A dime is tossed and then a quarter is tossed. One possible outcome is dime: heads, quarter: tails. What are the three other outcomes?
Answers
d = heads q= tails
d = tails q= tails
d = tails q = heads
Happy to Help!
dime:tails quarter:tails
dime:heads quarter:heads
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Do 0.3 and 3.0 have same value?explain
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(2x-3y=4) x2
(7x+6y=-1) x1
4x – 6y = 8
7x + 6y = -l
Answers
Answers
base is a squeare, so base=side²
Volume(Tank)=side² * height
600 m³=side² * 6 m
side²=600 m³/ 6 m
side²=100 m²
side=√(100 m²)=10 m.
answer: the side of the base is 10 m.
Answers
x in terms of b:
-2(bx - 5) = 16
-2bx + 10 = 16
-2bx = 6
x = 6 / -2b
x = -3/b
--------------------------------
when b = 3 then
-2(3x - 5) = 16
-6x + 10 = 16
-6x = 6
x = -1
Answer
The value of x in terms of b is -3/b
The value of x when b is 3 is -1
Answers
aprox pi to 3.14 fo this problem
v=(1/3)(2x-5)(3.14)(x-5)^2
v=(1/3)(2x-5)(3.14)(x^2-10x+25)
v=(1/3)(3.14)(2x^3-25x^2+100x-125)
v=(1/3)(
v=
and since we don't know what x,height, or radius or diameter or surface area or anything about the cylinder, we can't solve
Answers
So the length is 25 and the entire perimeter is 106. Lets put these both of these numbers as information we know.
We know the length is 25.
We know the full perimeter is 106.
We also know a rectangle has 2 pairs of congruent sides.
Okay so, the length is 25.
Since there are two sides that are the same we would multiply 25 by 2 to get 50.
Now we know 2 sides out of the four sides on a rectangle.
106 is the final perimeter, if we subtract 50 from 106, we get 56. That is the measurement for both sides we're missing but we need to know the width for just one side.
So we divide 56 by 2 to get 28.
The width is 28.
Heres the show your work part:
25 x 2 = 50
Gets both lengths for rectangle.
106 - 50 = 56
Gets the product for the widths.
56 / 2 = 28
Gets the width of just one side.
Your final answer: 28