A stone is thrown with an initial velocity of 20 meters per second straight upward from the edge of a cliff 100 meters above a canyon floor. The stone just misses the cliff'a edge on its way down. (Neglect friction) Calculate the time required for the stone to reach its maximum height.
Calculate the maximum height of the stone above the edge of the cliff.
Answers
The time taken by the stone to reach the maximum height above the cliff is and the maximum height reached by the stone above the cliff is
.
Explanation:
Given:
The initial velocity of the stone is .
The height of the cliff is .
Concept:
As the stone is thrown upward from the top of the cliff, the stone will move under the action of the acceleration due to gravity. The speed of the stone will decrease as it moves up because the acceleration on the stone is acting in the direction opposite to its motion.
The speed of the stone at its maximum height will be zero where is comes to rest for a moment.
The time taken by the stone to reach the maximum height is given by:
Here, is the final velocity,
is the initial velocity,
is the acceleration and
is the time taken by the stone.
Substitute the values in above expression.
The distance covered by the stone in reaching the maximum height is given by:
Here, is the distance covered by the stone.
Substitute the values in above expression.
Thus, The time taken by the stone to reach the maximum height above the cliff is and the maximum height reached by the stone above the cliff is
.
Learn More:
1. Compare the three types of friction brainly.com/question/1800116
2. The scale reading if the cable breaks suddenly brainly.com/question/4852539
3. The height of bridge above water brainly.com/question/10664397
Answer Details:
Grade: Senior School
Subject: Physics
Chapter: Kinematics
Keywords:
stone, initial velocity, final, thrown, cliff, canyon floor, maximum height, zero, acceleration, gravity, time taken, distance.
I thought you were going to ask how long it takes for the stone to hit
the canyon floor at the bottom of the cliff. But you're not asking for
anything after the stone barely misses the edge of the cliff on its way
down, and you're only asking about things that happen above the
edge of the cliff. So we don't need to know anything about the cliff,
or its height above anything else. The thrower might just as well be
standing in his front yard when he throws the stone straight up.
-- Gravity robs 9.8 m/s from the stone's upward speed every second.
So the stone reaches its maximum height, runs out of upward gas, and
starts falling, in (20 / 9.8) = 2.04 seconds after the toss.
-- Its average speed during that time is (1/2) (20 + 0) = 10 m/s .
In 2.04 seconds at that average speed, it rises (2.04 x 10) = 20.4 meters .
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B. projectile path
C. trajectory
D. path of motion
Answers
The path followed by a projectile is called itstrajectory. (C)
In the most common school situation... with gravity but without air resistance, the trajectory of a projectile is the shape of an inverted parabola (nose pointing up). That's the result of constant horizontal velocity and accelerated vertical velocity.
Answer:
Trajectory
Explanation:
Trajectory is the path followed or traced by a projectile.
It follows a parabola shape. That is the shape got in javeline.
Answers
Answer:
Resistance
Explanation:
Answer:
The correct answer is (C) resistance.
Explanation: i used the answer above and i got it right!
Answers
The frequency of a wave is the reciprocal of its period.
A period of 0.008 sec means a frequency of
1 / 0.008 sec = 125 per sec . (125 Hz)
A wave with a period of 0.008 second has a frequency of
1 /.008 = 125 Hz
B. When the acceleration of the object is zero, its velocity is also zero.
C. The direction of object velocity is not necessarily the same as that of acceleration.
D. When the object is vertically thrown up to the highest point, the speed and acceleration are zero.
E. When the object is free-falling, the displacement and acceleration direction are the same.
Answers
Answer:
A
Explanation:
Answers
Answer:
1069.38 gallons
Explanation:
Let V₀ = 1.07 × 10³ be the initial volume of the gasoline at temperature θ₁ = 52 °F. Let V₁ be the volume at θ₂ = 97 °F.
V₁ = V₀(1 + βΔθ) β = coefficient of volume expansion for gasoline = 9.6 × 10⁻⁴ °C⁻¹
Δθ = (5/9)(97°F -52°F) °C = 25 °C.
Let V₂ be its final volume when it cools to 52°F in the tank is
V₂ = V₁(1 - βΔθ) = V₀(1 + βΔθ)(1 - βΔθ) = V₀(1 - [βΔθ]²)
= 1.07 × 10³(1 - [9.6 × 10⁻⁴ °C⁻¹ × 25 °C]²)
= 1.07 × 10³(1 - [0.024]²)
= 1.07 × 10³(1 - 0.000576)
= 1.07 × 10³(0.999424)
= 1069.38 gallons
Final answer:
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. Using the equation for volume expansion, we can calculate this change in volume to be approximately 258 gallons.
Explanation:
To calculate the amount of gasoline that can be poured into the tank, we need to find the change in volume of the gasoline when its temperature changes from 97.0°F to 52.0°F. We can use the equation for volume expansion to calculate this change in volume:
ΔV = V₀ * β * ΔT
Where ΔV is the change in volume, V₀ is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature.
In this case, the initial volume V₀ is 1.07 * 10³ gallons, the coefficient of volume expansion β is 9.6 * 10⁻⁴ (°C)⁻¹, and the change in temperature ΔT is (52.0°F - 97.0°F) = -45.0°F.
Converting the change in temperature to Celsius: ΔT = (45.0°F) * (5/9) = -25.0°C.
Plugging in these values into the equation, we get:
ΔV = 1.07 * 10³ * 9.6 * 10⁻⁴ * -25.0 = -258 gallons.
Therefore, when the gasoline is poured into the tank, approximately 258 gallons will be poured out of the truck.
Learn more about Calculating thermal expansion here:
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b. -0.037 cm
c. 0.370 cm
d. 0.370 cm
Answers
Answer:
Explanation:
y = (0.2 cm) Sin(2x - 3 t + π/16)
Put x = 4 m, t = 10 s
y = (0.2 cm) Sin (2 x 4 - 3 x 10 + π/16)
y = (0.2 cm) Sin (8 - 30 + π/16)
y = (0.2 cm) Sin (π/16 - 22)
y = (0.2 cm) Sin(-21.80375)
y = (0.2 cm) x (- 0.1863)
y = - 0.37 cm
Final answer:
The given wave function represents a transverse wave on a string. Substituting the given values into the wave function yields a height of -0.037 cm. The correct option is a. -0.037 cm.
Explanation:
The given wave function y(x,t) represents a transverse wave on a string. To find the height of the string with respect to the equilibrium position at a position x = 4.00m and a time t = 10.00s, substitute these values into the wave function. y(4.00m, 10.00s) = (0.20 cm) sin[(2.00 m-1)(4.00m) - (3.00 s-1)(10.00s) + π/16].
Calculating this expression gives the height of the string as -0.037 cm. Therefore, the correct option is a. -0.037 cm.
Learn more about Wave Function on a String here:
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