Evaluate, 2 x {[5 x (60-14 divided by 7)] + 25} x 5=?

Answers

Answer 1

Answer: $2 * \left \{ [5 * (60-(14 )/(7) )] + 25 \right \} * 5=2 * \left \{ [5 * (60-2)] + 25 \right \} * 5= 2 * \left \{ (5 * 58) + 25 \right \} * 5=\n\n= 2 * \left \{ 290 + 25 \right \} * 5=2*315*5=3150$

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Elsa knows that for every bushel of apples she sells she earns $9 and for every basket of pears she earns $11. She uses the expression 9a + 11p to keep track of her earnings. Part A: Identify the coefficients and variables in the expression. (3 points)Part B: How many terms are in the expression, what are they, and how do you know? (4 points)Part C: Which term in the expression shows the total earned from selling baskets of pears? (3 points)I only need help with b and c ?
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Answers

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Jack reads his book for 8 minutes before school and 10 minutes after school. He attends school Monday through Friday. Which equation shows how many minutes Jack reads his book in two weeks? A. (8 × 5) + (10 × 5) = 40 + 50 = 90 minutes B. (8 × 8) + (10 × 10) = 64 + 100 = 164 minutes C. (8 × 10) + (10 × 10) = 80 + 100 = 180 minutes D. (8 × 14) + (10 × 14) = 112 + 140 = 252 minutes

Answers

Answer:

(8 × 10) + (10 × 10) = 80 + 100 = 180 minutes

Step-by-step explanation:

It is given that, Jack reads his book for 8 minutes before school and 10 minutes after school.

No of days between Monday to Friday = 5

No of days between Monday to Friday in 2 weeks = 10

We need to find how many minutes Jack reads his book in two weeks.

For 10 days, before school = (8 × 10) min = 80 minutes

For 10 days, after school = (10 × 10) min = 100 minutes

It means, total time will be :

T = (8 × 10) min + (10 × 10) min

T = 80 + 100

T = 180 minutes

Hence, the correct option is (C).

An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. This similar to the current problem as you have to consider the 25 mph tailwind and headwind. Plane on outbound trip of 4 hours with 25 mph tailwind and return trip of 5 hours with 25 mph headwind Let r = the rate or speed of the airplane in still air. Let d = the distance a. Write a system of equations for the airplane. One equation will be for the outbound trip with tailwind of 25 mph. The second equation will be for the return trip with headwind of 25 mph.
b. Solve the system of equations for the speed of the airplane in still air.

Answers

Answer:

r = 225 Mil/h speed of the airplane in still air

Step-by-step explanation:

Then:

d is traveled distance and r the speed of the airplane in still air

so the first equation is for a 4 hours trip

as d = v*t

d = 4 * ( r + 25) (1) the speed of tail wind (25 mil/h)

Second equation the trip back in 5 hours

d = 5 * ( r - 25 ) (2)

So we got a system of two equation and two unknown variables d and

We solve it by subtitution

from equation (1) d = 4r + 100

plugging in equation 2

4r + 100 = 5r - 125 ⇒ -r = -225 ⇒ r = 225 Mil/h

And distance is :

d = 4*r + 100 ⇒ d = 4 * ( 225) + 100

d = 900 + 100

d = 1000 miles

A sailboat’s sail has three sides that are all the same length. Each side measures x−10 units. The sail’s perimeter is 63 units.What is the value of x?

Answers

63/3=21
1 sail =21
21+10=31
x=31

Find the selling price cost to store:50$ markup 10%

Answers

If you would like to find the selling price, you can calculate this using the following steps:

10% of $50 = 10% * 50 = 10/100 * 50 = $5

$50 + $5 = $55

The correct result would be $55.

Answer:

$55

Step-by-step explanation:

$55

The sum of the page numbers of two facing pages in a book is 145. What are the page numbers?

Answers

The answer is 72 and 73. When you add 72+73 it equals 145.

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