A label is placed around a soup can during manufacturing. If the label is represented by the rectangle in the figure, how many square inches is the label? Answer in terms of π.image of a net drawing of a cylinder is shown as two circles each with a radius labeled 4 inches and a rectangle with a height labeled 7.8 inches

94.4π square inches
32π square inches
30.1π square inches
62.4π square inches

Answers

Answer 1
Answer:

The label on the soup can has area of 62.4π square inches. The Option D is correct.

What is the area of the label on the soup can?

The label is represented by the rectangle in the figure.

The height of rectangle is given as 7.8 inches. The length is equal to the circumference of the circular base of the cylinder.

The circumference of a circle is: 2πr

In this case, the radius of each circle is 4 inches. So, the circumference of each circle is:

= 2π(4)

= 8π

As length of rectangle represents circumference, its length is equal to 8π inches. The height of rectangle is given as 7.8 inches.

We will calculate the area of the rectangle:

Area = Length × Height

Area = (8π) × 7.8

Area = 62.4π.

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Related Questions

Write an equation in slope-intercept form of the line through point P(6, –1) with slope 4.A. y = 4x – 25 B. y = 4x – 1 C. y + 1 = 4(x – 6) D. y + 6 = 4(x – 1)
Find the VALUE or EVALUATE 62 + 5b when b = 3. (HINT: 62 means 6 X 6)
when measuring length 9 butcher knives are approximately equal to 16 steak knives. How many steak knives are equal to 63 butcher knives? how many butcher knives are equal to 48 steak knives
For a field trip 4 students rode in cars and the rest filled nine buses. How many students were in each bus if 472 students were on the trip?
Hannah reads 3 pages every 8 minutes. Write an equation that shows the relationship between the number of pages she reads (p) and the number of minutes she spends reading (m).

Ray Cupple bought a basic car costing $10,150.00, with options costing $738.00. There is a 6% sales tax in his state and a combined $50.00 license and registration fee. What was Ray's total cost?Here are the options but I don't understand them of course. ;n;
A. $11,591.28
B. $10,938.00
C. $11,541.28
D. $11,547.00

 
*I really need it explained and the answer, I can't do math to save my life and it is killing me. I've done all kinds of programs and such, just can't seem to keep any math in my brain.

Answers

            The Cost of a Basic Car: $10,150.00
Options on the Cost of a Basic Car: $738.00
           License and Registration Fee: $50.00
                                      Subtotal: $10,938.00
                                              Sales Tax: 0.06
                                           Total: $11,594.28

I notice that I have to add the cost of the car, the option of the car, the license and registration fee, and the sales tax in order to find out the total of what it might cost for all of them. So I calculated it in a receipt form to find of the subtotal and the total of Ray' s cost, which is above the screen.

One yardstick for measuring how steadily—if slowly—athletic performance has improved is the mile run. In 1958​, the local record for the running of a certain distance was 3​ minutes, 59.3 ​seconds, or 239.3 seconds. In the​ half-century since​ then, the record has decreased by 0.5 seconds per year.

Answers

Answer:

They will hit 180 seconds in 118.6 year

Step-by-step explanation:

Let M be the record for the mile (in seconds)

Let x be the year after 1958

So, x=(year)-19548

We are given that In the​ half-century since​ then, the record has decreased by 0.5 seconds per year

So, slope = m = 0.5

Now we will use point slope form

y = mx+c

So, we can express M as,

M=239.3-0.5 * x

Now we are supposed to find when they will hit 180 seconds

Substitute M = 180 in equation

180=239.3-0.5x

x=118.6

So, they will hit 180 seconds in 118.6 year

Final answer:

You can model the decreasing record time with the linear equation y=239.3-0.5x, where x is years since 1958 and y is the run time in seconds. By using this model, you can find the record time for any given year.

Explanation:

The subject of this question is Mathematics, specifically linear equations. The question mentions an initial record of 239.3 seconds for a run which decreases by 0.5 seconds every year. We are tasked to find the running time after a certain number of years.

