A helicopter rose vertically 300m and then flew west 400m. how far was the helicopter from it starting point?

Answers

Answer 1

Answer:

$a^(2) + b^(2) = c^(2) 300 ^(2) + 400 ^(2) = c^(2) c^(2) =250,000 √(250,000)=500m$

Answer 2

Answer: The helicopter rose vertically, and then flew horizontally, so it's final displacement (distance from where it is now to where it started) is in the shape of a triangle.

The displacement is the hypotenuse of this triangle, with sides 300m and 400m.

We can work out this distance using Pythagorus' theorem, because we know that;

$a^(2) = b^(2) + c^(2)$

Where $a$ is the hypotenuse, and $b$ and $c$ are the two other sides. So;

$a^(2) = b^(2) + c^(2) \n \n a^(2) = 300^(2) + 400^(2) \n \n a^(2) = 90000 + 160000 \n \n a = √(250000) \n \n a = \boxed{500m}$

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In exercises 3-6, write the expression in terms of sine or cosineSin 22°

Cos 56°

Cos 15°

Sin 37°

Answers

sin 22 = 0.3746
cos 56=0.5592
cos 15= 0.9659
sin 37=0.6018
just punch it in you calculator (ex. sin(22) and it should be in degree mode if you're using graphing calculator)

7/12 - 3/8=? Please help if you can also if you could give me a few tips tricks and pointers on adding and subtracted fractions that would be amazing thanks again!

Answers

So basically when you are adding or subtracting fractions the denominators the number on the bottom of the fraction 12 in this case and 8 as well the two denominators sharing the least common multiple so what is the lowest multiple of 12 and 8 so count off 12: 12, 24, 36... 8: 8, 16 , 24 does that help?

I get the whole trouble with fractions thing let me see if I can help!

so, 7/12 - 3/8 first you will always want to make the denominators even or the bottom #'s so to do that you have to find the GCD or greatest common denominator. Which would be 24. then you would have to do to the top what you did to the bottom by multiplying the top #'s by 2 for the first fraction (7/12) and then 3 for the denominator. now you just subtract the top numbers as if there wasn't even a fraction there. The bottom # doesn't change ever until you can simplify at the very end when you actually have an answer. so the answer would be 5/24 and that is as simplified as you can get it.

Glen collects a total of 450 stamps from the United States,Great Britain,and India. In his collection, 52% of the stamps are US stamps. He has 3/5 as many Indian stamps as British stamps. How many Indian stamps does Glen have? What percent of Glen' collection are British stamps?

Answers

50% of 450 = 225
2% of 450 = 4.5 x 2 = 9
so 52% of 450 is 234 (US Stamps)

~

450 - 234 = 216
216 / 8 = 27

27 x 5 = 135 (British Stamps)
[135 / 450 = 3 / 10 = 30%]

27 x 3 = 81 (Indian Stamps)
[81/135 = 3/5]

~

Indian Stamps 81
British Stamps (% of collection) 30%

Last week Trent made 80 on his quiz. This week he made a 90. What is the percent of increase in his score? A.10%
B.12.5%
C.11%
D.15%

Answers

90=80x
x=9/8=1.125
.125*100=12.5%

(A)10%
because 10+80 equals 90

Eduardo is building a sandbox that has an area of 84 square feet. What are the possible whole number measurements for the length and width of the sandbox?

Answers

To find the area, of a rectangle, you multiply length by width. Therefore, any factor pairs of 84 would be possible measurements for the length and width of the sandbox.
length=1ft, width=84ft (1x84=84)
length=2ft; width=42ft (2x42=84)
length=3ft; width=28ft (3x28=84)
length=4ft; width=21ft (4x21=84)
length=6ft; width=14ft (6x14=84)
length=7ft; width=12ft (7x12=84)
And switching the numbers around gives you more possibilities.
length=12ft; width=7ft
length=14ft; width=6ft
length=21ft; width=4ft
length=28ft; width=3ft
length=42ft; width=2ft
length=84ft; width=1ft
12 total possible whole number pairs for the length and width of the sandbox.
See how that works? Easy as pie, so long as you have the patience to find all the factors.
I hope this helps!

Estimate each product 5/7×1/9=

Answers

Multiply it out to get 5/7*1/9=5/63. This is an exact value of the product.

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