How many molecules are there in 5.0g of C2H5OH?
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Answer:
The specific heat capacity of the metal is approximately 0.3903 J/(g·°C)
Explanation:
The mass of the sample of the unknown metal, = 134.0 g
The temperature to which the metal is raised, = 91.0°C
The mass of water into which the mass of metal is placed, = 125 g
The temperature of the water into which the metal is placed, = 25.0°C
The final temperature of the water, = 31.0°C
The specific heat capacity of water, = 4.184 J/(g·°C)
The specific heat capacity of the metal =
Therefore, by the first laws of thermodynamics we have;
The heat transferred = Heat supplied by the metal = Heat gained by the water
The heat transferred, ΔQ, is given as follows;
ΔQ = ×
×(
-
) =
×
×(
-
)
125 × 4.184 × (31 - 25) = 134 × × (91 - 31)
∴ = (125 × 4.184 × (31 - 25))/(134 × (91 - 31)) ≈ 0.3903 J/(g·°C)
The specific heat capacity of the metal = ≈ 0.3903 J/(g·°C)
b. oxygen
c. dissolved salts
d. sand
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best answer is C. your welcome
(2) hard-sphere model, electron-shell model, wave-mechanical model
(3) electron-shell model, wave-mechanical model, hard-sphere model
(4) electron-shell model, hard-sphere model, wave-mechanical model
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Answer:2
Explanation:
HARD SPHERE MODEL
According to Dalton he viewed atoms as tiny, solid balls. His atomic theory had four statements which are:
1. Atoms are tiny, invisible particles.
2.Atoms of one element are all the same.
3.Atoms of different elements are different. 4.Compounds form by combining atoms.
ELECTRON SHELL MODEL
Bohr modified Rutherfords model of the atom by stating that electrons moves around the nucleus in orbit fixed sizes and energies.
WAVE MECHANICAL MODEL
Erwin states that electrons do not move in set path around the nucleus but in waves. He said it is impossible to know the exact point of an electron instead we have clouds of probability called the clouds.
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Answer:
Q = 1760 cal or 7356.8 J
Explanation:
The general expression to use to calculate heat is the following:
Q = m*Cp*ΔT (1)
Where:
Q = heat in cal or joules
m = mass of the compound.
Cp = specific heat of the compound
T: change in temperature (K) or T2 - T1
Now, the reported Cp for water is 1 cal/g °C and 4.18 J / g °C, we will use both to calculate the heat in calories and joules:
Using calories we have:
Q = 32 * 1 * (80 - 25)
Q = 1760 cal
This is the heat in calories.
Using joules we have:
Q = 32 * 4.18 * (80 - 25)
Q = 7356.8 J
This is the heat expressed in Joules.
(32.0g)(4.18J/g°C)(55°C)= 7360J
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