if beavers built a dam on a stream,the kinds of plants and animals that lived around the stream would not be affected? true or false

Answers

Answer 1

Answer:

If beavers built a dam on a stream, the kinds of plants and animals that lived around the stream would not be affected; this is a false statement as the dam becomes the barrier in the stream.

What is the importance of the dam?

The dam is an artificial structure that prevents the flow of water in the river and holds the water for various purposes, such as electricity generation and water distribution to the urban population, among others, so when the dam is formed in the stream, the free path of the fish and other species is restricted as they can't swim freely, and this restricts the biodiversity in the stream.

Hence, if beavers built a dam on a stream, the kinds of plants and animals that lived around the stream would not be affected; this is a false statement as the dam becomes the barrier in the stream.

Learn more about the importance of the dam here.

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Answer 2

Answer: False the fish in the stream wouldn't be able to swim up or down the stream

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Gloria’s science teacher has given her a sample of an unknown metal along with this table. Gloria finds that her sample has a mass of 53.5 grams and a volume of 2.5 cubic centimeters. The sample can be identified as copper. iron. lead. platinum.

Answers

The answer is: [D]: platinum .
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Explanation: Given the information provided, we need to find the "density" of the unknown metal; in: "mass per UNIT volume". Then we need to look up the "density" values of EACH of the 4 answer choices (or at least until we get the corresponding density). To be thorough, we still should look up the density of EACH of the metals listed in the answer choices given. We look up these "densities" online, or in a specialty reference guide in university library, for instance.
__________________________________
First, let us calculate the density of the unknown volume:
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Density, "D", = m / V ; in which: D = density; m = mass; V = volume;
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We are given: mass, "m" = 53.5 g ; and:
Volume, "V" = 2.5 cubic centimeters = 2.5 cm³
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D = 53.5 g / 2.5 cm³ = (53.5 / 2.5) g / cm³ = 21.4 cm³ ;
→ Round to "2 significant figures";
= 21 g/cm³
_______________________________________________________
We are given 4 (four) answer choices). Let us list EACH of the 4 (four) answer choices and their densities (researched).
____________________
Choice "A" : copper; (Cu) ; density = 8.96 g / cm³ ;
______________________________________
Choice "B" : iron ; (Fe) ; density = 7.874 g / cm³ ;
______________________________________
Choice "C": lead; (Pb) ; density = 11.34 g / cm³ ;
______________________________________
Choice "D": platinum; density = 21.45 g / cm³ ;
________________________________________
Clearly, Answer choice: [D]: "platinum" is the correct answer; with a density of "21.45 g / cm³ " ;
____________________________________________________
Since this value is the closest to our calculated value of
" 21 g/ cm³ "; or even "21.4 g/ cm³ " [our value before rounding down to 2 (two) significant figures].

The densities of the metals in all the other answer choices given are far from this value.
________________________________________________
I hope this explanation has been of some help.

Answer:

Yeah, its platnium.

Explanation:

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