Please help 1/7x-3 5/7 > 4/7x-5 6/7

Answers

Answer 1
Answer: \frac { 1 }{ 7 } x-\left( 3+\frac { 5 }{ 7 }  \right) >\frac { 4 }{ 7 } x-\left( 5+\frac { 6 }{ 7 }  \right)

\n \n -\left( 3+\frac { 5 }{ 7 }  \right) +\left( 5+\frac { 6 }{ 7 }  \right) >\frac { 4 }{ 7 } x-\frac { 1 }{ 7 } x

\n \n -3-\frac { 5 }{ 7 } +5+\frac { 6 }{ 7 } >\frac { 3 }{ 7 } x\n \n 2+\frac { 1 }{ 7 } >\frac { 3 }{ 7 } x

\n \n \frac { 14 }{ 7 } +\frac { 1 }{ 7 } >\frac { 3 }{ 7 } x\n \n \frac { 15 }{ 7 } >\frac { 3 }{ 7 } x

\n \n \frac { 7 }{ 3 } \cdot \frac { 15 }{ 7 } >\frac { 3 }{ 7 } x\cdot \frac { 7 }{ 3 } \n \n \frac { 15 }{ 3 } >x\n \n \therefore \quad x<5

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8x(3x2-8)+10 what does his mean?

Answers

8*(3*2-8)+10= \n\n =8*(6-8)+10= \n\n = 8*(-2)+10= \n\n =-16+10= \n\n =\boxed{-6}
8*(3*2-8)+10 \n =8*(6-8)+10 \n =8*(-2)+10 \n =-16+10 \n =-6

Ruth's car traveled 120 miles during the first race. During the second race, it traveled 124 miles. If the car averaged 123 miles over the first three races, how far did it travel during the third race?

Answers

EQUATION:
(120+124+x)/3 = 123
244+x = 369
x = 125 miles

HEY GUYS PLEASE HELP ME I WILL MARK WHOEVER EXPLAINS IT WELL AS BRAINLIEST .!! -3X+3Y=24X+2Y=13
REMEMBER I AM SOLVING FOR BOTH X AND Y ASAP I DO NOT HAVE TIME

Answers

-3x + 3y = 24
x + 2y = 13

(x + 2y) - 2y = 13 - 2y
x = 13 - 2y

-3(13 - 2y) + 3y = 24
-39 + 6y + 3y = 24
9y - 39 = 24
(9y - 39) + 39 = 24 + 39
9y = 63
9y ÷ 9 = 63 ÷ 9
y = 7

x + 2y = 13
x + 2(7) = 13
x + 14 = 13
(x + 14) - 14 = 13 - 14
x = -1

When x = -1
y = 7


An easy way to check: 
-3x + 3y = 24
-3(-1) + 3(7) = 24
3 + 21 = 24
24 = 24

Since it is the same on both sides, our answers are correct. 

In a normal distribution, a data value located 0.8 standard deviations below the mean has Standard Score: z = In a normal distribution, a data value located 2.4 standard deviations above the mean has Standard Score: z =

In a normal distribution, the mean has Standard Score: z =

Answers

Using the normal distribution, it is found that the z-scores are:

1) z = -0.8

2) z = 2.4

3) z = 0

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = (X - \mu)/(\sigma)

  • It measures how many standard deviations the measure is from the mean, either above the mean(positive z-score), or below(negative z-score).

Item 1:

0.8 standard deviations below the mean, hence z = -0.8.

Item 2:

2.4 standard deviations above the mean, hence z = 2.4.

Item 3:

The mean is 0 standard deviations from itself, hence z = 0.

A similar problem is given at brainly.com/question/24663213

Final answer:

A standard score (z-score) signifies how many standard deviations a data point is away from the mean. A data value 0.8 standard deviations below the mean has a z-score of -0.8, meanwhile, if it is 2.4 standard deviations above the mean, its z-score is 2.4. The mean in a normal distribution has a z-score of 0.

Explanation:

In the field of statistics, a standard score (also known as a z-score) represents how many standard deviations an element is from the mean. In a normal distribution, a data value located 0.8 standard deviations below the mean has a Standard Score: z = -0.8. This is because the z-score is negative when the data value is below the mean. Conversely, a data value located 2.4 standard deviations above the mean has a Standard Score: z = 2.4. As the data value is above the mean, the z-score is positive. Finally, for the mean value itself in a normal distribution, the Standard Score: z = 0 because the mean value is the center of distribution, hence no deviation from itself.

Learn more about Standard Score here:

brainly.com/question/24210074

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Choose the correct simplification of the expression (4a^4b)^2.

Answers

(4a^4b)^2

= 4^2a^8b^2

= 16a^8b^2


Hope it helps.

\sf Hello!

\sf (4a^(4)b)^(2)

\sf 4^(2).a^(4 × 2).b^(2)

\sf 16.a^(8).b^(2)

\sf 16a^(8)b^(2)

\sf Hence,
\sf Simplified\: expression \:is\: obtained

~ \sf iCarl

Work out the balance for £1500 invested for 2 years at 3.7% per annum

Answers

Given:
Principal = 1,500
term = 2 years
interest rate = 3.7% per annum

Simple Interest = Principal * interest rate * term
S.I = 1,500 * 0.037 * 2
S.I = 111

Total value = 1,500 + 111 = 1,611

Compound interest
A = P (1+r/n)^nt
where n is the number of times interest is compounded. Assuming interest is only compounded once.

A = 1,500(1+0.037/1)^1*2
A = 1,500(1.037)²
A = 1,500(1.075369)
A = 1,613.0535