23. Jackie returned to the store later that day and bought n more notebooks at the same price. This time she used a store coupon for $3.50 off her entire purchase. The total she spent was more than $18. Write an inequality to represent this situation.Inequality
What was the least number of notebooks that Jackie could have bought this time?
Answer
notebooks

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

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Help me solve ;;;;; FCC Solving equations
Jackie scored 82 and 88 on her first two quizzes. Write and solve a compound inequality to find possible values for a third quiz score that would give her an average between 80 and 85, inclusive.a. 80 <= 82 + 88 + n / 3 <= 85; 70 <= n <= 85b. 70 <= 82 + 88 + n / 3 <= 85; 80 <= n <= 85c. 80 <= 82 + 88 + n / 3 < 85; 70 < n < 85d. 82 <= 80 + 85 + n / 3 <= 88; 70 <= n <= 85

Ashley can ride her bicycle 15 miles in 2 hours. There are 60 minutes in 1 hour, and there are 1760 yards in 1 mile. How many yards does Ashley travel in each minute?

A. 440 yards

B. 14 2/3 yards.

C. 29 1/3 yards.

D. 220 yards

Answers

b. 14 2/3 yards.
I think

Answer:

Step-by-step explanation:

the answer is 220 when u do the math you'll find the answer and you will get 220

Find the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13.

Answers

The area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

What is area and perimeter of the isosceles trapezoid?

The area of the isosceles trapezoid is the space occupied by it. It can be find out using the following formula,

$A=(a+b)/(2)* h$

Permiter of the isosceles trapezoid is the total length of the boundary by which it is enclosed. It can given as,

$P=a+b+2c$

Here (a,b) are the base side (c) is the side of leg and (h) is the height.

The image of the given isosceles trapezoid is attached below. Let the value of leg is x units. Thus using right angle property the cos theta is,

$\cos60=(2)/(x)\nx=1$

And the height of this trapezoid is,

$\tan60(h)/(2)\nh=3.46$

Thus the area of the solid is,

$A=(9+13)/(2)* 3.46\nA=38.105\rm\; units^2$

The perimeter of the solid is,

$P=9+13+2*1\nP=24\rm\; units$

Thus, the area and perimeter of an isosceles trapezoid with a 60° base angles and bases 9 and 13 is 38.105 squared units and 24 units respectively.

Learn more about the area of the isosceles trapezoid here;

brainly.com/question/436117

The trapezoid has two right triangles each with one side of length (13-9)2 = 4/2 = 2.

The other side of each right triangle is such that tan 60° = Heigth / 2

Then height = 2*tan60°.

The area of the trapezoid is height * (base 1 + base 2)/2

Then area = 2*tan (60°) * (13+9)/2 = 38.11

Remove all grouping symbols and combine like terms.( 3x + x ^2) - { 4x^2 - 3x +[ 2x^2 - x - (5x^2 + 4x)]}
Thank you

Answers

$(3x+x^2)-\{4x^2-3x+[2x^2-x-(5x^2+4x)]\}\n\n=3x+x^2-\{4x^2-3x+[2x^2-x-5x^2-4x]\}\n\n=3x+x^2-\{4x^2-3x+[-3x^2-5x]\}\n\n=3x+x^2-\{4x^2-3x-3x^2-5x\}\n\n=3x+x^2-\{x^2-8x\}\n\n=3x+x^2-x^2+8x\n\n=11x$

$( 3x + x ^2) - (4x^2 - 3x +(2x^2 - x - (5x^2 + 4x)))=\n 3x+x^2-4x^2+3x-(2x^2-x-5x^2-4x)=\n -3x^2+6x-2x^2+x+5x^2+4x=\n 11x$

during a basketball game, your team scored three times as many 2-point field goals than it did 3-point field goals, and scored a total of 90 points. How many field goals did your team score?