4. HOW MANY MOLECULES ARE IN 1.5 MOL OF SULFUR TRIOXIDE?

Answers

Answer 1

Answer: Sulfur trioxide is SO3
Now to find number of particles we take number of moles x avogadros number.
1.5 x (6.02x10^23) = 9.03x10^23 molecules

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Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50 Ti (5.3%). What is the average atomic mass of titanium?

Answers

(46x8.0)+(47x7.8)+(48x73.4)+(49x5.5)+(50x5.3) = 4792.3

4792.3/100 = 47.923 this is the average atomic mass of Titanium

Final answer:

The average atomic mass of titanium, calculated by weighting each isotope's mass by its percent abundance, is approximately 47.923 atomic mass units (amu). This aligns closely with the atomic mass on the periodic table of 47.867 amu.

Explanation:

The average atomic mass of titanium can be calculated by weighting each isotope's mass by its percent abundance, which is essentially what an 'average' is. Here is how each isotope of titanium contributes to the average atomic mass:

46Ti: 46 amu * 0.08 = 3.68 amu
47Ti: 47 amu * 0.078 = 3.666 amu
48Ti: 48 amu * 0.734 = 35.232 amu
49Ti: 49 amu * 0.055 = 2.695 amu
50Ti: 50 amu * 0.053 = 2.65 amu

Adding it all up: 3.68 amu + 3.666 amu + 35.232 amu + 2.695 amu + 2.65 amu = 47.923 amu. Therefore, the calculated average atomic mass of titanium is approximately 47.923 amu, which aligns closely with the atomic mass on the periodic table of 47.867 amu.

Learn more about average atomic mass here:

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CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?

Answers

The stoichiometric ratio of CuCl2 to NaCl is 1 is to 2. The stoichiometric ratio of 31.0 g CuCl2 is 26.95 grams of NaCl by converting the amount of CuCl2 to mole and multiplying by 0.5 and molar mass of NaCl.This amount is equal to 78.65% yield.

tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 ∘C.Which of the following is most likely the identity of this unknown liquid?tert-Butyl alcohol is a solvent with a of 9.10 and a freezing point of 25.5 . When 0.807 of an unknown colorless liquid was dissolved in 11.6 of tert-butyl alcohol, the solution froze at 15.3 .Which of the following is most likely the identity of this unknown liquid?ethylene glycol (molar mass = 62.07 g/mol)1-octanol (molar mass = 130.22 g/mol)glycerol (molar mass = 92.09 g/mol)2-pentanone (molar mass = 86.13 g/mol)1-butanol (molar mass = 74.12 g/mol)

Answers

Answer: ethylene glycol (molar mass = 62.07 g/mol)

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

$\Delta T_f=k_f* m$

or,

$\Delta T_f=k_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

where,

$T_f$ = change in freezing point

$k_f$ = freezing point constant= $9.10^0C/m$

m = molality

Given mass of solute = 0.807 g

Molar mass of solute=? g/mol

weight of solvent in kg= 11.6 g=0.0116 kg

$\Delta T_f=T^(o)_f-T_f=25.5^0C-15.3^0C)=10.2^0C$

$10.2=9.10* \frac{0.807}{\text{molar mass of solute}* 0.0116kg}$

${\text{molar mass of solute}}=62.07 g/mol$

Thus the solute is ethylene glycol which has same molecular mass as calculated, i.e 62.07 g/mol.

At constant temperature and pressure, 2.05 g of oxygen gas O2 is added to a 1.0 L balloon containing 1.00 g of O2. What is the new volume of the balloon?

Answers

Answer:

1.50 L.

Explanation:

From the general gas law:

PV = nRT,

Where, P is the pressure if the gas,

V is the volume if the gas container,

n is the no. of gas moles,

R is the general gas constant,

T is the temperature of the gas.

At constant P and T:

n₁V₂ = n₂V₁.

V₁ = 1.0 L, V₂ = ??? L.

n₁ = mass/molar mass = (2.05 g)/(32.0 g/mol) = 0.064 mol.

n₂ is the no. of moles of the total gas (2.05 g + 1.0 g).

n₂ = n₁ + (1.00 g)/(32.0 g/mol) = 0.0953 mol.

∴ V₂ = n₂V₁/n₁ = (0.0953 mol)(1.0 L)/(0.064 mol) = 1.489 L ≅ 1.50 L.

What would happen if u washed the benzoic acid in the Büchner funnel with hot solvent ? answer ASAP

Answers

Benzoic acid is able to dissolve in hot solvents. That means that it would not be filtered out by the buchner funnel since the buchner funnel has holes in it that make it so that the solvent can get through but solids can't (the benzoic acid would be dissolved in the solvent and therefore would leave the funnel with the solvent through the holes).

Note that it is important that the solvent is hot. Benzoic acid will start to precipitate out (re crystallize) as soon as the temperature drops which will make it so that some of the benzoic acid would get caught in the buchner funnel.

I hope this helps. Let me know in the comments if anything was unclear.

Which element has the smallest atomic radius? calcium potassium scandium titanium

Answers

The element that has the smallest atomic radius is titanium

explanation

Calcium,potassium, scandium and titanium are in period 4 in the periodic table.

Generally the atomic radius decreases across the period (from the left to the right) . This is because across the period there is increase in nuclear charge which make electrons been strongly attracted to the nuclear.

Titanium is in atomic number 22 thus it has more nuclear charge that calcium,potassium and scandium therefore titanium has the smallest atomic radius.

Answer:

Which element has the smallest atomic radius?

❌calcium

❌potassium

❌scandium

✔titanium

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