The _______ is the time required for one complete wave oscillation to occur.

Answers

Answer 1

Answer: period is the answer

Answer 2

Answer: The period is the time required.....

Related Questions

In the picture below, two light beams are traveling through water. If the frequency of one light beam is greater than the other, what can be said about their wavelengths?Select one:a. The light beam with the higher frequency has the longer wavelength.b. The light beam with the higher frequency has the shorter wavelength.c. Wavelength does not depend on frequency therefore the wavelengths could be equal. d. Not enough information is given to tell.
A baseball on a T-ball stand has no momentum until it is hit with a bat. When Tyler swings the bat, it has a momentum of 12 kg m/s. After the bat hits the ball, the ball has a momentum of 8 kg m/s. What is the momentum of the bat AFTER it hits the ball
Harnessing the sun's energy to produce heat or electricity is _____.. A. non-polluting . B.inexpensive . C. possible only in coastal areas. D. a mojor source of air pollution.
A softball player leaves the batters box, overruns first base by 3.0 meters, and then returns to first base. Compared to the total distance traveled by the player, how much smaller or larger is the magnitude of the players total displacement from the batters box?
Suppose you wanted to do an experiment to find out if changing the length of a pendulum changed the amount of time it takes the pendulum to swing back and forth. Which pendulums from the above diagram would you use for the experiment?a.1 and 4 b.2 and 4 c.1 and 3 d.2 and 5 e.all

What is the power of a refrigerator with voltage 110 V and
current 0.8 A?

Answers

Answer: 88

Explanation:

A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.600 m. What impulse was given to the ball by the floor?

Answers

Here are the given values:

mass (m) = 0.120kginitial velocity (Vo) = 0distance traveled (s) = 1.25 m

We first calculate for the final velocity of the ball:

Vf^2 = 2gs + Vo^2
Vf^2 = 2(9.8m/s2)(1.25m)
Vf = 4.95 m/s

Impulse = m(Vf−Vo)
Impulse = 0.120(4.95)
Impulse = 0.59 Ns

Before we find impulse, we need to find the initial and final momentum of the ball.

To find the momentum of the ball before it hit the floor, we need to figure out its final velocity using kinematics.

Values we know:
acceleration(a) - 9.81m/s^2 [down]
initial velocity(vi) - 0m/s
distance(d) - 1.25m [down]

This equation can be used to find final velocity:

Vf^2 = Vi^2 + 2ad

Vf^2 = (0)^2 + (2)(-9.81)(-1.25)

Vf^2 = 24.525

Vf = 4.95m/s [down]

Now we need to find the velocity the ball leaves the floor at using the same kinematics concept.

What we know:
a = 9.81m/s^2 [down]
d = 0.600m [up]
vf = 0m/s

Vf^2 = Vi^2 + 2ad

0^2 = Vi^2 + 2(-9.81)(0.6)

0 = Vi^2 + -11.772

Vi^2 = 11.772

Vi = 3.43m/s [up]

Now to find impulse given to the ball by the floor we find the change in momentum.

Impulse = Momentum final - momentum initial

Impulse = (0.120)(3.43) - (0.120)(-4.95)

Impulse = 1.01kgm/s [up]

The conductive tissues of the upper leg can be modeled as a 40- cm-long, 12-cm-diameter cylinder of muscle and fat. The resistivities of muscle and fat are 13 Ω m and 25 Ω m, respectively. One person’s upper leg is 82% muscle, 18% fat. What current is measured if a 1.5 V potential difference is applied between the person’s hip and knee?

Answers

Answer:

current = 0.0027 A

Explanation:

the resistivity of upper leg

$\rho = 0.82 (13) + 0.18(25) = 15.16 ohm . m$

Resistance of upper leg

$R = (\rho L)/(A)$

$= (\rho L)/(\pi R^2)$

$= (15.16 * 0.40)/(\pi [(0.12)/(2)]^2)$

= 551.27 ohm

current $i = (V)/(R)$

$current = (1.5)/(551.27)$

current = 0.0027 A

A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. \rm mg. How many pills does the patient need to take each time she wants the 625 mg dosage? Assume that these pills are scored and can be cut in half if necessary.

Answers

For the patient to take 625mg of Ibuprofen, the person would need to take 2.5 pills each time. Two pills will equal 500mg and taking one half pill would be another 125mg which is equal to 625 mg. Doing this twice a day would equal the 1250mg required in a full day.

The speed of sound is 330.0 m/s and the wave length of a particular sound wave is 33.0 meters. Calculate the frequency of the sound wave. A)11,000 Hz B)10.0 Hz C) 0.10 Hz D)9.1 x 10-5 Hz

Answers

Answer:

B). f = 10.0 Hz

Explanation:

As we know the relation between frequency, wavelength and speed is given as

$v = f \lambda$

here we know that

$v = 330 m/s$

$\lambda = 33 m$

now in order to find the frequency of the sound we can use above relation as

$f = (v)/(\lambda)$

plug in all values in it

$f = (330)/(33)$

$f = 10 Hz$

v: velocity of wave
f: frequency
L: wavelenght

v = fL => f = v/L => f = (330)/(33) => L = 10Hz

A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration.

Answers

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 44 mi/h\n\ns = 0.00833 mi\n\n=> 0^2 = 44^2 + 2 * a * 0.00833\n\n=> 1936 = -0.01666a\n\na = -116206.48 mi/h^2 or -14.43 m/s^2$

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 79 mi/h\n\na = -116206.48 mi/h\n\n=> 0^2 = 79^2 + (2 * -116206.48 * s)\n\n6241 = 232412.96s\n\ns = (6241)/(232412.96) \n\ns = 0.0268531 mi = 141.78 ft$

The minimum stopping distance is 141.78 ft.

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