Will give 100 points to anyone who can find the arc measure and show work! thanks!​
Will give 100 points to anyone who can find the - 1

Answers

Answer 1
Answer:

Answer:

  • 2π/3 radians

----------------------

Given:

  • Arc length (s) = 8π/3
  • Radius (r) = 4 km

To find the arc measure (θ) in radians, we can use the formula:

  • s = rθ

Now, plug in the given values:

  • 8π/3 = 4θ

To solve for θ, divide both sides by 4:

  • (8π/3) / 4 = θ

Simplify the expression:

  • 2π/3 = θ

So, the arc measure (θ) is 2π/3 radians


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If the garden is to be 1250 square feet, and the fence along the driveway costs $6 per foot while on the other three sides it costs only $2 per foot, find the dimensions that will minimize the cost.

Answers

So, the minimum cost is $400.

Area of the rectangle:

The area of a rectangle is the region occupied by a rectangle within its four sides or boundaries.

And the formula is,

A=l* b

Given that,

Area of the garden=1250 square feet.

Let, the length be x and the breadth be y then,

xy=1250...(1)

The total cost of the fence is,

C(x,y)=6x+2x+4y\nC(x,y)=8x+4y\nC(x)=8x+4((1250)/(x) )\n

Now, differentiating the obtained equation we get,

C'(x)=8-(4* 1250)/(x^2) =0\nx^2=625\nx=25\ny=50

Therefore the length is 25 ft

And breadth is 50ft

Now, calculating the minimum cost,

8(25)+4(50)=50\n=400

Learn more about the area of the rectangle:

brainly.com/question/1037253

Answer:

Dimensions of rectangular garden:

x = 25 feet   ( sides along the driveway)

y = 50 feet

Step-by-step explanation:

Rectangular area is:

A(r)  = x*y           (1)

if we call x one the driveway side the cost of that side will be

6*x

The cost of the other side parallel to driveway side is 2*x and cost of the others two sides are 4*y

Total costs:  C = 6*x + 2*x  * 4*y     (2)

From equation (1)

A(r)  = 1250 = x*y      ⇒⇒   y = 1250/ x

Plugging that value in equation (2) we get costs as a function of x

that is:

C(x) = 6*x + 2*x +  4* 1250/x

Taking derivatives on both sides of the equation

C´(x)  = 6 + 2 - 5000/x²

C´(x)  = 8 - 5000 /x²

C´(x) = 0       ⇒       8 - 5000 /x² = 0

8*x² -5000 = 0

x² = 5000/8

x² = 625

x = 25 feet

and    y = 1250/ 25

y = 50 ft

C(min) = 50*2*2 + 6*25 + 2*25

C(min) = 200 + 200

C(min) = 400 $

Question 3 (1 point) If the following is a rhombus, find the missing measures. Find PQ. PQ=​

Answers

Answer:

Step-by-step explanation:

PQ*PQ=PQ²=(5x+16)²=25x²+160x+256

John has $12. Tony has twice as much as John. Eric has $4 less than Tony. How much money does Eric have?​

Answers

Answer:

$20

Step-by-step explanation:

John=$12

Tony=$24

Eric=$20

multiply 12 by 2 to get Tony's money then subtract 4 for eric's money

Answer:

20

Step-by-step

Tony : 24

Eric : 24 - 4

Answer : 20

A recipe calls for a total of 3 cups flour and sugar. If the recipe calls for a cup of sugar, how much flour is needed?o 3 te cups
3 cups
4 cups
3 cups
5
12 cup
3
13 cups

Answers

Answer:

3 cups

Step-by-step explanation:

The same amount of each is needed if I read that correctly.

Find x
1) 3.38
2)13.99
3)12.59
4)16.09

Answers

Answer:

12.59

Step-by-step explanation:

took the got dam tst

What is the greatest common factor of 8x and 40y?

8
8xy
320
320xy

Answers

The greatest common factor of 8x and 40y is 8.

What are Factors?

Factors of a number or an algebraic expression are the numbers or expressions which divides the given number evenly.

For example, 10 = 2 × 5

So we can say that 2 and 5 are factors of 10.

Greatest common factor of two or more numbers is the factor which is the greatest among all the common factors of both the numbers.

8x can be prime factorized as,

8x = 2 × 2 × 2 × x

Similarly, 40y can be prime factorized as,

40y = 2 × 2 × 2 × 5 × y

Greatest common factor of both the numbers is the product of the common prime factors of both.

Greatest common factor = 2 × 2 × 2 = 8, which is common to both.

Hence 8 is the greatest common factor of 8x and 40y.

Learn more about Greatest Common Factors here :

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#SPJ6

Answer:

8

Hope this helps!