Let's let x represent the number of years since 1958 and y represent the number of seconds to run the race. Based on the information provided:

  • The starting time (y-intercept) in 1958 was 239.3 seconds.
  • The rate of decrease (slope) is 0.5 seconds per year.

Therefore, the relationship between x and y can be expressed by the linear equation: y=239.3-0.5x

To find a certain year's running time, we substitute the number of years passed since 1958 into x in the equation above and solve for y. For example, to find the running time in 50 years after 1958 (2008), we replace x with 50: y = 239.3 - 0.5(50) = 214.3 seconds.

Learn more about Linear Equations here:

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Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Answers

L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\n\n(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\n\n(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\n\n(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\n\n(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\n\dots-3c^4a^2+3c^2a^4-a^6\n\n=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\n\n=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)

R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\n\n=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\n\n=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\n\n=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\n\n=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\n\nL=R

(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a + b)(b +c)(c + a)(a - b)(b - c)(c - a)
(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a + b)(a - b)(b + c)(b - c)(c + a)(c - a)
(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a^2 - b^2)(b^2 - c^2)(c^2 - a^2)

(a^2 - b^2)^3 = (a^2 - b2)(a^2 - b^2)(a^2-b^2) = a^6 - 3a^4b^2 + 3a^2b^4 - b^6
(b^2 - c^2)^3 = (b^2 - c^2)(b^2 - c^2)(b^2 - c^2) = b^6 - 3^4c^2 + 3b^2c^4 - c^6)
(c^2 - a^2)^3 = (c^2 - a^2)(c^2 - a^2)(c^2 - a^2) = c^6 - 3a^2c^4 + 3a^4c^2 - a^6

a^6 - 3a^4b^2 + 3a^2b^4 - b^6 + b^6 - 3b^4c^2 + 3b^2c^4 - c^6 + c^6 - 3a^2c^4 + 3a^4c^2 - a^6
-3a^4b^2 + 3a^2b^4 - 3b^4c^2 + 3b^2c^4 - 3a^2c^4 + 3a^4c^2
3(-a^4b^2 + a^2b^4 - b^4c^2 + b2^c^4 - a^2c^4 + a^4c^2)

3(a^2 - b^2)(b^2 - c^2)(c^2 - a^2) = 3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2)

3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2) = 3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2

If line segment is 100 feet, and line segment is 80 feet, what is the length of line segment ?

Answers

which, in theory, would be the third side of the triangle formed by these three lines, would be 60 feet.


At a dental office, the probability a patient needs a cleaning is 0.89. The probability a patientneeds a filling is 0.44. Assuming the events "needs a cleaning" and "needs a filling" are
independent, then what is the probability a patient needs a filling given that he/she needs a cleaning?
A. 0.83
B. Additional information is required to determine the probability.
C.0.39
D. 0.89
E. 0.44

Answers

Answer:  0.44

Reason:

The events "needs a cleaning" and "needs a filling" are independent. Therefore, we can immediately conclude that the prior condition "needs a cleaning" does not affect "needs a filling". That's why we go for the answer of 0.44 which is stated in the instructions.

In terms of symbols:

  • C = patient needs a cleaning
  • F = patient needs a filling
  • P(C) = 0.89 = probability the patient needs a cleaning
  • P(F) = 0.44
  • P(F given C) = P(F) .... since F and C are independent
  • P(F given C) = 0.44

The knowledge about event C happening does not change the value of P(F). Now if events F and C were dependent somehow, then P(F given C) would be different from P(F).

What is 56 written as a decimal?

Answers

Answer:

56 as a decimal is 56.0 :)

Step-by-step explanation:

A whole number is a number whose fraction part is zero. To convert a whole number into a decimal, you must decide the result to a certain number of places after the decimal point and simply add a decimal and the number of zeros required to the right side of the whole number.