What are the effects of baking powder solution on dilute hydrochloric acid solution

The correct Statement is B: U carries 2 e- and 2 H+, cytochrome C carries 1 e- and no H+. It claims that ubiquinone carries 2 electrons and 2 protons, whereas cytochrome C carries 1 electron and no protons, is not a difference between the two but a similarity.

The statement that is NOT a difference between cytochrome C and ubiquinone (U) is Option B: U carries 2 e- and 2 H+, cytochrome C carries 1 e- and no H+. This is because both molecules act as electron carriers, with ubiquinone carrying two electrons and two protons (H+), while cytochrome C can only carry one electron without carrying a proton.

Moreover, in Statement A and Statement C, ubiquinone and cytochrome c play different roles in the electron transport chain, therefore those statements describe actual differences between ubiquinone and cytochrome C.

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Answer:

27.3 L

Explanation:

Final answer:

To calculate the volume of the balloon at a certain height, we can use the combined gas law. The volume of the balloon at the new height is approximately 1.13 L.

Explanation:

To solve this problem, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature will be equal to the ratio of the final pressure, volume, and temperature.

Using the formula PV/T = constant, we can set up the equation (1.00 atm * 2.30 L) / (23.5 + 273.15 K) = (0.810 atm * V) / (12.0 + 273.15 K), where V is the volume of the balloon at the new height.

Simplifying the equation and solving for V, we find that the volume of the balloon at the new height is approximately 1.13 L.

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Answer:

From the degree of freedom analysis, the degree of freedom of the system and its components are equal to zero hence the system is well defined

Explanation:

To appraise the evaporation-crystallisation process, we go over the system to check if it is well defined from the available information as follows

45% by weight of inlet water is evaporated hence where inlet consists of 19.6% by weight of K₂SO₄ we have, Molar mass of K₂SO₄ = 174.259g/mol. Thus for every mole of K₂SO₄, we have 174.259×100/19.6 = 889.1g  of solution is fed per mole of K₂SO₄,

Also the stream of concentrate leaving the evaporator contains

889.1 – 174.259 = 714.7 grams of water, and if 45% by weight of water is evaporated we have

45% of 889.1 is evaporated leaving a solution of weight = 889.1 × 55/100 = 489grams of solution which contains

100×174.259÷489 or 35.6% by weight of K₂SO₄ concentrate leaving the evaporator and moving on to the evaporator

However, 175. kg of water is evaporated/s hence from the previous calculation, quantity of water per mole of K₂SO₄ evaporated = 0.45×889.1= 400.1g which in comparison with actual quantity gives mass flow into

0.4001/175 = 0.003 or 437.39 to 1 hence the mass flow rate is 889.1g×437.39 = 388884g/s or 388.9Kg/s

a. Degrees of freedom analysis for the overall system

We have the following 4 unknowns in the overall system viz

m1, m3, m4 and m5

where m1 = maximum mass flow rate into the system

m3 = mass rate of evaporated water

m4 = maximum mass of solid K₂SO₄ crystals produced from the crystallizers

m5 = recycle ratio

While we have

1) Information, maximum capacity of evaporation from where we can calculate the maximum rate of feed supply

2) information, including chemical formula, to determine the maximum production rate

3) Information to calculate the water evaporated from fraction of water which is evaporated to that which is supplied

4) information to calculate the recycle ratio

Hence degrees of freedom = 4 – 4 =0

b. Degree of freedom analysis for the recycle-fresh feed mixing point

For the recycle-fresh feed mixing point we have m1 and m5, two unknowns

Where m1 is maximum feed rate and m5 is the mass of filtrate and we are given the compound molecular formula and the maximum flow rate from where we can calculate both m1 and m5

Hence the degrees of freedom = 0

c. Degree of freedom analysis for the evaporator

For the evaporator we have three unknowns m1,m2 and m3 and the available information are

1. The maximum water processing capacity of the evaporators and

2.   The percentage quantity of water evaporated

Which is 2 hence we have 2 – 2 = 0 degrees of freedom

and

d. Degree of freedom analysis for the crystallizer the unknowns are m2, m4, m5

For the crystallizer the unknowns are m2, m4, m5The information available are

1. the ratio of crystals per kilogram of solution

2. The concentration of the recycled K₂SO₄ solution

3. Information of the maximum capacity of the evaporator so as to calculate the mass of concentrates leaving the evaporator and moving towards the crystallizer

Hence, we have 3 -3 = 0 degrees of freedom

From the degree of freedom analysis, the degree of freedom of the system and its components are zero hence the system is well defined

Answer:

B.

Explanation:

Hello,

The solubility of HgS is increased by adding due to common ion effect which consists on the effect that the higher solubility of has over the HgS as the sulfur-based ions modify the solubility product. In such a way, by adding the sulfate, the equilibrium will be shifted rightwards, therefore the solubility is increased.

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