I recently took a test in my Algebra 1 class. This was on the test (that I most likely failed)and it said something about vertical motion. The problem is below. Try to solve it, please! Thanks!2=-t^2+4+5

Answers

Answer 1

Answer:
OK.    2 = -t² + 4t + 5

Subtract 2 from each side: 0 = -t² + 4t + 3

Multiply the right side by -1 : 0 = t² - 4t - 3

Unfortunately, this can't be factored. The only other way I know
to find the solutions to a quadratic equation is with the use of the
quadratic formula. When you do that, you get these solutions:

   t = 2 + √7 = about 4.65
and
   t = 2 - √7 = about -0.65 .

If this equation comes from a problem that involves real people throwing
real things into the air and making vertical motion, then you want only the
positive solution.

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Kevin has 3 bags of apples weighing a total of 22 1/2 pounds.Two of the bags weigh 6 3/8 pounds and 3 1/4 pounds.How much does the third bag weigh?

Answers

3 bags total 22 and 1/2
bag1+bag2+bag3=22 and 1/2
two of the bags weight 6 and 3/8 and 3 and 1/4 so just assign them random bags
bag1=6 and 3/8
bag2=3 and 1/4
subsitute

6 and 3/8+3 and 1/4+bag3=22 and 1/2
we have to add them by making the bottom number same

6 and 3/8+3 and 1/4
common one is 8
6 and 3/8+3 and 2/8
6+3/8+3+2/8
9+5/8

9 and 5/8+bbag3=22 and 1/2
subtract 9 and 5/8 from both sides
bag3=22 and 1/2-9 and 5/8
bag3=22+1/2-9-5/8
bag3=22+4/8-9-5/8
bag3=21+8/8+4/8-9-5/8
bag3=21+12/8-9-5/8
bag3=21-9+12/8-5/8
bag3=12+7/8
bag3=12 and 7/8

answe ris 12 and 7/8 pounds

First, you change 6 3/8 and 3 1/4 to a common denminator. 8

6 3/8= 6 3/8
3 1/4= 3 2/8 (x2)

Then add those.

6 3/8+ 3 2/8 = 9 5/8

Then subtract 22 1/2 and 9 5/8. (Common denominator)

22 1/2= 22 4/8 (x4)
9 5/8= 9 5/8

the 3rd bag is 12 7/8 lbs.

You can also add each bag (lbs) to see if it gets to 22 1/2
Hope this helps!

All of the following are equivalent except _____.a.33%

b.0.3

c.1/3

d.33.3

Answers

D is not right. So your answer is D

yeah your answer is 33.3 because its equalent so when you do pemdas you get that answer

15 POINTS PLS ANSWER! A bagel shop sells bagels by the half dozen. The table at the right shows the number of bagels a shop gives per "half dozen" ordered. Write an algebraic expression that gives the rule for finding the number of bagels in any number b of half dozens.

Answers

Answer:

The expression that gives the number of bagels is 6b.

Step-by-step explanation:

The given table is ;

6 36

7 42

8 48

b ----

Let 'b' represents the bagels in any number of half dozen.

Let the total number of bagels be represented by x.

Now, we can represent the situation as follows:

$x=6b$

The expression that gives the number of bagels is 6b.

We can check this also.

When b = 7, we get x = 42

when b = 8, we get x = 48

9×6=54

(6 is a half dozen)

The table shows that each part it multiplied by 6,

6×6=36

7×6=42

8×6=48

(b) represents nine, and six is a half a dozen, so,

(b)9×6 (half a dozen)

The equation 7^2=a^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is k times the mean distance from the sun as planet X, by what factor is the orbital period increased?

Answers

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

$(T_y ^ 2)/(T_x ^ 2)=(a_y ^ 3)/(a_x^ 3)\n\n(T_y ^ 2)/(T_x ^ 2)=((a_xk)^3)/(a_x ^ 3)\n\n(T_y^ 2)/(T_x^ 2)=\frac{k ^ {3}a_(x)^ 3}{a_(x)^ 3}\n\n(T_(y)^ 2)/(T_(x)^ 2)=k ^ 3\n\nT_(y)^ 2 = T_(x)^(2)k^(3)\n\nT_(y) =k^{(3)/(2)}T_x$

Finally the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Simplify the expression

14+2y+3-6y

Answers

14+2y+3-6y=
14+3+2y-6y=
17-4y

Answer:

Step-by-step explanation:

How do you simplify an expression?

Here are the basic steps to follow to simplify an algebraic expression:

remove parentheses by multiplying factors.

use exponent rules to remove parentheses in terms with exponents.

combine like terms by adding coefficients.

combine the constants.

The sum of Sally's age plus twice Tomas's age is 12. The difference of Sally's age and Thomas's age is 3. Write and solve a system of equation to find their ages. Interpret the solution.

Answers

s=sally
tomas=t

s+2t=12
s-t=3
add t to both sides
s=3+t
subtitute 3+t for s in first equation
3+t+2t=12
3+3t=12
subtract 3
3t=9
divide by 3
t=3
tomas=3

subsitute
s=t+3
s=3+3
s=6

sally=6
tomas=3

Sally is older because:Sally:6Thomas:3Twice Thomas's age is 6.6+6=12Equation:6+3x2 or (6+3)x2 hint:PEMDASSolved:12

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