TRUE OR FALSE If f(x) = 2x and g(x) = 1/2x, then f(x)*g(x) is x.

Answers

Answer 1
Answer: well i don't think so because f(x) is 2x but g(x) is 1/2x
HOPE I HELPED(and got it right)!
:)

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What is the area of a circle, rounded to the nearest tenth, with a
diameter of 12 centimeters?

Answers

Answer:

113

Step-by-step explanation:

area of a circle is 3.14*r^2

r=d/2 r=6

3.14*36=113

Why might algebra tiles not be a good tool to use to factor x2 + 18x + 80? Explain.

Answers

For the polynomial x² + 18x + 80, to represent using algebra tiles would be difficult because the number of tiles needed would be very plenty.

Polynomial

Polynomial is an expression that involves only the operations of addition, subtraction, multiplication of variables.

Algebra tiles is the use of tiles to represent variables and constants.

Given the polynomial x² + 18x + 80, to represent using algebra tiles would be difficult because the number of tiles needed would be very plenty.

Find out more on Polynomial at: brainly.com/question/2833285

Answer:

Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.

WARNING!!!!!!!

This is an sample response, so if u can put it in your own words.

Evaluate ∫ e3x cosh 2x dx A. 1/2e5x + 1/2ex + C B. 1/10e5x + 1/5 x + C C. 1/10e5x + 1/2ex + C D. 1/4e3x + 1/2 x + C

Answers

∫ e^(3x)*(cosh(2x)dx

= ∫ [e^(3x)*(e^(2x)+e^(-2x))/2]dx

= ∫ [(e^(5x)+e^x)/2]dx

=e^(5x)/10+e^x/2+C

=(1/10)(e^(5x)+5e^x)+C

What are the solutions of x^2 - 5x+7 = 0 ?​

Answers

Answer:

C.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=(-b\pm√(b^2-4ac) )/(2a)

Algebra II

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

Step 1: Define

x² - 5x + 7 = 0

Step 2: Identify Variables

a = 1

b = -5

c = 7

Step 3: Find solutions

  1. Substitute [Quad Formula]:                    x=(5\pm√((-5)^2-4(1)(7)) )/(2(1))
  2. Evaluate Exponents:                               x=(5\pm√(25-4(1)(7)) )/(2(1))
  3. Evaluate Multiplication:                          x=(5\pm√(25-28) )/(2)
  4. Evaluate Subtraction:                             x=(5\pm√(-3) )/(2)
  5. Factor:                                                     x=(5\pm√(-1) √(3) )/(2)
  6. Simplify:                                                  x=(5\pm i√(3) )/(2)

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Option C is the correct answer.

We have,

To find the solutions of the quadraticequation x² - 5x + 7 = 0, we can use the quadraticformula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, the coefficients are:

a = 1

b = -5

c = 7

Substituting these values into the quadraticformula,

x = (-(-5) ± √((-5)² - 4(1)(7))) / (2(1))

Simplifying further:

x = (5 ± √(25 - 28)) / 2

x = (5 ± √(-3)) / 2

Since the discriminant (the value inside the square root) is negative, √(-3) is imaginary, meaning there are norealsolutions to this quadratic equation.

The solutions exist in the complex number system.

So,

√-1 = i

x = (5 ± i√3) / 2

This can be written as,

x = (5 + i√3) / 2

and

x = (5 - i√3) / 2

Thus,

The solutions to the equation x² - 5x + 7 = 0  are:

x = (5 + i√3) / 2 or x = (5 - i√3) / 2

Learn more about solutionsofequations here:

brainly.com/question/545403

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A two digit number is 4 times the sum of its digits and twice the product of its digit.FIND THE NUMBER

Answers

x - tenths digit
y - units digit

10x+y=4(x+y)\n 10x+y=2xy\n\n 10x+y=4x+4y\n 10x+y=2xy\n\n 6x=3y\n 10x+y=2xy\n\n 3x=y\n 10x+y=2xy\n\n 10x+3x=2x\cdot3x\n 13x=6x^2\n 6x^2-12x=0\n 6x(x-2)=0\n x=0 \vee x=2\n\n y=3\cdot2\n y=6\n\n 10\cdot2+6=\boxed{26}

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x)?4(x – 7)2 – x – 7 + 3

4(x – 7)2 – (x – 7) + 3

(4x2 – x + 3) – 7

(4x2 – x + 3)(x – 7)

Answers

The correct answer is 4(x-7)²-(x-7)+3.

Explanation:
When we find (t*s)(x), that is the same as t(s(x)). To evaluate this, we take the value of s(x), x-7, and substitute it in for every x in t(x). Instead of 4x
², we have 4(x-7)²; instead of -x, we have -(x-7). This gives us 4(x-7)²-(x-7)+3.

Answer:

(4x^2-x+3)(x-7)<strong>

D is the correct option.

Step-by-step explanation:

We have been given that

s(x)=x-7\text{ and }t(x)=4x^2-x+3

We have to find (t\cdot x)

which means we have to find the product of these two expressions.

We can rewrite (t\cdot x) as t(x)s(x)

Therefore, we have

(t\cdot x)\n\n=t(x)s(x)=(4x^2-x+3)(x-7)

Hence, the equivalent expression is

(4x^2-x+3)(x-7)

D is the correct option.