MATHEMATICS HIGH SCHOOL

Evaluate the function f(x)=7x+3 at the given values of the independent variable and simplifya. f(5) b. f(x+8) c. f(-x)

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Answers

Answer 1
Answer: f(x)=7x+3\n\nf(5)\ substitute\ 5\to x\n\nf(5)=7\cdot5+3=35+3=38\n\n\nf(x+8)\ substitute\ x+8\to x\n\nf(x+8)=7(x+8)+3=7x+56+3=7x+59\n\n\nf(-x)\ substitute\ -x\to x\n\nf(-x)=7\cdot(-x)+3=-7x+3

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A physical fitness association is including the mile run in its secondary- school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Answers

Answer:

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 440 seconds

Standard Deviation, σ = 50 seconds

We are given that the distribution of time is a bell shaped distribution that is a normal distribution.

Formula:

z_(score) = \displaystyle(x-\mu)/(\sigma)

P(run the mile in less than 325 seconds)

P(x < 325)

P( x < 325) = P( z < \displaystyle(325 - 440)/(50)) = P(z < -2.3)

Calculation the value from standard normal z table, we have,  

P(x < 325) = 0.0107 = 1.07\%

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

What is x^2 + 3x - 10 =0

Answers

x^2 + 3x - 10 = 0 \n \n (x - 2)(x + 5) = 0 \n \n x = 2, -5 \n \n

The final result is: x = 2, -5.
(x - 5)(x + 2) = 0 

Set both factors equal to 0 
x - 5 = 0 
x + 2 = 0 

Solve for x and the answer is 
x = 5 
x = -2

Solve for w k=2b-5w/3k

Answers

Answer:

b = (2b - 3k^(2) )/(5)

Step-by-step explanation:

To solve for w in this equation;

k = (2b - 5w)/(3k)

This implies we have to make w the subject of the formula.

To make w subject of the formula, first we cross multiply.

3k  × k  =  2b  -  5w

3k²  =   2b   -5w

Now we will subtract  2b from both- side of the equation

3k²   - 2b  = -5w

we want to make the right hand side of the equation positive, to do that , we will just multiply through by minus sign.  The equation becomes;

-3k²   +   2b   = 5w

We can rearrange the equation;

2b -  3k²   =    5w

5w  =  2b  - 3k²

Then we will now divide both-side of the equation by 5

(5w)/(5) = (2b - 3k^(2) )/(5)

In the left side of the equation, the 5 at the  numerator will cancel out the 5 at the denominator.

Hence;

w  =   (2b - 3k^(2) )/(5)
k = (2b - 5w)/(3k)
3k^(2) = 2b - 5w
3k^(2) + 5w = 2b
5w = 2b - 3k^(2)
w = (2)/(5)b - (3)/(5)k^(2)

What comes next 

1,2,6,14,....

Answers

next it comes as
1,2,6,14,30,62
everytime the difference between the numbers doubles.
i think it is correct!
All it is is multiplying by n, and n = x+1, if you don't get it it means that you multiply by consecutive numbers. For ex. the first one is 1x2 then 2x2 then 4x3 then 4x4 and so on

Giselle graphs the function f(x) = x^2. Robin graphs the function g(x) = –x^2. How does Robin’s graph relate to Giselle’s?Robin’s graph is a reflection of Giselle’s graph over the x-axis.
Robin’s graph is a reflection of Giselle’s graph over the y-axis.
Robin’s graph is a translation of Giselle’s graph 1 unit down.
Robin’s graph is a translation of Giselle’s graph 1 unit left.

Answers

The first one is the answer.

Sketch the graph of the two by substituting x as 1, 2, 3 and you will see that the two graphs look exactly the same but seem to be reflected through the mirror line of the x-axis

Answer:

First Option

Step-by-step explanation:

If Ying Zyiyu covers the first 200 miles of a trip going at 50 mph and the last hundred going 40 mph, what was his average speed for the entire trip?

Answers

the person covers different distances at different speeds

to find the average speed we have to find the total distance travelled and the total time taken

average speed = total distance travelled / total time taken


first 200 miles

speed - 50 mph

time taken for 50 miles - 1 hour

then time for 200 miles - 1/50 x 200 = 4 hours


last 100 miles

speed - 40 mph

time taken for 40 miles - 1 hour

time for 100 miles - 1/40 x 100 = 2.5 hours


total time taken for a distance of 300 miles - 2.5 + 4 = 6.5 hours


average speed = 300 miles / 6.5 hours = 46.2 mph

average speed is 46.2 mph
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