P(X>8) = 1-P(X=9)$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^(9-9)=0.913517$

And replacing we got:

$P(X \leq 8)= 1-0.913517=0.086483$

Step-by-step explanation:

Let X the random variable of interest "numebr of times that an alarm is triggered", on this case we now that:

$X \sim Binom(n=9, p=0.99)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^(n-x)$

Where (nCx) means combinatory and it's given by this formula:

$nCx=(n!)/((n-x)! x!)$

Part a

We want to find this probability:

$P(X \geq 1) = 1-P(X<1) = 1-P(X=0)$

$P(X=0)=(9C0)(0.99)^0 (1-0.99)^(9-0)=1x10^(-18)$

And replacing we got:

$P(X \geq 1) =1 -1x10^(-18) \approx 1$

Part b

$P(X \geq 7)= P(X=7) +P(X=8)+ P(X=9)$

$P(X=7)=(9C7)(0.99)^7 (1-0.99)^(9-7)=0.003355$

$P(X=8)=(9C8)(0.99)^8 (1-0.99)^(9-8)=0.083047$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^(9-9)=0.913517$

And adding we got:

$P(X \geq 7) = 0.003355+0.083047+0.913517 =0.99992$

Part c

$P(X \leq 8) =1 -P(X>8) = 1-P(X=9)$

$P(X=9)=(9C9)(0.99)^9 (1-0.99)^(9-9)=0.913517$

And replacing we got:

$P(X \leq 8)= 1-0.913517=0.086483$

A line with a slope of -1/2 passes thru the point (-4,3)...Which equation represents this line?

Answers

Here you go!! Hope this helps!!!!

Answer: Go to a website called m a t h w a y

Step-by-step explanation:

1. It's really good for all kinds of math problems

2. It lets you answers to one question in different ways to give you the best possible answer!!!

3. IT'S FREE!!!!!!!

A researcher wishes to conduct a study of the color preferences of new car buyers. Suppose that 50% of this population prefers the color green. If 14 buyers are randomly selected, what is the probability that exactly 12 buyers would prefer green

Answers

Answer:

The probability that exactly 12 buyers would prefer green

=0.00555

Step-by-step explanation:

We are given that

p=50%=50/100=0.50

n=14

We have to find the probability that exactly 12 buyers would prefer green.

q=1-p

q=1-0.50=0.50

Using binomial distribution formula

$P(X=x)=nC_r p^r q^(n-r)$

$P(x=12)=14C_(12)(0.50)^(12)(0.50)^(14-12)$

$P(x=12)=14C_(12)(0.50)^(12)(0.50)^2$

$P(x=12)=14C_(12)(0.50)^(14)$

$P(x=12)=(14!)/(12!2!)(0.50)^(14)$

$P(x=12)=(14* 13* 12!)/(12!2* 1)(0.50)^(14)$

$P(x=12)=91\cdot (0.50)^(14)$

$P(x=12)=0.00555$

Hence, the probability that exactly 12 buyers would prefer green

=0.00555

To construct a confidence interval using the given confidence level, do whichever of the following is appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical value t Subscript alpha divided by 2, or (c) state that neither the normal nor the t distribution applies. 95%; nequals200; sigma equals 19.0; population appears to be skewe

Answers

Answer:

The correct option is (a).

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n > 30) from the population with replacement, then the distribution of the sample- means will be approximately normally-distributed.

Then, the mean of the sample means is given by,

$\mu_(\bar x)=\mu$

And the standard deviation of the sample means is given by,

$\sigma_(\bar x)=(\sigma)/(√(n))$

The information provided is:

n = 200

σ = 19.0

Population is skewed.

As the sample selected is quite large, i.e. n = 200 > 30 the central limit theorem can be used to approximate the distribution of the sample mean by the normal distribution.

So, $\bar X\sim N(\mu, (\sigma^(2))/(n))$ .

Then to construct a confidence interval for mean we will use a z-interval.

And for 95% confidence level we will compute the critical value of z, i.e. $z_(\alpha/2)$ .

Thus, the correct option is (a).

A customer has $10 to spend at the concession stand. Hotdogs cost $2 each and drinks cost $2.50 each. Graph the inequality that illustrates this situation. Use the space below to explain what the answer means.